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Distance vs. Time. Analysis of a Distance vs. Time Graph. Determining the motion on a D vs. T Graph. Where did the object start? Which direction did it go? Where did the object stop? Is the motion uniform (constant)? Is the motion non-uniform (changing)?
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Distance vs. Time Analysis of a Distance vs. Time Graph
Determining the motion on a D vs. T Graph • Where did the object start? • Which direction did it go? • Where did the object stop? • Is the motion uniform (constant)? • Is the motion non-uniform (changing)? • Can you tell which is faster? (if 2 or more objects are present)
d(m) A Object A is stationary at some positive position from the origin. t(s)
d(m) B Object B moves away from origin with a constant positive velocity. t(s)
d(m) C Object C start at some positive position and moves away from the origin at a constant positive velocity. t(s)
d(m) Object D moves away from the origin at a constant positive velocity (slower than previous examples). D t(s)
d(m) Object E start at some positive position and walks toward the origin with a constant velocity. E t(s)
Distance vs. Time Graphs with Non-Uniform Motion Changing velocity (increasing) Changing velocity (decreasing)
Slope of a D vs. T Graph • Rise/run • On a distance vs. time graph • Rise = df – di =Δd • Run = tf – ti = Δt • Slope = Δd / Δt =… Average Velocity (Vave)
Using slope to predict motion • On a distance vs. time graph • If slope is 0, then velocity is 0. • If slope is positive, velocity is constant in positive direction. • If slope is negative, velocity is constant in the opposite direction. • If slope is changing, velocity is changing.(i.e. you are accelerating)
d(m) C B Same velocity as B. Constant +V A V=0 D Slower than B or C. t(s)
E A East B High St. D C West
Finding position Vavg = Δd / Δt Vavg = (df –di)/Δt df = di + Vavg Δt (df = final position)
Time to Practice • Physics Book: • Pg. 85 (2 & 3) • Pg. 87 (5 & 8) • Pg. 89 (9 – 12a)