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Newton’s Laws

Newton’s Laws. Newton’s First Law. Newton’s first law of motion states that an object will remain at rest or moving in at a constant velocity unless it is acted upon by an unbalanced force. i.e. table cloth demo, or ripping a paper towel off a roll of paper towels. Newton’s Second Law.

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Newton’s Laws

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  1. Newton’s Laws

  2. Newton’s First Law Newton’s first law of motion states that an object will remain at rest or moving in at a constant velocity unless it is acted upon by an unbalanced force. i.e. table cloth demo, or ripping a paper towel off a roll of paper towels.

  3. Newton’s Second Law Newton’s second law of motion states that acceleration depends on the net force acting on an object and on the object’s mass. Acceleration = force / mass or A= F/m

  4. A=f/m example: A speed boat pulls a 55 kg water skier. The skier accelerates at 2.0 m/s/s. Calculate the net force that causes this acceleration. Given: mass= 55kg acceleration= 2.0 m/s/s Find: net force Solution: a= f/m or f=ma f=(55kg) x (2.0 m/s/s) f= 110 kg x m/s/s or 110 N

  5. Newton’s Third Law Newton’s third law of motion states that if one object exerts a force on another object, then the second object exerts a force of equal strength in the opposite direction on the first object. i.e. Newton’s cradle or shooting a gun

  6. Momentum All moving objects have momentum. To calculate momentum, multiply the object’s mass and velocity. Momentum = mass x velocity Conservation of Momentum The total momentum of any group of objects remain the same, or is conserved unless outside forces act upon it.

  7. 2 m/s 2 kg 4 kg Momentum example: Given: mass A= 4 kg velocity A= 2 m/s mass B= 2 kg velocity B= 0 m/s Find: momentum A, momentum B, total momentum after collision Solution: momentum A = mv momentum A = (4 kg) (2 m/s) momentum A = 8 kg m/s

  8. 2 m/s 2 kg 4 kg Momentum example: Given: mass A= 4 kg velocity A= 2 m/s mass B= 2 kg velocity B= 0 m/s Find: momentum A, momentum B, total momentum after collision Solution: momentum B = mv momentum B = (2 kg) (0 m/s) momentum B = 0 kg m/s

  9. 2 m/s 2 kg 4 kg Momentum example: Given: mass A= 4 kg velocity A= 2 m/s mass B= 2 kg velocity B= 0 m/s Find: momentum A, momentum B, total momentum after collision Solution: total momentum = mAvA + mBvB total momentum = (4 kg x 2m/s) + (2 kg x 0 m/s) total momentum = 8 kg m/s

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