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Learn how to interpret velocity-time graphs, calculate displacement, and understand the relationship between velocity and time. Explore areas under the graph and equations for motion.
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The slope > 0 (positive). The object is moving towards the end position
The slope <0 (negative). The object is moving towards the start position
Speed or velocity is at middle instant of the time interval.
Construct from a distance-time graph (or a displacement-time graph)
Displacement and v-t graph • The following slides show you the relationship between displacement (S) and the v-t graph (velocity-time graph)
area under the graph? Graph area under the graph from t = 0.1s to 0.2s is the distance travelled during t=0.1s to 0.2s Area = 0.6 x (0.2- 0.1) Area = speed x time = distance
Displacement travelled by the object from time t1 to t2 = area A V1
V/ms-1 v2 v1 t/s t1 t2 The area under v-t graph Displacement due to the increase of velocity from v1 to v2 from t1 to t2 Displacement due to v1 from t1 to t2
c is the y-intercept, c = 0. Slope m= a. The equation is v = a t y = mx
‘at’ or ‘v’ S = area t
y m x c
at v S=(u+v)t/2 1/2 (a t2) ut u u t t
nos nov noa not
u , v , a & s can be ‘+’ or ‘-’ depend on direction
‘+’direction Case 1 t = 3s u = 1ms-1 v = 4ms-1 a = ? Case 2 t = 5s u = 1ms-1 v = - 4ms-1