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Control Theory. Integral Action. The formulas. Introduction. Steady state error of the servo problem to a step of size 1 (r 0 =z 0 =0) ?. 0 2 K c + None of the above. [Default] [MC Any] [MC All]. Integral Action.
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ControlTheory Integral Action
Steady state error of the servoproblemto a step of size 1(r0=z0=0)? • 0 • 2Kc • + • None of the above [Default] [MC Any] [MC All]
Integral Action Whenan integrator is present in the loop: steady state error = 0? Idea! We addanintegral in the control action. The PI controllernow looks like (in the time domain): TI is the ‘reset time’: it’s a measure for the time over which this integral is ‘smeared out’. A smaller reset time gives a stronger influence over a shorter period of time. (So notice: to put the I action off, the reset time should be infinity!)
The TF of the PI controller • Has a zero in zero and no poles • Has a zero in zero and one pole • Has a pole in zero and no zeros • Has a pole in zero and one zero [Default] [MC Any] [MC All]
Integral Action The PI controllernow looks like (in the Laplace domain):
Example 1: The TF of the closed loop • Is of first order • Is of second order and onepole lies in 0 • Is of second order and contains a zero in 0 • Is of second order and contains a zero • Is of third order [Default] [MC Any] [MC All]
First example Calculate the steady state error.
Secondexample TakeKc=1 GROUP TASK: Canyou make the polescriticallydamped?
Example 1: The TF of the closed loop • No • The poles are alwayscriticallydamped • Yes, forTI = 0,75 • Yes, forTI = 7,5 • Yes, forTI = 10 [Default] [MC Any] [MC All]
Will I have overshoot in the step response forthatchoice of TI? • Yes • No [Default] [MC Any] [MC All]