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Design and Synthesis of Complex Column Networks

Design and Synthesis of Complex Column Networks. By: Dr. Gerardo Ruiz LPPD UIC 08/26/2009. Quaternary Separation Networks. Network 1. Network 2. Vtotal = 3.9247 kmol/h. Vtotal = = 3.4321 kmol/h. Network 3. Network 4. Vtotal = = 4.8288 kmol/h. Vtotal = = 4.5288 kmol/h.

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Design and Synthesis of Complex Column Networks

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  1. Design and Synthesis of Complex Column Networks By: Dr. Gerardo Ruiz LPPD UIC 08/26/2009

  2. Quaternary Separation Networks Network 1 Network 2 Vtotal = 3.9247 kmol/h Vtotal = = 3.4321 kmol/h Network 3 Network 4 Vtotal = = 4.8288 kmol/h Vtotal = = 4.5288 kmol/h

  3. Global Search Different xD3 Different r

  4. ------------------- GIVEN DATA -------------------- CASE - 1 Component : Pentane/Hexane/Heptane/Octane r= 2.255 D= 38.460591701410777; xD=[0.650000000000000; 0.340000000000000; 0.008157894710526; 0.001842105289474] B= 61.539408298589223 xB= [0.000010000000000; 0.193752250000000; 0.401145269753289; 0.405092480246711]; minBPD1 = 1.044842065311968e-006 minBPT1 = 72.538858073595463 TotalH1 = 10.365258759272738 Hfeed1 = 4.847528563013216 Find Feasible design of Network 1-1 1-1

  5. Aspen Validation Find Feasible design of Network 1-1 1-1

  6. Find Feasible design of Network 1-2 1-2 • ------------------- GIVEN DATA -------------------- • CASE – 1 • Component : Hexane/Heptane/Octane • Feed Flow Rate :61.539408298589223 • Feed Composition : [0.193754187541875; 0.401149281246101; 0.405096531212023] • Distillate Purity : [0.327941811382181; 0.672048188617819; 0.000010000000000] • Bottom Purity : [0.000001000000000; 0.009999000000000; 0.990000000000000] • --------------------- RESULT ---------------------- • minimum BPD : 4.214684851089404e-08 • Reflux : 5 • Distillate Flowrate : 36.358562592555927 • Bottom Flowrate : 25.180845706033292

  7. Find Feasible design of Network 1-2 1-2 Aspen Validation

  8. Find Feasible design of Network 1-3 1-3 • ------------------- GIVEN DATA -------------------- • CASE -1 • Component : Hexane/Heptane/Octane • xF(:,1)= [0.651199578187482; 0.340627471667299; 0.008172950145219] • xF(:,2)= [ 0; 0.327945090833089; 0.672054909166911 ] • xp(:,1)=[0.995000000000000; 0.004999990000000; 0.000000010000000] • xp(:,2)=[0.005000000000000; 0.990000000000000; 0.005000000000000] • xp(:,3)=[0.000000000100000; 0.009999999900000; 0.990000000000000] • F=[38.460591701410777; 36.358562592555927] • Reflux : 2.9 • Reboil Ratio : • Flow rate :[25.046255499393155; 24.899373683227921; 24.873525111345632]

  9. Find Feasible design of Network 1-3 1-3 • Aspen Validation

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