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OBJECTIVE:

OBJECTIVE:. - graph system of inequalities. STEPS. 1. graph each inequality (DOTTED OR SOLID LINE ; SHADE THE CORRECT AREAS! ! !) 2. the area where the two shaded regions overlap is the solution. Shade that area in darker. 3. if the two shaded areas do not overlap, NO SOLUTION.

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OBJECTIVE:

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  1. OBJECTIVE: - graph system of inequalities

  2. STEPS 1. graph each inequality (DOTTED OR SOLID LINE ; SHADE THE CORRECT AREAS! ! !) 2. the area where the two shaded regions overlap is the solution. Shade that area in darker. 3. if the two shaded areas do not overlap, NO SOLUTION.

  3. y > x + 2 y-int = 2 ; slope = 1 1 dotted line ; shade up y < -x + 1 y-int = 1 ; slope = -1 1 solid line ; shade down 1. y > x + 2 y < -x + 1

  4. y > x + 2 y-int = 2 ; slope = 1 1 dotted line ; shade up y < -x + 1 y-int = 1 ; slope = -1 1 solid line ; shade down where do they overlap? 1. y > x + 2 y < -x + 1

  5. y < x + 3 y-int = 3 ; slope = 1 1 dotted line ; shade down y > x – 1 y-int = -1 ; slope = 1 1 solid line ; shade up 2. y < x + 3y > x - 1

  6. y < x + 3 y-int = 3 ; slope = 1 1 dotted line ; shade down y > x – 1 y-int = -1 ; slope = 1 1 solid line ; shade up where do they overlap? 2. y < x + 3 y > x - 1

  7. y < -x + 5 y-int = 5 ; slope = -1 1 dotted line ; shade down y < 3x – 2 y-int = -2 ; slope = 3 1 dotted line ; shade down 3. y < -x + 5 y < 3x - 2

  8. y < -x + 5 y-int = 5 ; slope = -1 1 dotted line ; shade down y < 3x – 2 y-int = -2 ; slope = 3 1 dotted line ; shade down where do they overlap? 3. y < -x + 5 y < 3x - 2

  9. x + y > 2 - x -x y > -x + 2 y-int = 2 ; slope = -1 1 dotted line ; shade up 2x – y < 1 - 2x - 2x -y < -2x + 1 -1 -1 -1 y > 2x – 1 y-int = -1 ; slope = 2 1 dotted line ; shade up 4. x + y > 2 2x – y < 1 divide by neg. flip symbol

  10. x – 2y < 4 - x -x -2y < -x + 2 -2 -2 -2 y > ½x – 1 y-int = -1 ; slope = 1 2 dotted line ; shade up 2x + y > 3 - 2x - 2x y > -2x + 3 y > -2x + 3 y-int = 3 ; slope = -2 1 dotted line ; shade up 5. x – 2y < 4 2x + y > 3 divide by neg. flip symbol

  11. x – 3y < 9 - x -x -3y<-x + 9 -3 -3 -3 y >1/3x – 3 y-int = -3 ; slope = 1 3 solid line ; shade up 2x – y > 3 - 2x - 2x -y > -2x + 3 -1 -1 -1 y < 2x – 3 y-int = -3 ; slope = 2 1 dotted line ; shade down 6. x – 3y < 9 2x – y > 3 divide by neg. flip symbol divide by neg. flip symbol

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