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Understanding Light and Quantum Models in Physics

Explore the dual wave-particle properties of light and dive into quantum models explaining electron behavior and configurations in atoms. Discover the fascinating world of luminescence and electron configurations.

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Understanding Light and Quantum Models in Physics

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  1. Ch4: Electrons Final 1 2 3 4

  2. 100 LightName three wave properties of light.Light behaves as a wave when it _______.Answer

  3. Light 100 Refraction, diffraction, interference, reflection Light behaves as a wave when it propagates (travels).

  4. 200 LightWhen an electron in an atom falls from the 5th to the 2nd energy level, 4.58 x 1019 J of energy are released. What is the frequency of this energy?Answer All Play!

  5. Light 200 E = h 4.58 x 1019 J = 6.626 x 1034Jsec X Answer = 6.91 x 1014 Hz

  6. 300 LightA bright line in the spectrum of sodium has a wavelength of 5.90 x 102nm. What is the frequency?Answer All Play!!

  7. Light 300 ?m = 5.90 x 102 nm x 1 m_ = 5.90 x 10-7 m 1 x 109 nm Use c =  3.00 x 108m/sec = 5.90 x 10-7 m X Answer X= 5.08 x 1014Hz

  8. 400 LightExplain the photoelectric effect. Is this a wave or particle property? Give an example of how this is useful.Answer

  9. Light400 Light of certain frequencies striking a metal causes the metal to release electrons. (electric current is created) This is a particle property. Useful: solar panels, garage door opener safety

  10. 500 LightA device emits light with frequency of 9.37 x 107 Hz. Find the wavelength.Is the device a tanning bed, red laser or a radio tower?All Play!Answer

  11. Light 500 Use c =  3.00 x 108 m/s =  9.37 x 107 Hz • = 3.20 m ?nm = 3.20m X 1 x 109 nm= 3.20x 109 nm 1 meter 3.20x 109nm is longer wavelength than visible light, thus it is Radio

  12. 100 Quantum ModelName the scientist who stated that electrons occupy orbitals of equal energy singly, with parallel spins, before doubling up.Answer All Play

  13. Quantum Model100 Hund

  14. 200 Quantum ModelA 3-dimensional region about the nucleus where an electron may be found is a(n)Answer All Play!!!!

  15. Quantum Model200 orbital

  16. 300 Quantum ModelName the 1st quantum number, describe what it indicates and what its possible values are.Answer

  17. Final Jeopardy A photon of yellow light has 3.58 x 10-19 Joules of energy. What is the wavelength of this light in nanometers? Answer

  18. Final Jeopardy Answer E = hc/   = hc = 6.626 x 10-34 Jsec x 3.00 x 108 m/s E 3.58 x 10-19 Joules  = 5.55 x 10-7 m = 555 nm

  19. Quantum Model300 Principle Quantum Number Indicates energy level of electron – distance from nucleus Values are positive integers 1, 2, 3, etc.

  20. 400 Quantum Model The noble gas configuration of an element is: [Kr]5s24d105p3. Identify the element and state how many unpaired electrons it has.Answer All Play!!

  21. Quantum Model400 1. [Kr]5s24d105p3 -- this element is Sb. 2. It has 3 unpaired electrons.

  22. 500 Quantum ModelGive the letters naming the 4 types of sublevels (shapes) and indicate the maximum # of electrons each can hold.Answer

  23. Quantum Model 500 s= 2 p= 6 d = 10 f = 14

  24. An illuminated tungsten light bulb, a hot toaster coil, and molten lava are all examples of __________.The spectrum of these light sources would be _________.Answer 100 Lab All Play!!

  25. Lab 100 Incandescence continuous spectrum

  26. 200 LabExplain the difference between phosphorescence and fluorescence. Give one example of each. Answer

  27. Lab 200 Both are the absorption of energy(usually UV) with the emission of visible light. In fluorescence the object stops glowing as soon as the energy source is removed. In phosphorescence, the glowing persists for a time after the energy source is removed. An example of phosphorescence is: a glow-in-the-dark toothbrush. An example of fluorescence is: the bright white glow of dirty shoelaces under a UV light.

  28. 300 LabA flame test is performed on a metal compound. The flame is a hot pink/magenta color. What metal must be present? (Give name and symbol) Answer

  29. Lab 300 Li Lithium

  30. 400 LabWhat piece of lab equipment is needed to view a spectrum? What in this room emits a bright line spectrum?Answer

  31. Lab 400 A spectroscope The fluorescent lights or a flame test.

  32. 500 LabWhat is the main difference between luminescence and incandescence?Give 2 examples each of incandescence and chemiluminescence.Answer

  33. Lab 500 Luminescence is light produced without heat. Incandescence is light from a material heated to glowing. Incandescence – a W filament light bulb, a metal wire held in a flame until it glows red. Chemiluminescence- glowsticks, fireflies, moon jellyfish, the plants on Pandora

  34. 100 Electron Configuration Identify each of the following atoms based on their electron configurations.A. [Ne]3s2B. [Ar]3d64s2C. [Xe]6s24f145d7 Answer All Play!!

  35. Electron Configuration 100 • Mg – magnesium • Fe – iron • Ir -- iridium

  36. 200 Electron ConfigurationWrite the orbital diagram for phosphorus.Answer

  37. Electron Config 200 Answer          1s 2s 2px py pz 3s 3px py pz

  38. 300 Electron ConfigurationWrite the noble gas configuration for Re, RheniumAnswer

  39. Electron Configuration 300 Re [Xe]6s24f145d5

  40. 400 Electron ConfigurationGive the electron configuratio and noble gas configuration for strontium.Answer

  41. Electron Configuration 400 1s22s22p63s23p64s23d104p65s2 [Kr]5s2 Sr:

  42. 500 Electron ConfigurationWrite an electron configuration for an excited carbon atom.Answer All Play!!

  43. Electron Configuration 500 Ground state: 1s22s22p2 Excited configuration: 1s22s22p13s1 one of the 2p electrons is in a higher energy orbital (can be any higher orbital)

  44. 100 PotpourriWhich of the following configurations is impossible according to the Quantum Model?A. 1s22s23p1B. 1s22s22p62d1C. [Rn]7s26d1D. [Xe]6s25d1Answer All Play!

  45. Potpourri 100 B. Is impossible because there is no d sublevel allowed in the 2nd energy level.

  46. Determine the % by mass of nitrogen in TNT. The formula of TNT is C7H5N3O6Answer 200 Potpourri All Play!!

  47. Answersfor Potpourri 200 % N inC7H5N3O6 % N = 14.01 x 3 x 100 = 18.50% 227.15 g/mol

  48. 300 PotpourriA line in the spectrum of an element has a wavelength of 7.5 x 10-7 m. 1. Can you see this light?2. What is the energy of the light?Answer

  49. Potpourri 300 Answer • The wavelength is longer than visible (7 x 10-7 m or 700nm) thus it is infrared. No, we can’t see it. • E= hc= (6.626 x 10-34Jsec) (3.00 x 108 m/s)  7.5 x 10-7 m = 2.7 x 10-19 J

  50. 400 PotpourriState and explain the Pauli Exclusion Principle.Answer

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