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Orbit Orbit condition Example Whiteboards

Orbit Orbit condition Example Whiteboards. Orbit. m s v 2 r or m s 4  2 r T 2. m s. =. Gm s m c r 2. m c. Example 1 - What is the velocity of orbit 250 miles above the earth? r = 6.38x10 6 m + (250 mi)(1609 m/mi) = 6782250 m

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Orbit Orbit condition Example Whiteboards

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  1. Orbit • Orbit condition • Example • Whiteboards

  2. Orbit msv2 r or ms42r T2 ms = Gmsmc r2 mc Example 1 - What is the velocity of orbit 250 miles above the earth? r = 6.38x106 m + (250 mi)(1609 m/mi) = 6782250 m mc = 5.97 x 1024 kg, use mv2/r = Gmm/r2 Do algebra first!!!!!!!! How to enter on calculator TOC

  3. Orbit msv2 r or ms42r T2 ms = Gmsmc r2 mc Example 2 - What is the radius of a geosynchronous orbit? T = 23:56:04 = 23(3600) + 56(60) + 4 = 86164 s mc = 5.97 x 1024 kg, use m42r/T2 = Gmm/r2 Algebra TOC

  4. Whiteboards: Orbit 1 | 2 | 3 | 4 TOC

  5. msv2 r • = Gmsmc • r2 What is the velocity of orbit 7.2 x 106 m from the earth’s center for a 23.5 kg object? Me = 5.97 x 1024 kg 7436 m/s W 7400 m/s

  6. msv2 r • = Gmsmc • r2 At what distance from the moon’s center is the orbital velocity 52.5 m/s? Mm = 7.36 x 1022 kg • r = Gmc • v2 1781086621 m W 1.78 x 109 m

  7. ms42r T2 • = Gmsmc • r2 You are orbiting 2.3 km from the center of an asteroid in a 24,600 kg spacecraft with a period of 2500 seconds. What must be the mass of the asteroid? mc = 42r3 GT2 1.15223E+15 kg W 1.2 x 1015 kg

  8. ms42r T2 • = Gmsmc • r2  42r3 Gmc T = You are orbiting 8.5 x 106 m from the center of a planet with a mass of 4.5 x 1024 kg. Your spaceship has a mass of 45,120 kg. What is your period of motion? 8987.5 s W 9.0 x 103 s

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