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Free Radical Reactions Halogenation of Alkanes. RH + X 2 RX + HX. Reactive Intermediates. O rbital hybridization in carbocations and carbanions :. Reactive Intermediates: Free Radicals.
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Free Radical ReactionsHalogenation of Alkanes RH + X2 RX + HX
Reactive Intermediates • Orbital hybridization in carbocations and carbanions:
Reactive Intermediates:Free Radicals • Free radicals can be thought of as sp2 hybridized or quickly interconverting sp3 hybridized.
Energetics • RH + X2 RX + HX • explosive for F2 • exothermic for Cl2 and Br2 • endothermic for I2
Chlorination of Methane • carried out at high temperature (400 °C) • CH4 + Cl2 CH3Cl + HCl • CH3Cl + Cl2 CH2Cl2 + HCl • CH2Cl2 + Cl2 CHCl3 + HCl • CHCl3 + Cl2 CCl4 + HCl
.. .. .. .. . . : : : : : Cl Cl Cl Cl .. .. .. .. Mechanism of Chlorination of Methane Free-radical chain mechanism. • The initiation step "gets the reaction going"by producing free radicals—chlorine atomsfrom chlorine molecules in this case. • Initiation step is followed by propagationsteps. Each propagation step consumes onefree radical but generates another one. Initiation step: (Light or Heat is Necessary) +
Question • Which of the above initiates reactions most readily? A) B) C)
.. .. . . H3C H : Cl: Cl: .. .. Second propagation step: .. .. .. .. . . + : : : : : Cl: + Cl Cl Cl H3C H3C .. .. .. .. Mechanism of Chlorination of Methane First propagation step: + H3C : H +
.. .. . . H3C H : Cl: Cl: .. .. .. .. .. .. . . : : : : : Cl: Cl Cl Cl H3C H3C .. .. .. .. .. .. .. .. : : Cl : : : H3C H : Cl: Cl Cl .. .. .. .. Mechanism of Chlorination of Methane First propagation step: + H3C : H + Second propagation step: + + + + H3C : H
.. .. . . H3C H : Cl: Cl: .. .. .. .. .. .. . . : : : : : Cl: Cl Cl Cl H3C H3C .. .. .. .. .. .. .. .. : : Cl : : : H3C H : Cl: Cl Cl .. .. .. .. Almost all of the product is formed by repetitivecycles of the two propagation steps. First propagation step: + H3C : H + Second propagation step: + + + + H3C : H
.. .. . . : : Cl H3C H3C Cl: .. .. Termination Steps • stop chain reaction by consuming free radicals • hardly any product is formed by termination stepbecause concentration of free radicals at anyinstant is extremely low +
Question • The step shown below is a _____________ step of the free-radical chlorination of • chloromethane. • A)initiation • B)propagation • C)chain-terminating • D)bond cleavage
Question • For the free-radical reaction below, light is involved in which of the following reaction • steps? • A)Initiation only • B)Propagation only • C)Termination only • D)Initiation and propagation
Chlorination of Alkanes • can be used to prepare alkyl chlorides from alkanes in which all of the hydrogens are equivalent to one another 420°C CH3CH3 + Cl2 CH3CH2Cl + HCl (78%) h + Cl2 + HCl Cl (73%)
Chlorination of Alkanes Major limitation: Chlorination gives every possible monochloride derived from original carbonskeleton. Not much difference in reactivity ofdifferent hydrogens in molecule.
Example • Chlorination of butane gives a mixture of1-chlorobutane and 2-chlorobutane. (28%) CH3CH2CH2CH2Cl Cl2 CH3CH2CH2CH3 h CH3CHCH2CH3 (72%) Cl
10% 10% 10% 10% 10% 10% 10% 10% 10% 10% Percentage of Product that Results from Substitution of Indicated Hydrogen if Every Collision with Chlorine Atoms is Productive
Percentage of Product that Actually Results from Replacement of Indicated Hydrogen 18% 18% 4.6% 4.6% 4.6% 4.6% 4.6% 4.6% 18% 18%
4.6 4.6 18 4.6 Relative Rates of Hydrogen Atom Abstraction 18% 4.6% • divide by 4.6 = 1 = 3.9 A secondary hydrogen is abstracted 3.9 times faster than a primary hydrogen by a chlorine atom.
