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(Mon) A 100 g ball has to travel a horizontal distance of 10 m to a target. If the ball is released at an angle of 30 º above horizontal, what speed must it have when it is released to reach the target? (10 min / 7 pts).
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(Mon) A 100 g ball has to travel a horizontal distance of 10 m to a target. If the ball is released at an angle of 30º above horizontal, what speed must it have when it is released to reach the target? (10 min / 7 pts)
(Mon) A 100 g ball has to travel a horizontal distance of 10 m to a target. If the ball is released at an angle of 30º above horizontal, what speed must it have when it is released to reach the target? (10 min / 7 pts) In the ‘y’ direction: Δy = (vi)(sin30)(t) + ½(a)(t²) 0 = (vi)(0.5)(t) + (0.5)(-9.81 m/s²)(t²) In the ‘x’ direction: 0 = (vi)(0.5)(11.55/vi) + (0.5)(-9.81)(11.55/(vi))² Δx = (vi)(cos30)(t) 0 = 5.775 – 654.34/(vi)² 10m = (vi)(0.866)(t) 5.775 = 654.34/(vi)² 10/(0.866)(vi) = (t) 654.34/5.775 = (vi)² 11.55/(vi) = (t) vi² = 113.31 vi = 10.64 m/s Substitute (t) value into ‘y’ direction equation
(Tue) A 100 g ball has to travel a horizontal distance of 10 m to a target. The ball is released at an angle of 30º above horizontal with a speed of 10.64 m/s. If you use a rubber band with a spring constant of 150 N/m to accelerate the ball, how much must the rubber band be stretched to reach the target? (5 min / 5 pts)
(Tue) A 100 g ball has to travel a horizontal distance of 10 m to a target. The ball is released at an angle of 30º above horizontal with a speed of 10.64 m/s. If you use a rubber band with a spring constant of 150 N/m to accelerate the ball, how much must the rubber band be stretched to reach the target? (5 min / 5 pts) MEi = MEf X X X X KEi + PEgi + PEei = KEf + PEgf + PEef Cancel terms that are equal to 0 ½kx² = ½mv² ½(150)x² = ½(0.1)(10.64)² x² = 0.0755 x = 27.5 cm
(Wed) A 100 g ball has to travel a horizontal distance of 10 m to a target. The ball is released at an angle of 30º above horizontal with a speed of 10.64 m/s. If you use a catapult that has an arm length of 30 cm, what angular velocity must the ball have when it is released? (5 min / 5 pts)
(Wed) A 100 g ball has to travel a horizontal distance of 10 m to a target. The ball is released at an angle of 30º above horizontal with a speed of 10.64 m/s. If you use a catapult that has an arm length of 30 cm, what angular velocity must the ball have when it is released? (5 min / 5 pts) vt = ωr ω = vt/r ώ = (10.64 m/s)/(0.3 m) ώ = 35.47 rad/s
(Fri) A 100 g ball has to travel a horizontal distance of 10 m to a target. You use a catapult that has an arm length of 30 cm. If that arm starts from rest and rotates 1.05 radiansto release the ball at 35.47 rad/s, what angular acceleration did the ball experience? (5 min / 5 pts)
(Fri) A 100 g ball has to travel a horizontal distance of 10 m to a target. You use a catapult that has an arm length of 30 cm. If that arm starts from rest and rotates 1.05 radiansto release the ball at 35.47 rad/s, what angular acceleration did the ball experience? (5 min / 5 pts) ώf² = ώi² + 2αΔθ (35.47 rad/s)² = 0 + 2α(1.05 rad) α = (1258.12 rad²/s²)/(2.10 rad) ώ = 599.1 rad/s²
End of Week Procedures: • Add up all the points you got this week • Put the total number of points at the top of your page (out of 22 points) • List any dates you were absent (and why) • Make sure your name and period is on the top of the paper • Turn in your papers