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Sound Interference

Sound Interference. Positions of zero displacement resulting from destructive interference are referred to as: A. antinodes B. nodes C. supercrests D. supertroughs. Sound Interference. Positions of zero displacement resulting from destructive interference are referred to as:

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Sound Interference

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  1. Sound Interference Positions of zero displacement resulting from destructive interference are referred to as: A. antinodes B. nodes C. supercrests D. supertroughs

  2. Sound Interference Positions of zero displacement resulting from destructive interference are referred to as: A. antinodes B. nodes C. supercrests D. supertroughs

  3. Forced Vibration and Resonance 3U Physics

  4. Natural Frequencies Nearly all objects, when disturbed, will vibrate. Objects tend to vibrate at a particular frequency (or set of frequencies) that depends on the properties of the object.

  5. Natural Frequencies Nearly all objects, when disturbed, will vibrate. Objects tend to vibrate at a particular frequency (or set of frequencies) that depends on the properties of the object: the material (which affects the speed of the wave) the length (which affects the wavelength) This frequency is known as the natural or resonant frequency of the object.

  6. Resonance: Example For example, the sound wave produced by a vibrating tuning fork will cause an identical tuning fork to start vibrating.

  7. Resonance An object that is forced at its natural frequency will resonate (vibrate) at that frequency (with increasing ? if the forcing continues).

  8. Resonance An object that is forced at its natural frequency will resonate (vibrate) at that frequency (with increasing amplitude if the forcing continues).

  9. Resonance An object that is forced at its natural frequency will resonate (vibrate) at that frequency (with increasing amplitude if the forcing continues). Consider the forced vibration of a child on a swing – pushing at the natural frequency increases the amplitude.

  10. Resonance An object that is forced at its natural frequency will resonate (vibrate) at that frequency (with increasing amplitude if the forcing continues). Or the Tacoma-Narrows Bridge:

  11. Resonance An object that is forced at its natural frequency will resonate (vibrate) at that frequency (with increasing amplitude if the forcing continues). Or: http://www.youtube.com/watch?v=O9FrMkhQoA4 http://www.youtube.com/watch?v=nHSGd2X1nc8&feature=related http://www.youtube.com/watch?v=oXV45t6wlWU&feature=related

  12. Standing Waves The natural or resonant frequencies of an object are those that produce standing waves (when the wave interferes with its own reflection in the medium).

  13. Nodes and Antinodes The points of zero displacement are nodes. The points of maximum displacement are antinodes.

  14. Nodes and Antinodes The points of zero displacement are nodes. The points of maximum displacement are antinodes. Because it is difficult to draw a standing wave in motion, they are often illustrated showing both extremes at once:

  15. Wavelengths How many wavelengths are illustrated in the diagram below?

  16. Wavelengths How many wavelengths are illustrated in the diagram below? 2

  17. Standing Waves These natural frequencies are called harmonics. The 1st harmonic is called the fundamental frequency:

  18. String Harmonics The first three harmonics for a vibrating string (which is secured at each end and therefore has to have a node at each end) are: l = l = l =

  19. String Harmonics The first three harmonics for a vibrating string (which is secured at each end and therefore has to have a node at each end) are: l = 2L l = l =

  20. String Harmonics The first three harmonics for a vibrating string (which is secured at each end and therefore has to have a node at each end) are: l = 2L l = L l = 2L/3

  21. String Harmonics Recall that the first three harmonics for a vibrating string (which is secured at each end and therefore has to have a node at each end) are: l = 2L so f = v/2L l = L so f = v/L l = 2L/3 so f = 3v/2L

  22. Practice Question 1 A string resonates with a fundamental frequency of 512 Hz. The speed of sound in the string is 1750 m/s. What is the length of the string?

  23. Practice Question 1 A string resonates with a fundamental frequency of 512 Hz. The speed of sound in the string is 1750 m/s. What is the length of the string?

  24. Practice Question 1 A string resonates with a fundamental frequency of 512 Hz. The speed of sound in the string is 1750 m/s. What is the length of the string?

  25. Practice Question 2 A guitar string has a frequency of 256 Hz and a length of 49.1 cm. A guitarist reduces the string's length by 12.8 cm by pressing on the string. What is the new frequency?

  26. Practice Question 2 A guitar string has a frequency of 256 Hz and a length of 49.1 cm. A guitarist reduces the string's length by 12.8 cm by pressing on the string. What is the new frequency? For the 1st length,

  27. Practice Question 2 A guitar string has a frequency of 256 Hz and a length of 49.1 cm. A guitarist reduces the string's length by 12.8 cm by pressing on the string. What is the new frequency? For the 2nd length,

  28. Practice Question 2 Note that reducing the length increased the fundamental frequency.

  29. More Practice Homework: Resonance Isn’t it hypnotic?

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