CH3 (63%) CH3CCH2Cl CH3 H Cl2 CH3CCH3 h H CH3 CH3CCH3 (37%) Cl • Similarly, chlorination of 2-methylbutane gives a mixture of isobutyl chloride and tert-butyl chloride
Question • How many monochlorination products do you expect to obtain from the chlorination of • 2-methylbutane? • A)two • B)three • C)four • D)five
Percentage of Product that Results from Replacement of Indicated Hydrogen 7.0% 37%
Relative Rates of Hydrogen Atom Abstraction • divide by 7 7.0 37 = 5.3 = 1 7 7 A tertiary hydrogen is abstracted 5.3 times faster than a primary hydrogen by a chlorine atom.
QuestionTrue (A) / False (B) • Hyperconjugationcontributes more to thermodynamic stability than resonance.
QuestionTrue (A) / False (B) • Vinyl free radicals are more thermodynamically stable thanbenzylic and allylic free radicals.
Selectivity of Free-radical Halogenation • R3CH > R2CH2 > RCH3 • chlorination: 5 4 1 • bromination: 1640 82 1 • Chlorination of an alkane gives a mixture of every possible isomer having the same skeletonas the starting alkane. Useful for synthesis only when all hydrogens in a molecule are equivalent. Bromination is highly regioselective for substitution of tertiary hydrogens. Major synthetic application is in synthesis of tertiary alkyl bromides.
Question • How many mono-bromination products are expected from the following reaction? • A. 5 B. 4 C. 3 D. 2 E. 1
Cl Cl2 h Synthetic Application of Chlorination of an Alkane • Chlorination is useful for synthesis only when all of the hydrogens in a molecule are equivalent. (64%)
Question • An alkane with a molecular formula of C8H18 reacts with Cl2 in the presence of light and • heat to give a single monochloride C8H17Cl. What is the most reasonable structure for the starting alkane? • A) CH3CH2CH2CH2CH2CH2CH2CH3 • B) (CH3CH2)2CHCH2CH2CH3 • C) (CH3)2CHCH2CH2CH(CH3)2 • D) (CH3)3CC(CH3)3
Br H CH3CCH2CH2CH3 CH3CCH2CH2CH3 CH3 CH3 Synthetic Application of Bromination of an Alkane Br2 • Bromination is highly selective for substitution of tertiary hydrogens. • Major synthetic application is in synthesis of tertiary alkyl bromides. h (76%)
Question • Which of the following best describes a mechanistic feature of the free-radical bromination (Br2, light) of 2-methylpropane? • A) The initiation step involves cleavage of a C-H bond. • B) The free-radical (CH3)3C· is produced in one propagation step and reacts with Br2 in another. • C) The reaction is characterized by the homolytic cleavage of the C-Br bond. • D) The reaction is concerted; i.e., it occurs in a single step.
Question • Which reaction has a faster rate? • Which product is kinetically favored? • A. I) and I) B. II) and II) C. I) and II) D. II) and I) I) II)
Question • Which reaction has a propagation step that is endothermic?Which reaction is more regioselective? • A. I) and I) B. II) and II) C. I) and II) D. II) and I) I) II)
Stereochemistry • Three mono-substituted isomers form in the halogenation of butane. The products are optically inactive.
Question • True (A) / False (B) • Bromination of optically active 3-methylhexane produces only (S)-3-bromo-3-methylhexane.
Question • How many products (including stereoisomers) are expected in the following halogenation? • A. 5 B. 4 C. 3 D. 2 E. 1
Allylic/BenzylicBromination • Resonance and regioselectivity: Br- A mixture is obtained that includes the di-brominated product. Di-bromination can be avoided using a specialized reagent: N-bromosuccinimide (NBS)
Allylic/BenzylicBromination • N-bromosuccinimide (NBS)
Question What is the major product of the following reaction?
Halogenated Marine Natural Products (A) Barbamide, a cyanobacterial peptide containing a trichloromethyl group and (B) dysidenin, a barbamide-related compound isolated from a sponge-cyanobacterial association
Radical Polymerization • Free radical conditions are frequently used to form polymers. • Recall that a polymerization process joins together many small units called monomers in a long chain.
Radical Polymerization • Radical polymerizations commonly proceed through a chain reaction mechanism.