600 likes | 619 Views
NaCl, salt. Compounds & Molecules. Ethanol, C 2 H 6 O. Buckyball, C 60. Compounds & Molecules. COMPOUNDS are a combination of 2 or more elements in definite ratios by mass. The character of each element is lost when forming a compound.
E N D
NaCl, salt Compounds & Molecules Ethanol, C2H6O Buckyball, C60
Compounds & Molecules • COMPOUNDSare a combination of 2 or more elements in definite ratios by mass. • The character of each element is lost when forming a compound. • MOLECULESare the smallest unit of a compound that retains the characteristics of the compound.
MOLECULAR FORMULAS • Formula for glycine is C2H5NO2 • In one molecule there are • 2 C atoms • 5 H atoms • 1 N atom • 2 O atoms
WRITING FORMULAS • Can also write glycine formula as • H2NCH2COOH to show atom ordering • or in the form of a structural formula
MOLECULAR MODELING Drawing of glycine Ball & stick Space-filling
Resources for Molecular Modeling • Modeling software on the General Chemistry Interactive CD-ROM • CAChe — see the folder labeled CAChe on the CD-ROM • Rasmol
MOLECULAR WEIGHT AND MOLAR MASS Molecular weight = sum of the atomic weights of all atoms in the molecule. Molar mass = molecular weight in grams
What is the molar mass of ethanol, C2H6O? 1 mol contains 2 mol C (12.01 g C/1 mol) = 24.02 g C 6 mol H (1.01 g H/1 mol) = 6.06 g H 1 mol O (16.00 g O/1 mol) = 16.00 g O TOTAL = molar mass = 46.08 g/mol
Tylenol • Formula = • Molar mass = C8H9NO2 151.2 g/mol
How many moles of alcohol are there in a “standard” can of beer if there are 21.3 g of C2H6O? (a) Molar mass of C2H6O = 46.08 g/mol (b) Calc. moles of alcohol
How many moleculesof alcohol are there in a “standard” can of beer if there are 21.3 g of C2H6O? = 2.78 x 1023 molecules We know there are 0.462 mol of C2H6O.
How many atoms of Care there in a “standard” can of beer if there are 21.3 g of C2H6O? = 5.57 x 1023 C atoms There are 2.78 x 1023 molecules. Each molecule contains 2 C atoms. Therefore, the number of C atoms is
Molecular & Ionic Compounds NaCl Heme
ELEMENTS THAT EXIST AS MOLECULES See SCREEN 3.2 on the CD-ROM Allotropes of C
ELEMENTS THAT EXIST AS POLYATOMIC MOLECULES S8 sulfur molecules White P4 and polymeric red phosphorus
IONS AND IONIC COMPOUNDSsee Screen 3.5 • IONSare atoms or groups of atoms with a positive or negative charge. • Taking away an electron from an atom gives a CATION with a positive charge • Adding an electron to an atom gives an ANION with a negative charge.
Forming Cations & Anions A CATION forms when an atom loses one or more electrons. An ANION forms when an atom gains one or more electrons F + e- --> F- Mg --> Mg2+ + 2 e-
PREDICTING ION CHARGES • See CD-ROM Screen 3.5 and book Figure 3.7 In general • metals (Mg) lose electrons ---> cations • nonmetals (F) gain electrons ---> anions
-4 -3 -2 -1 +1 +2 Charges on Common Ions +3 By losing or gaining e-, atom has same number of e-’s as nearest Group 8A atom.
METALS M ---> n e- + Mn+ where n = periodic group Na+ sodium ion Mg2+ magnesium ion Al3+ aluminum ion Transition metals --> M2+ or M3+ are common Fe2+ iron(II) ion Fe3+ iron(III) ion
Group 5A Group 6A Group 7A Group 4A C4-,carbide NONMETALS NONMETAL + n e- ------> Xn- where n = 8 - Group no. N3-, nitride O2-, oxide F-, fluoride S2-, sulfide Cl-, chloride Br-, bromide I-, iodide
Ion Formation Reaction of aluminum and bromine
POLYATOMIC IONSCD Screen 3.6 Groups of atoms with a charge. MEMORIZEthe names and formulas in Table 3.1, page 89.
Polyatomic Ions NO3- nitrate ion HNO3 nitric acid
Polyatomic Ions NH4+ ammonium ion One of the few common polyatomic cations
Polyatomic Ions CO32- carbonate ion HCO3- bicarbonate ion hydrogen carbonate
Polyatomic Ions PO43- phosphate ion CH3CO2- acetate ion
Polyatomic Ions SO42- sulfate ion SO32- sulfite ion
Polyatomic Ions NO3- nitrate ion NO2- nitrite ion
COMPOUNDS FORMED FROM IONS CATION + ANION ---> COMPOUND Na+ + Cl- --> NaCl A neutral compd. requires equal number of + and - charges.
NH4+ Cl- IONIC COMPOUNDS ammonium chloride, NH4Cl
Some Ionic Compounds Ca2+ + 2 F- ---> CaF2 Mg2+ + NO3- ----> Mg(NO3)2 magnesiumnitrate Fe2+ + PO43- ----> Fe3(PO4)2 iron(II) phosphate (See CD, Screen 3.11 for naming practice) calcium fluoride
Properties of Ionic CompoundsForming NaCl from Na and Cl2 • A metal atom can transfer an electron to a nonmetal. • The resulting cation and anion are attracted to each other by electrostatic forces.
Electrostatic Forces The oppositely charged ions in ionic compounds are attracted to one another by ELECTROSTATIC FORCES. These forces are governed by COULOMB’S LAW.
Electrostatic Forces COULOMB’S LAW As ion charge increases, the attractive force _______________. As the distance between ions increases, the attractive force ________________. This idea is important and will come up many times in future discussions!
Importance of Coulomb’s Law NaCl, Na+ and Cl-, m.p. 804 oC MgO, Mg2+ and O2- m.p. 2800 oC
Molecular CompoundsCompounds without Ions CO2 Carbon dioxide BCl3 boron trichloride CH4 methane
Naming Molecular Compounds All are formed from two or more nonmetals. CO2 Carbon dioxide Ionic compounds generally involve a metal and nonmetal (NaCl) BCl3boron trichloride CH4 methane
Empirical & Molecular Formulas A pure compound always consists of the same elements combined in the same proportions by weight. Therefore, we can express molecular composition as PERCENT BY WEIGHT Ethanol, C2H6O 52.13% C 13.15% H 34.72% O
Structure of NO2 Percent Composition Consider some of the family of nitrogen-oxygen compounds: NO2, nitrogen dioxide and closely related, NO, nitrogen monoxide (or nitric oxide) Chemistry of NO, nitrogen monoxide
Percent Composition Consider NO2, Molar mass = ? What is the weight percent of N and of O? What are the weight percentages of N and O in NO?
How to Determine a Formula? Mass spectrometer
Mass Spectrum of Ethanol Mass Spectrum of Ethanol (from the NIST site) CH2O+ 31 CH3CH2O+ 45 CH3CH2OH+ 46
Determining Formulas In chemical analysis we determine the % by weight of each element in a given amount of pure compound and derive the EMPIRICALor SIMPLESTformula. PROBLEM: A compound of B and H is 81.10% B. What is its empirical formula?