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Tema

LYG ČIŲ, KAI SANDAUGA LYGI NULIUI, SPRENDIMAS Sudarė: Laima Arbačiauskienė Jiezno gimnazija. Tema. Tikslai. Pasikartosime, kada sandauga lygi nuliui. Išmoksime spręsti lygtis.

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Tema

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  1. LYGČIŲ, KAI SANDAUGA LYGI NULIUI, SPRENDIMAS Sudarė: Laima Arbačiauskienė Jiezno gimnazija Tema

  2. Tikslai • Pasikartosime, kada sandauga lygi nuliui. • Išmoksime spręsti lygtis.

  3. Sandauga lygi nuliui,kai bent vienas iš dauginamųjų lygus nuliui. (x + a) (x – b) = 0

  4. Kadangi nežinome, kuris dauginamasis lygus nuliui, rašome: x+a =0 arba x–b=0 Sprendžiama x= -a x= b Ats:. –a; b.

  5. Pavyzdžiai: • x(x+1)=0 x=0 arba x+1=0 x= -1 Ats.: 0; -1 2. (x-5) (x+4)=0 x-5=0 arba x+4=0 x=5 x= -4 Ats.: 5; -4

  6. 3. 3x(2x-1)(3x+6)=0 3x=0 arba 2x-1=0 arba 3x+6=0 x=0 2x=1 3x= -6 x=1:2 x= -6:3 x=0,5 x= -2 Ats:. 0; 0,5; -2.

  7. 3(x - 4) = 0 x(x + 5) = 0 (x - 1) (x - 6) = 0 (8 - 2x) (7x + 14) = 0 x(1 - 4x) (3x + 9) = 0 Išspręskite:

  8. Pasitikrinkite Atsakymai: • 4. • 0; -5. • 1; 6. • 4; -2. • 0; 0,25; -3.

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