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Warm Up Find the perimeter and area of each polygon.

Warm Up Find the perimeter and area of each polygon. 1. a rectangle with base 14 cm and height 9 cm 2. a right triangle with 9 cm and 12 cm legs 3. an equilateral triangle with side length 6 cm. P = 46 cm; A = 126 cm 2. P = 36 cm; A = 54 cm 2. Objectives.

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Warm Up Find the perimeter and area of each polygon.

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  1. Warm Up Find the perimeter and area of each polygon. 1.a rectangle with base 14 cm and height 9 cm 2. a right triangle with 9 cm and 12 cm legs 3. an equilateral triangle with side length 6 cm P = 46 cm; A = 126 cm2 P = 36 cm; A = 54 cm2

  2. Objectives Learn and apply the formula for the surface area of a prism. Learn and apply the formula for the surface area of a cylinder.

  3. Prisms and cylinders have 2 congruent parallel bases. A lateral faceis not a base. The edges of the base are called base edges. A lateral edgeis not an edge of a base. The lateral faces of a right prismare all rectangles. An oblique prismhas at least one nonrectangular lateral face.

  4. An altitudeof a prism or cylinder is a perpendicular segment joining the planes of the bases. The height of a three-dimensional figure is the length of an altitude. Surface areais the total area of all faces and curved surfaces of a three-dimensional figure. The lateral area of a prism is the sum of the areas of the lateral faces.

  5. The net of a right prism can be drawn so that the lateral faces form a rectangle with the same height as the prism. The base of the rectangle is equal to the perimeter of the base of the prism.

  6. The surface area of a right rectangular prism with length ℓ, width w, and height h can be written as S = 2ℓw + 2wh + 2ℓh.

  7. Caution! The surface area formula is only true for right prisms. To find the surface area of an oblique prism, add the areas of the faces.

  8. Example 1A: Finding Lateral Areas and Surface Areas of Prisms Find the lateral area and surface area of the right rectangular prism. Round to the nearest tenth, if necessary. L = Ph P = 2(9) + 2(7) = 32 ft = 32(14) = 448 ft2 S = Ph + 2B = 448 + 2(7)(9) = 574 ft2

  9. Example 1B: Finding Lateral Areas and Surface Areas of Prisms Find the lateral area and surface area of a right regular triangular prism with height 20 cm and base edges of length 10 cm. Round to the nearest tenth, if necessary. L = Ph = 30(20) = 600 cm2 P = 3(10) = 30 cm S = Ph + 2B The base area is

  10. Check It Out! Example 1 Find the lateral area and surface area of a cube with edge length 8 cm. L = Ph = 32(8) = 256 cm2 P = 4(8) = 32 cm S = Ph + 2B = 256 + 2(8)(8) = 384 cm2

  11. The lateral surfaceof a cylinder is the curved surface that connects the two bases. The axis of a cylinderis the segment with endpoints at the centers of the bases. The axis of a right cylinderis perpendicular to its bases. The axis of an oblique cylinderis not perpendicular to its bases. The altitude of a right cylinder is the same length as the axis.

  12. Example 2A: Finding Lateral Areas and Surface Areas of Right Cylinders Find the lateral area and surface area of the right cylinder. Give your answers in terms of . The radius is half the diameter, or 8 in. L = 2rh = 2(8)(10) = 160 in2 S = L + 2r2 = 160 + 2(8)2 = 288 in2

  13. Example 2B: Finding Lateral Areas and Surface Areas of Right Cylinders Find the lateral area and surface area of a right cylinder with circumference 24 cm and a height equal to half the radius. Give your answers in terms of . Step 1 Use the circumference to find the radius. Circumference of a circle C = 2r Substitute 24 for C. 24 = 2r Divide both sides by 2. r = 12

  14. Example 2B Continued Find the lateral area and surface area of a right cylinder with circumference 24 cm and a height equal to half the radius. Give your answers in terms of . Step 2 Use the radius to find the lateral area and surface area. The height is half the radius, or 6 cm. L = 2rh = 2(12)(6) = 144 cm2 Lateral area S = L + 2r2 = 144 + 2(12)2 = 432 in2 Surface area

  15. Check It Out! Example 2 Find the lateral area and surface area of a cylinder with a base area of 49and a height that is 2 times the radius. Step 1 Use the circumference to find the radius. A = r2 Area of a circle 49 = r2 Substitute 49 for A. Divide both sides by  and take the square root. r = 7

  16. Check It Out! Example 2 Continued Find the lateral area and surface area of a cylinder with a base area of 49and a height that is 2 times the radius. Step 2 Use the radius to find the lateral area and surface area. The height is twice the radius, or 14 cm. Lateral area L = 2rh = 2(7)(14)=196in2 Surface area S = L + 2r2 = 196 + 2(7)2 =294 in2

  17. Example 3: Finding Surface Areas of Composite Three-Dimensional Figures Find the surface area of the composite figure.

  18. Check It Out! Example 3 Find the surface area of the composite figure. Round to the nearest tenth.

  19. Check It Out! Example 3 Continued Find the surface area of the composite figure. Round to the nearest tenth. The surface area of the rectangular prism is S =Ph + 2B = 26(5) + 2(36) = 202 cm2. The surface area of the cylinder is S =Ph + 2B = 2(2)(3) + 2(2)2 = 20 ≈ 62.8 cm2. The surface area of the composite figure is the sum of the areas of all surfaces on the exterior of the figure.

  20. Check It Out! Example 3 Continued Find the surface area of the composite figure. Round to the nearest tenth. S = (rectangular surface area) + (cylinder surface area) – 2(cylinder base area) S = 202 + 62.8 — 2()(22) = 239.7 cm2

  21. Remember! Always round at the last step of the problem. Use the value of  given by the  key on your calculator.

  22. Example 4: Exploring Effects of Changing Dimensions The edge length of the cube is tripled. Describe the effect on the surface area.

  23. 24 cm Example 4 Continued original dimensions: edge length tripled: S = 6ℓ2 S = 6ℓ2 = 6(24)2 = 3456 cm2 = 6(8)2 = 384 cm2 Notice than 3456 = 9(384). If the length, width, and height are tripled, the surface area is multiplied by 32, or 9.

  24. Check It Out! Example 4 The height and diameter of the cylinder are multiplied by . Describe the effect on the surface area.

  25. 11 cm 7 cm Notice than 550 = 4(137.5). If the dimensions are halved, the surface area is multiplied by Check It Out! Example 4 Continued original dimensions: height and diameter halved: S = 2(112) + 2(11)(14) S = 2(5.52) + 2(5.5)(7) = 550 cm2 = 137.5 cm2

  26. Example 5: Recreation Application A sporting goods company sells tents in two styles, shown below. The sides and floor of each tent are made of nylon. Which tent requires less nylon to manufacture?

  27. Example 5 Continued Pup tent: Tunnel tent: The tunnel tent requires less nylon.

  28. Check It Out! Example 5 A piece of ice shaped like a 5 cm by 5 cm by 1 cm rectangular prism has approximately the same volume as the pieces below. Compare the surface areas. Which will melt faster? The 5 cm by 5 cm by 1 cm prism has a surface area of 70 cm2, which is greater than the 2 cm by 3 cm by 4 cm prism and about the same as the half cylinder. It will melt at about the same rate as the half cylinder.

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