300 likes | 377 Views
Exam 2 Help Session. Prepared by Stephen M. Thebaut, Ph.D. University of Florida. Software Testing and Verification. A student writes:
E N D
Exam 2 Help Session Prepared by Stephen M. Thebaut, Ph.D. University of Florida Software Testing and Verification
A student writes: I would like to request you to provide some tips on hypothesizing functions for given programs. I refer in particular to Example 2 of Lecture Notes #24 and Question 1 of the self check quiz in lesson plan for Lectures Notes #’s 24 and 25. Although I followed the concept of synthesizing limited invariants, I found it difficult to come up with a function to represent the given program when I attempted these on my own.
General Rule of Thumb for hypothesizing functions of compound programs: • Work top-down, and • Use the Axiom of Replacement • Good example (nested if_then’s + sequencing): problem 4 of Problem Set 7 • For while loops, see examples 1 and 2 from Lecture Notes #21.
Example 2 (from Lecture Notes #24) • Consider the assertion: {n≥0} p := 1 k := 0 while k<>n do p := p*2 k := k+1 end_while {p=2n} What function, f, is computed by the while loop?
Example 2 (cont’d) P = while k<>n do p,k := 2p,k+1 When will P terminate? What measure would you use to prove this using the method of Well-Founded Sets? Use the measure in one or more conditional rules describing the function. For this case, the initial relationship between k and n determine three different loop “behaviors.” (What are they?)
Example 2 (cont’d) • P = while k<>n do p,k := 2p,k+1 k<n p,k := p2n−k,n k=n p,k := p,k := p2n−k,n k>n undefined Therefore, [P] = (k≤n p,k := p2n−k,n)
Problem 1 from Self-Check Quiz Consider the assertion: y := 0 t := x while t<>k do t := t–1 y := y+1 end_while What function, f, is computed by the while loop?
Problem 1 from Self-Check Quiz (cont'd) P = while t<>k do t,y := t–1,y+1 t>k t,y := k,y+1*(t-k) := k,y+t-k t=k t,y := t,y := k,y+t-k t<k undefined Therefore, [P] = (t≥k t,y := k,y+t-k)
Another student writes: I have some questions about exam 2 for fall 07, problem No 6. And I do not know how to make up counterexample.
6. (4 pts.) It was noted in class that wp(while b do s, Q) is the weakest (while)loop invariant which guarantees termination. Is it also the case that the wp(Repeat s until b) is the weakest (Repeat_until) loop invariant which guarantees termination? Carefully justify your answer. (Hint: recall that in Problem Set 6, you were asked to prove “finalization” from the while loop ROI using the weakest pre-condition as an invariant. Does “finalization” from the Repeat_until ROI hold using the weakest pre-condition as an invariant?) Answer: No. In general, the wp(Repeat s until b, Q) cannot be used as an invariant with the Repeat_until ROI. In particular, (wp(Repeat s until b) Лb ≠> Q in general). (Note that the ROI –- i.e., via the “initialization” antecedent {P} s {I} -- does not require “I” to hold until after s executes.
ROI for while loop and repeat_until loop P I, {IЛ b} S {I}, (IЛb) Q {P} while b do S {Q} {P} S {I}, {IЛ b} S {I}, (IЛ b) Q {P} repeat S until b {Q} Note that for the repeat_until loop, "I" need not hold UNTIL AFTER S executes.
wp(repeat S until b, Q) = H1 V H2 V H3 V... where: H1 = wp(S, b ЛQ) H2 = wp(S, ~b ЛH1) H3 = wp(S, ~b ЛH2) Hk = wp(S, ~b Л Hk-1) Note that b Л (H1 V H2 V H3 V...) Q in general.
Finding counter-examples • Suppose you wish to prove (A => B) is FALSE. • This can be done by finding just one case for which A is true and B is false. This case is referred to as a "counter-example". • So, to prove that the hypothesized ROI: A, B, C {P} while b do S {Q} is FALSE, find one case for which A, B, and C are each true, but {P} while b do S {Q} is FALSE. ?
Finding counter-examples (cont'd) • How do you identify such a case? By exploiting the fallacy in the (FALSE) ROI. • For example, what's the fallacy in the following ROI? P I, (IЛb) Q {P} while b do S {Q} Answer: The two antecedents do not require that "I" holds after S executes! So, choose P, b, S, Q, and I such that the two antecedents hold, but neither I nor Q will hold after S executes when b becomes false. ?
