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y 1 = (32 mm)/2 tan  = y 1 /L tan  sin   for small 

Example: 633 nm laser light is passed through a narrow slit and a diffraction pattern is observed on a screen 6.0 m away. The distance on the screen between the centers of the first minima outside the central bright fringe is 32 mm. What is the slit width?.

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y 1 = (32 mm)/2 tan  = y 1 /L tan  sin   for small 

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  1. Example: 633 nm laser light is passed through a narrow slit and a diffraction pattern is observed on a screen 6.0 m away. The distance on the screen between the centers of the first minima outside the central bright fringe is 32 mm. What is the slit width? y1 = (32 mm)/2 tan = y1/L tan  sin   for small  32 mm 6 m

  2. Resolution of Single Slit (and Circular Aperture) The ability of optical systems to distinguish closely spaced objects is limited because of the wave nature of light. If the sources are far enough apart so that their central maxima do not overlap, their images can be distinguished and they are said to be resolved.

  3. When the central maximum of one image falls on the first minimum of the other image the images are said to be just resolved. This limiting condition of resolution is called Rayleigh’s criterion.

  4. These come from the small angle approximation, and geometry. From Rayleigh’s criterion we can determine the minimum angular separation of the sources at the slit for which the images are resolved. For a slit of width a: For a circular aperture of diameter D: Resolution is wavelength limited!

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