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VB Collection Data Structures

VB Collection Data Structures. Array ArrayList HashTable VB6 Collection Others:SortedList, Stack, Queue. Arrays. Declaring a Array. With subscript: Dim numbers(2) as Integer Using variable as subscript: Dim arrayIndex as Integer = 10 Dim myArray(arrayIndex) as Integer

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VB Collection Data Structures

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  1. VB Collection Data Structures

  2. Array • ArrayList • HashTable • VB6 Collection • Others:SortedList, Stack, Queue

  3. Arrays

  4. Declaring a Array • With subscript: • Dim numbers(2) as Integer • Using variable as subscript: • Dim arrayIndex as Integer = 10 • Dim myArray(arrayIndex) as Integer • Without subscript • Dim numbers() as Integer = {2, 4, 6} • Dim someNames() as String = {“”, “”, “”} • Note: Can not have a subscript with a initialization list. • Without subscript and initialization • Dim numbers As Integer() • numbers = New Integer() {2, 4, 6}

  5. Accessing Array Elements with a For … Next Loop • Dim i As Integer = 0, sum As Integer = 0 • For i = 0 To 2 • sum += numbers(i) • Next • GetUpperBound • For i = 0 to numbers.GetUpperBound(0) sum += numbers(i) • Next • Length • For i = 0 to numbers.length-1 sum += numbers(i) • Next

  6. Accessing Array Elements with a For Each Loop Dim i As Integer For Each i In numbers i = i * 2 MessageBox.Show(i.ToString) Next

  7. Array’s Properties and Methods • Properties: • Length • IsFixedSize • IsReadOnly • Methods • BinarySearch *** return negative value if not found • Clear • Clone, Copy, CopyTo • GetLowerBound, GetUpperBound • Reverse • Sort

  8. Highest Values in a Array Dim highest As Integer highest = numbers(0) For i = 1 To numbers.GetUpperBound(0) If numbers(i) > highest Then highest = numbers(i) End If Next

  9. Searching Arrays Dim found As Boolean = False Dim searchValue As Integer searchValue = InputBox("Enter search value: ") For i = 0 To numbers.GetUpperBound(0) If numbers(i) = searchValue Then found = True Exit For End If Next If found Then MsgBox("Number found") Else MsgBox("Number not found") End If

  10. Searching with the IndexOf Method If numbers.IndexOf(numbers, InputBox("Enter search value: ")) < 0 Then MessageBox.Show("not exist") Else MessageBox.Show("exist") End If

  11. Using Parallel Relationship between Array and Listbox Private Sub Form4_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load ListBox1.Items.Add("Peter") ListBox1.Items.Add("Paul") ListBox1.Items.Add("Mary") phone(0) = "1234" phone(1) = "6789" phone(2) = "3456" End Sub Private Sub ListBox1_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ListBox1.SelectedIndexChanged MessageBox.Show(ListBox1.SelectedItem & "phone is" & phone(ListBox1.SelectedIndex)) End Sub

  12. ReDim • ReDim numbers(5) • Original values in the array will be lost. • ReDim Preserve numbers(5) • Use ReDim to assign size if the array is declared without subscript. • Dim test As Integer() • … • ReDim test(2)

  13. Passing Arrays as Arguments Dim outstr As String setnew(test) For i = 0 To test.GetUpperBound(0) outstr &= test(i).ToString & vbCrLf Next MessageBox.Show(outstr) End Sub Sub setnew(ByVal a() As Integer) Dim i As Integer For i = 0 To a.GetUpperBound(0) a(i) = 0 Next End Sub Note: ByVal or ByRef? With ByVal, it will prevent an array argument from being assigned to another array.

  14. Two-Dimensional Arrays • Depts=1 • Prods=2 • Dim SalesData(Depts, Prods) As Double • With initialization • Dim SalesData(,) as Double = {{20,30,15},{40,32,55}}

  15. For Each Loops for 2-dimensional Array Dim salesData(,) As Double = {{20, 15, 30}, {30, 21, 50}} Dim totalSales, I As Double For Each I In salesData totalSales += I Next TextBox1.Text = totalSales.ToString

  16. For Next Loops for 2-dimensional Array Dim row, col As Integer For row = 0 To salesData.GetUpperBound(0) For col = 0 To salesData.GetUpperBound(1) totalSales += salesData(row, col) Next Next MessageBox.Show(totalSales.ToString) Problem: How to compute total sales by Department? by Product?

  17. Data Binding with Arrays • Connect a control to one data source. • Arrays can be used as data source for a control. • Demo: ListBox DataSource property. • Dim fruits() As String = {"Apple", "Orange", "Banana", "Strawberry", "Kiwi"} • ListBox1.DataSource = fruits

  18. Other Collections • More flexible than array: • No need to declare the number of objects in a collection. • Objects can be added, deleted at any position. • Object can be retrieved from a collection by a key. • Can store any types of data.

  19. ArrayList • Define an arraylist: • Dim myArrayList As New ArrayList() • Properties:Count, Item, etc. • myArrayList.Item(0) 0-based index • Methods: • Clear, Add, Insert, Remove, RemoveAt, Contains, IndexOf, etc.