Finding counter-examples (cont'd) P I, (IЛb) Q {P} while b do S {Q} For example, consider, for I: x=1 {x=1 Л y=-17} while y<0 do y := y+1 x := 2 end_while {x=1} ?
Problem 2, Exam 2, Summer ‘09 • Suppose {P} while b do S {Q} for some P, Q, b, and S. Suppose, too, that K = wp(while b do S, Q). Circle “necessarily true” or “not necessarily true” for each of the following assertions. b. {K Л b} S {K} true (See Lecture Notes #20.)
Loop Invariants and wp’s • In general, will loops terminate when P wp ? • For while loops, does {wp Л b} S {wp} ? • Does (wp Л ¬b) Q ? √ √ √
Problem 2, Exam 2, Summer ‘09 • Suppose {P} while b do S {Q} for some P, Q, b, and S. Suppose, too, that K = wp(while b do S, Q). Circle “necessarily true” or “not necessarily true” for each of the following assertions. b. {K Л b} S {K} true (See Lecture Notes #20.) e. {K Л b} repeat S until ¬b {Q} true
{K Лb} {K Лb} S K (since {K Лb} S {K}) S T = ¬b T ¬b F S F {Q} ? {Q} (since (K Л ¬b) Q)
Problem 3, Exam 2, Summer ‘09 3. Circle either “true” or “false” for each of the following assertions. k. ({P} S {Q}) ({P} if b then S {(Q b)}) False The assertion may seem plausible, but consider: {z=1} y:=5 {z=1} {z=1} if x=0 then y:=5 {(z=1 x=0)} ?
Problem 2, Exam 2, Spring ‘10 2. Circle either “true” or “false” for each of the following assertions. h. [{P Л b} S {Q}] [{P} while b do S {Q}] False Consider the counterexample: {x=0} while x<5 do x:=x+1 {x=1}
A student writes: We've learned two ways of identifying loop invariant "I": a heuristic approach and a more systematic approach. My question is: since a systematic approach seems to be more effective, can we always use it to find I for all the problems? • Unfortunately, no. The concept of an “invariant” as described in the context of axiomatic verification is directly related to a Rule of Inference (ROI), e.g.: P I, {IЛ b} S {I}, (IЛb) Q {P} while b do S {Q}
The antecedents represent the necessary and sufficient requirementsfor I (in terms of P, b, S, and Q) in order to use the ROI to deduce {P} while b do S {Q}. • The heuristics considered in class are motivated by these necessary and sufficient requirements, and are therefore dependent on the program’s specification (P and Q), as well as the program itself. • In contrast, a (full) invariant as defined in Mill’s Invariant Status Theorem is a logical condition with properties: q(X0), ( q(X)Лp(X) ) qog(X), and ( q(X)Л¬p(X) ) ( X=f(X0) ) where q(X)=( f(X)=f(X0) ).
The function f = [while p do g],which is “characterized by q on termination,” need not be consistent with the pre- and post-condition used to specify the program by a user/designer. • Thus, an invariant derived using the Invariant Status Theorem may or may not allow one to prove that a user/designer specified post-condition will hold on termination of a loop. • In “reasonable” cases, however, q may be useful, at least as a starting point, in a trial-and-error process. • Additional research is needed to fully explore this area.
A student writes: I still have trouble in providing counter examples... • Consider the following assertion/ROI: “People who wear red shirts do not smoke.” = Wears red shirts(X) => Does not smoke(X) = Wears red shirts(X) Does not smoke(X)
Is the assertion valid (true)? • No. Proof by counterexample: • This person satisfies the antecedent, but not the consequent!
More examples Does [(P Л ¬b) Q] [{P} while b do S {Q}] ? = [(P Л ¬b) Q] [{P} while b do S {Q}] Counterexample: {x=0} while y<>5 do x := x+1; y := y+1 {x=0 Л y=5} ?
From Exam 2, Spring ‘10, problem 2 True or False? c. {x=5} while k <= 5 do k := k+3 {k-x≥0} strongly e. {wp(S, Q)} x>0} x := 17; S {Q}
Confusion re “undefined” and “I” (Identity function) “I am confused about ‘undefined’ and ‘I’. Suppose we have the program P like this: if (x>0) x := 9 end_if Is [P] = (x>0 -> x := 9|true ->I) or [P] = (x>0 -> x := 9|true ->undefined)?
Exam 2 Help Session Prepared by Stephen M. Thebaut, Ph.D. University of Florida Software Testing and Verification