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Control Flow Testing

Control Flow Testing. Software Quality. Eko Prasetyo Teknik Informatika Univ. Pembangunan Nasional Veteran Jawa Timur 2011. Basic Idea. Dua jenis statemen dasar dalam unit program adalah assignment statements dan conditional statements.

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Control Flow Testing

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  1. Control Flow Testing Software Quality Eko Prasetyo TeknikInformatika Univ. Pembangunan Nasional Veteran JawaTimur 2011

  2. Basic Idea • Duajenisstatemendasardalam unit program adalahassignment statements dan conditional statements. • Statemen assignment secaraeksplisitdirepresentasikanmenggunakansimbol assignment “=“, • seperti : x = 2*y, dimana x dan y are variables. • Condition adalahintidalam statement kondisi, seperti: if(), for() loop, while() loop, and goto. • Misal, dalam if(x! = y), kitamengujiketidaksamaan x dan y. • Pemanggilanfungsiadalahmekanismeuntukmemberikanabstraksidesain program. • Karenafungsimenerima input danmemberikan output, makasebuahfungsisebenarnyamenjalankanserangkaianstatemendarititikmasukansampaiketitikkeluaran. • Eksekusiserangkaianinstruksidarititikmasukketitikkeluardisebutdenganlintasan (path).

  3. Lintasan (path) unit program • Sebuah unit program bisamempunyaisejumlah path, banyak, bahkantakterhinggajumlahnya. • Sebuah path dikarakteristikkandengansebuah input dansebuah output yang diharapkan. • Sebuahmasukanbisamemberikankeluaran yang berbedakarenalintasan yang dilaluijugaberbeda. • Semakinbanyakkemungkinanpengujian, akanmemberikankualitas unit yang lebihbaik. • Control flow testing, dilakukanoleh programmer.

  4. Outline Control Flow Testing

  5. Simbol Control Flow Graph (CFG)

  6. Contoh CFG • Unit program untukmenentukanbilanganterbesardari 3 bilangan. • Koding: A, B, C 1 A, B, C if A>B if A>C max = A else max = B end else if B>C max = B else max = C end 2 T F A > B 3 4 A > C B > C T F T F 7 8 5 6 max = A max = C max = B max = C

  7. A, B, C 1 Jalur yang mungkinterjadi 2 T F A > B 3 4 A > C B > C T F T F 7 8 5 6 max = A max = C max = B max = C Input Domain danJalur yang mungkinterjadi

  8. Pengujian

  9. Latihan • Jika A adalahbilangangenapmakakalikan A dengan 2, kemudianhitungjumlahdarikelipatan 5 untuk 2*A • Jika A adalahbilanganganjilmakakalikan A dengan 2 kemudianditambah 1, kemudianhitungjumlahdarikelipatan 10 untuk 2*A+1 • Misal: • A= 2, B=2*A=4, H=1 • A= 4, B = 2*A = 8, H = 2 • A = 10, B = 2*A=20, H=4 • A = 3, B = 2*A+1=7, H=1 • A= 7, B = 2*A+1 = 15, H=2 • A = 11, B = 2*A+1 = 23, H=3

  10. Latihan A = ? sisa = A mod 2 H = 0 1 A = ? sisa = A mod 2 H = 0; if sisa == 0 B = 2*A while B > 5 H = H+1 B = B - 5; end while else B = 2*A+1 while B > 10 H = H+1 B = B - 10; end while End if H = H+1 F 2 T sisa == 0 4 3 B = 2*A B = 2*A+1 5 6 B > 5 B > 10 F F T T 7 9 H = H + 1 B = B - 5 H = H + 1 B = B - 10 10 H = H + 1

  11. A = ? sisa = A mod 2 H = 0 Input domain danJalur yang mungkinterjadi 1 F 2 T sisa == 0 4 3 B = 2*A B = 2*A+1 5 6 B > 5 B > 10 F F T Pengujian T 7 9 H = H + 1 B = B - 5 H = H + 1 B = B - 10 10 H = H + 1

  12. A = ? sisa = A mod 2 H = 0 Input domain danJalur yang mungkinterjadi 1 F 2 T sisa == 0 4 3 B = 2*A B = 2*A+1 5 6 B > 5 B > 10 F F T Pengujian T 7 9 H = H + 1 B = B - 5 H = H + 1 B = B - 10 10 H = H + 1

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