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Ejercicio 14 – pag. 54 Organizar los datos: 5 movimientos

Ejercicio 14 – pag. 54 Organizar los datos: 5 movimientos 1) mrua (a+) V 0 = 0 m/s, a=2 m/s 2 , t=4 s 2) mrua (a+), a=6 m/s 2 , t=1 s 3) mrua (a-) a=-4 m/s 2 , t=3 s 4) mru (a0) a=0 m/s 2 , t=1 s 5) mrua (a-) a=-2 m/s 2 , t=1 s Dibujo o esquema y sistema de referencia:

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Ejercicio 14 – pag. 54 Organizar los datos: 5 movimientos

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  1. Ejercicio 14 – pag. 54 • Organizar los datos: • 5 movimientos • 1) mrua (a+) V0= 0 m/s, a=2 m/s2, t=4 s • 2) mrua (a+), a=6 m/s2, t=1 s • 3) mrua (a-) a=-4 m/s2, t=3 s • 4) mru (a0) a=0 m/s2, t=1 s • 5) mrua (a-) a=-2 m/s2, t=1 s • Dibujo o esquema y sistema de referencia: Origen sistema de referencia, la posición Inicial 0, V0= 0 m/s mrua(a+) mrua(a+) mrua(a+) mru(a0) mrua(a-) mrua(a-) mru(a0) mrua(a-) 0 0 A A B B C C D E Miguel Vaquero

  2. Combinación de movimientos • Ecuaciones del movimiento y Resolución:De 0 a A: v = 0 + 2 t = 2 · 4 = 8 m/s, e = 0 · 10 + ½ 2 · 42 = 16 m De A a B: v = 8 + 6 t = 14 m/s e = 16 + 8 · 1 + ½ 6 · 12 = 27 m De B a C: v = 14 – 4 · 3 = 2 m/s e = 27 + 14 · 3 - ½ 4 · 32 = 51 m De C a D: v = 2 m/s e = 51 + 2 · 1 = 53 m De D a E: v = 2 – 2 · 1 = 0 m/s e = 53 + 2 · 1 - ½ 2 · 12 = 54 m Miguel Vaquero

  3. Combinación de movimientos Gráfica velocidad - tiempo: Miguel Vaquero

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