  20. ArrayList Demo Dim testArrayList As New ArrayList() Dim Fruits() As String = {"Apple", "orange", "Banana"} Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim f2 As New Form2() testArrayList.Add("David") testArrayList.Add(20) testArrayList.Add(Fruits) testArrayList.Add(f2) TextBox1.Text = testArrayList.Item(0) TextBox2.Text = testArrayList.Item(1).ToString TextBox3.Text = testArrayList.Item(2)(1) TextBox4.Text = testArrayList.Item(3).Age End Sub

  21. For Each Loop with ArrayList Dim testArrayList As New ArrayList() Dim f2 As New DataForm2() Dim Fruits() As String = {"Apple", "orange", "Banana"} testArrayList.Add("David") testArrayList.Add(20) testArrayList.Add(Fruits) testArrayList.Add(f2) Dim myObj As Object For Each myObj In testArrayList MessageBox.Show(myObj.GetType.ToString) Next

  22. Data Binding with ArrayLists • Arraylists can be used as data source for a control. • Demo: ListBox DataSource property. • Dim myArrayList As New ArrayList() • myArrayList.Add("apple") • myArrayList.Add("banana") • myArrayList.Add("orange") • ListBox1.DataSource = myArrayList

  23. Spelling Checker Example Dim wordList As New ArrayList Private Sub Form3_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load wordList.Add("This") wordList.Add("is") wordList.Add("a") wordList.Add("list") wordList.Add("of") wordList.Add("words") wordList.Add("that") wordList.Add("we") wordList.Add("will") wordList.Add("use") wordList.Add("in") wordList.Add("the") wordList.Add("spell") wordList.Add("checker") wordList.Add("david") wordList.Add("chao") wordList.Add(" ") End Sub

  24. Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Try Dim re As Regex re = New Regex("\w+") Dim source As String source = txtSource.Text Dim mc As MatchCollection = re.Matches(source) Dim m As Match Dim result As String For Each m In mc If Not wordList.Contains(m.Value) Then result += m.ToString & vbCrLf txtSource.Select(txtSource.Text.IndexOf(m.ToString), m.Length) MessageBox.Show("next") End If Next MessageBox.Show("Invalid words: " & vbCrLf & result) Catch ex As System.Exception MessageBox.Show(ex.Message) End Try End Sub

  25. HashTable • The HashTable collection provides very fast look-up. • Each element in a HashTable is a DictionaryEntry type containing a pair of Key and Value. • Properties:Count, Item, Keys, Values • myHashTable.Item(key) • Methods: • Clear, Add, Remove,ContainsKey, ContainsValue, etc. • Note 1: Elements in a HashTable are stored according to the hash value of keys. • Note 2: Keys must be unique.

  26. HashTable Example Dim myHashTable As New Hashtable() Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load myHashTable.Add("UK", "United Kingdom") myHashTable.Add("US", "United States") myHashTable.Add("CHN", "China") myHashTable.Add("DE", "Germany") Dim myKey As String For Each myKey In myHashTable.Keys ListBox1.Items.Add(myKey) Next End Sub Private Sub ListBox1_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ListBox1.SelectedIndexChanged MessageBox.Show(myHashTable.Item(ListBox1.SelectedItem)) End Sub

  27. Dim searchKey As String searchKey = InputBox("enter key") If myHash.ContainsKey(searchKey) Then TextBox1.Text = myHashTable.Item(searchKey) Else MessageBox.Show("key not exists") End If

  28. VB 6 Collections • Define a collection: • Ex. Dim Pets as New Collection • Methods: • ADD: Add object to a collection • Pets.Add(“dog”) • Add an object with a key: • Pets.Add(“Dog”, “D”) • Item: Retrieve an object from a collection with a position index (base 1) or with a key. • petName = Pets.Item(1) • petName = Pets.Item(“D”) • Count: Return the number of objects in a collection. • Remove: Delete an object with a position index or key.

  29. Iterating Through a Collection Dim Pets as New Collection … Dim Indx as Long For Indx = 1 to Pets.Count …operations … Next Indx For Each pet in Pets … operations … Next pet

  30. Timer • Event: • Tick • Property: • Enable • Interval property • measured in millisecond, 1000 millis = 1 second • Methods: • Start • Stop

  31. Status Bar & Timer • Status Bar • Panels property (collection) • Set ShowPanel property to true. • StatusBar1.ShowPanels = True • StatusBarPanel1.Text = System.DateTime.Now.ToString • Timer • Private Sub Timer1_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer1.Tick StatusBarPanel1.Text = System.DateTime.Now.ToString End Sub

  32. Bitmap Data Type • To read a picture file to program: • Dim pic as New Bitmap(“c:\mypic.jpg”)

  33. Rotate Form’s Background Image Create a collection of pictures: Dim pcol As New ArrayList Add images to collection Dim im1 As New Bitmap("c:\Paradise.jpg") Dim im2 As New Bitmap("c:\Flyaway.jpg") Dim im3 As New Bitmap("c:\SnowTrees.jpg") pcol.Add(im1) pcol.Add(im2) pcol.Add(im3) Use Timer to change image

  34. Dim pcol As New ArrayList Private Sub Form4_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim im1 As New Bitmap("c:\Paradise.jpg") Dim im2 As New Bitmap("c:\Flyaway.jpg") Dim im3 As New Bitmap("c:\SnowTrees.jpg") pcol.Add(im1) pcol.Add(im2) pcol.Add(im3) End Sub Private Sub Timer1_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer1.Tick Static counter As Integer Me.BackgroundImage = pcol.Item(counter) counter += 1 counter = (counter Mod 3) End Sub

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