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HOW TALL IS IT?

HOW TALL IS IT?. By: Kenneth Casey, Braden Pichel, Sarah Valin , Bailey Gray. 1 st Period – March 8, 2011. Kenneth Casey 1 st. 30˚. Trigonometry. Opposite 30˚ is X. Adjacent 30˚ is 36 feet. Tangent= Opposite÷Adjacent. Tan 30˚= X÷36 feet. Tan (30) 36 = 20.78 ft.

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HOW TALL IS IT?

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  1. HOW TALL IS IT? By: Kenneth Casey, Braden Pichel, Sarah Valin, Bailey Gray 1st Period – March 8, 2011

  2. Kenneth Casey 1st 30˚ Trigonometry Opposite 30˚ is X. Adjacent 30˚ is 36 feet. Tangent= Opposite÷Adjacent. Tan 30˚= X÷36 feet. Tan (30) 36 = 20.78 ft. 20.78 ft + 5.83 ft = 26.61 ft. Special right triangles Long leg= short leg √3 36=x√3 (36/√3) = (x√3/√3) X=(36/√3) (√3/√3) X=36√3/3 X=12√3=20.78ft. 20.78 ft + 5.83 ft = 26.61 ft. 60˚ X 30˚ 5.83ft. 36 ft.

  3. 45˚ - Sarah Valin • Special Right Triangles- • leg = leg • x = 48 • 48 ft + 5.75 ft = 53.75 ft • Trig- • Tan 45° = x/48 • x = 48 • 48 ft + 5.75 ft = 53.75 ft 45° x 45° 90° 48 ft 5.75 ft

  4. 60° - Bailey Gray 30° x 60° 90° 12 ft 4.9 ft Special Right Triangles (30-60-90) : l.leg = sh.leg √3 x = 12 √3 ≈20.78 20.78 ft + 4.9 ft = 25.68 ft Trig: tan 60° = x/12 x ≈ 20.78 20.78 ft + 4.9 ft = 25.68 ft

  5. Braden Pichel 1st 20⁰ Y X 20⁰ 60 5.25 5.25 Cos20 = 60/yCos20(y) = 60 y = 60/Cos20 y ≈ 63.85 ft. Tan20 = x/60x = Tan20(60) x ≈ 21.84 ft. Height = x + 5.25 Height = 21.84 + 5.25 Height ≈ 27.09 ft.

  6. CONCLUSION We learned that the average height of the library arch is about 33.28 feet high. To figure this out, each person measured the top of the arch from a different angle using a clinometer. Then, we each figured out the height by using the formulas for a special right triangle and/or using trigonometry, depending on which angle was measured. After, we added the total heights each person got for their triangle, then divided by 4 to get out average height for the library arch.

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