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1. The volume of a gas at 99.0 kPa is 300.0 mL. If the pressure is

1. The volume of a gas at 99.0 kPa is 300.0 mL. If the pressure is increased to 188 kPa, what will be the new volume?. P 1 V 1 = P 2 V 2 (99.0 kPa) (300.0 mL) = (188 kPa) V 2 (99.0 kPa) (300.0 mL) = V 2 (188 kPa) V 2 = 158 mL.

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1. The volume of a gas at 99.0 kPa is 300.0 mL. If the pressure is

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  1. 1. The volume of a gas at 99.0 kPa is 300.0 mL. If the pressure is increased to 188 kPa, what will be the new volume? P1V1 = P2V2 (99.0 kPa) (300.0 mL) = (188 kPa) V2 (99.0 kPa) (300.0 mL) = V2 (188 kPa) V2 =158 mL

  2. 2. The pressure of a sample of Helium in a 1.00 L container is 0.988 atm. What is the new pressure if the sample is placed in a 2.00 L container? P1V1 = P2V2 (0.988 atm) (1.00 L) = P2 (2.00 L) (0.988 atm) (1.00 L) = P2 (2.00 L) P2 =0.494 atm

  3. 4. What volume will the gas in the balloon at the right occupy at 250 K? V1=V2 T1 T2 4.3 L = V2V2 =3.1 L 350 K 250 K

  4. 5. A gas at 89 oC occupies a volume of 0.67 L. At what Celsius temperature will the volume increase to 1.12 L? V1=V2 T1 T2 0.67 L = 1.12 L 362 K T2 T2 = 605 K = 330 oC

  5. 6. The Celsius temperature of a 3.00 L sample of gas is lowered from 80.0 oC to 30.0 oC. What will be the resulting volume of this gas? V1=V2 T1 T2 3.00 L = V2 V2 =2.58 L 353 K 303 K

  6. 8. The pressure in an automobile tire is 1.88 atm at 25.0 oC. What is the pressure if the temperature increases to 37.0 oC? P1=P2 T1 T2 1.88 atm = P2P2 =1.96 atm 298 K 310. K

  7. 9. Helium gas in a 2.00 L cylinder is under 1.12 atm of pressure. At 36.5 oC that same gas sample has a pressure of 2.56 atm. What was the initial temperature of the gas in the cylinder? P1=P2 T1 T2 1.12 atm = 2.56 atmT1 =136 K T1 310. K = - 137 oC

  8. 11. A sample of air in a syringe exerts a pressure of 1.02 atm at 22.0 oC. The syringe is placed in a boiling-water bath at 100.0 oC. The pressure is increased to 1.23 atm by pushing the plunger in, which reduces the volume to 0.224 ml. What was the initial volume? P1V1=P2V2 T1 T2 1.02 atm * V1 = 1.23 atm * 0.224 ml 295 K 373 K V1 = 0.214 ml

  9. 12. A balloon contains 146.0 mL of gas confined at a pressure of 1.30 atm and a temperature of 5.0 oC. If the pressure doubles and the temperature decreases to 2.0 oC, what will be the volume of gas in the balloon? P1V1=P2V2 T1 T2 1.30 atm * 146.0 mL = 2.60 atm * V2 278 K 275 K V2 = 72.2 mL

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