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Force on a current carrying conductor. Submitted to: Dr. Tariq Bhatti Submmited by: Ahmad Mushtaq Roll No.: 07-45 Program BS-it Session 2007-11. Department of Computer Science Bahauddin Zakariya University, Multan. How to find force on a current carrying conductor ?.
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Force on a current carrying conductor Submitted to: Dr. Tariq Bhatti Submmited by: Ahmad Mushtaq Roll No.: 07-45 Program BS-it Session 2007-11 Department of Computer Science Bahauddin Zakariya University, Multan
How to find force on a current carrying conductor ? • Equation for finding force on a moving particle can be used to find force on a current carrying conductor. Current Source: www.boredofstudies.org
Substituting • We know that, F = qv x B Substituting, Velocity v = vd Total Charge q = Nq = nAlq Hence, F = nAlqvdx B . . . N = nAl
Relation of Force with Length & Current F = nAlqvdx B • ‘l’ has the same direction as ‘vd’ we can write: lvd = lud • Substituting: F = nAlqudx B
Relation of Force with Length & Current • We know that, Current Density j = nqud and Current I = jA = nqud A F = nAlqudx B • Hence, F = Il x B
Magnitude of Magnetic Force F = Il x B sin0 • Where ‘O’ is angle b/w directions of ‘l ’ & ‘B’. Direction of the force can be determined by fleming’s left hand rule Source:http://physics503.one-school.net
What if conductor is not straight? • Here we use, dF=IdlxB • For sum, F= ∫IdlxB
Conclusion: The magnitude of the force on length l of the conductor is proportional to the length as well as to the current in the conductor and to the magnitude of the magnetic field.