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Understanding Newton’s 2nd Law Experiment Analysis

Explore Newton’s 2nd Law through lab data analysis on Marcy Road. Calculate mass using acceleration measurements. Interpret graphs to determine force and friction impact. Discover the relationship between force, acceleration, and mass.

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Understanding Newton’s 2nd Law Experiment Analysis

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  1. Newton’s 2nd Law Lab Marcy Road 11/13/08

  2. Newton’s 2nd Law Data

  3. Trial #1 Vi=d/t Vf=d/t Vi=.200/.521 Vf=.200/.209 Vi=.384 m/s Vf=.957 m/s Vf^2=Vi^2+2ad .957^2=.384^2+2(a)1.515 .915849=.147456+3.03 .76839=3.03a .254 m/s/s=a

  4. Trial #1 Continued… w=m*g f=m*a w=.600*9.81 5.886=m*.254 w=5.886 N 23.173 kg=m %diff=act.-exp./act *100 %diff=1.820-23.173/1.820*100 %diff=21.353/1.820*100 %diff=11.73241758*100 %diff=1,173%

  5. Trial #2 Vi=d/t Vf=d/t Vi=.200/.341 Vf=.200/.209 Vi=.587 m/s Vf=1.639 m/s Vf^2=Vi^2+2ad 1.639^2=.587^2+2(a)1.515 2.686321=.344569+3.03a 2.341752=3.03a .773 m/s/s=a

  6. Trial #2 Continued… w=m*g f=m*a w=.800*9.81 7.848=m*.773 w=7.848 N 10.765 kg=m %diff=act.-exp/act*100 %diff=1.820-10.765/1.820*100 %diff=8.945/1.820*100 %diff=4.914835165*100 %diff=491%

  7. Trial #3 Vi=d/t Vf=d/t Vi=.200/.269 Vf=.200/.094 Vi=.743 m/s Vf=2.128 m/s Vf^2=Vi^2+2ad 2.128^2=.743^2+2(a)1.515 4.528384=.552049+3.03a 3.976335=3.03a 1.312 m/s/s=a

  8. Trial #3 Continued… w=m*g f=m*a w=1.000*9.81 9.81=m*1.312 w=9.81 N 7.477 kg=m %diff=act.-exp./act.*100 %diff=1.820-7.477/1.820*100 %diff=5.657/1.820*100 %diff=3.108241758*100 %diff=311%

  9. Diagram ceiling pulley weight string gate #2 gate #1 sled board pulley counter floor

  10. Questions • Newton’s 2nd Law states that when an unbalanced fore acts on an object, the object is accelerated in the direction of the force. • We used Newton’s 2nd Law to find the mass of the cart by creating an unbalanced force on the cart and measured the acceleration. • The y-values are the force applied, the x-values are the acceleration and the plotted dots or the slope are the mass. • The force needed to overcome the friction on the cart is the y-intercept, 4.9576 N.

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