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Optical Devices Demonstration

Explore different optical devices in action - from cameras to projectors and more. Understand how lenses create images based on object distance and focal length. Discover the fascinating world of optics with practical examples.

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Optical Devices Demonstration

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  1. LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm Measured di = 7.7 cm hi = 2.0 cm scale 1cm = 1cm ho di F 2F' F' hi dO 2F Theoretical Distance to Image Height of Image 1/do + 1/di = 1/f m = -di/do hi = m(ho) 1/10 + 1/di = 1/4.3 m = - 7.54/10 hi = .75(2.5) di = 7.54 cm m = -.75 hi = 1.88cm % deviation = 2.12% - inverted % deviation = 6.38% < 1 smaller This is an example of a camera. The object is located beyond 2F. The image formed is located between F' and 2F'. The image is real, inverted and smaller than the object. F stops on cameras adjust the focal length of the lens.

  2. LENS F= 4.3 cm OBJECT AT 2F Distance to Object dO = 8.6 cm Height of Object hO = 2.5 cm scale 1cm = 1cm Measured di = 8.3 cm hi = 2.2 cm ho . dO F 2F' F' 2F Theoretical Distance to Image Height of Image 1/d0 + 1/di = 1/f m = -di/d0 hi = m(ho) 1/8.6 + 1/di = 1/4.3 m = -8.6/8.6 hi = -1(2.5) di = 8.6 cm m = -1 hi = 2.5cm % deviation = 3.49% - inverted % deviation = 12% = 1 same size This is an example of a photo copier. The object is located at 2F. The image formed is located at 2F'. The image is real, inverted and the same size as the object.

  3. LENS F= 4.3 cm OBJECT BETWEEN 2F & F MEASURED Distance to Object dO = 6 cm di = 11.6 cm Height of Object hO = 2.5 cm hi = 4.9 cm scale 1cm = 1cm ho dO 2F' 2F F' F di Theoretical Distance to Image Height of Image 1/do + 1/di = 1/f m = -di/do hi = m(ho) 1/6 + 1/di = 1/4.3 m = -15.18/6 hi = 2.53(2.5) di = 15.18 cm m = -2.53 hi = 6.33 cm % deviation = 23.58% - inverted % deviation = 22.59% > 1 larger hi This is an example of a projector. The object is between 2F and F. The image formed is located beyond 2F'. The image is real, inverted and larger than the object. Slides are put on a projector upside down so that the image is seen right side up.

  4. LENS F= 4.3 cm OBJECT AT F Distance to Object dO = 4.3 cm Height of Object hO = 2.5 cm ho dO 2F' F' 2F F The rays are parallel and will not intersect. scale 1cm = 1cm This is an example of a lighthouse. There is no image.

  5. LENS F= 4.3 cm OBJECT BETWEEN F & LENS MEASURED Distance to Object dO = 2.0 cm di = 3.9 cm Height of Object hO = 2.5 cm hi = 4.8 cm scale 1cm = 1cm hi ho dO di 2F' 2F F' F Theoretical Distance to Image Height of Image 1/do + 1/di = 1/f m = -di/do hi = m(ho) 1/2 + 1/di = 1/4.3 m = -(-3.74)/2 hi = 1.87(2.5) di = -3.74 cm m = 1.87 hi = 4.68 cm - on same side as object + erect virtual image % deviation = 4.28% >1 larger % deviation = 2.5% This is an example of a magnifying glass. The object is between F and the lens. The image formed is on the same side as the object. The image is virtual, erect and larger than the object. A magnifying glass is used to make objects look larger to the human eye and used only when a real image is not necessary.

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