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From last time(s)…. Gauss’ law Conductors in electrostatic equilibrium. Finish conductors in electrostatic equilibrium Work, energy, and (electric) potential Electric potential and charge Electric potential and electric field. Today…. Exam 1 Scores. Class average = 76%. (This is 84/110).
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From last time(s)… • Gauss’ law • Conductors in electrostatic equilibrium • Finish conductors in electrostatic equilibrium • Work, energy, and (electric) potential • Electric potential and charge • Electric potential and electric field. Today…
Exam 1 Scores Class average = 76% (This is 84/110) Your score postedat learn@uw Curve: B / BC boundary is 76%
Conductor in Electrostatic Equilibrium In a conductor in electrostatic equilibrium there is no net motion of charge • E=0 everywhere inside the conductor Ein • Conductor slab in an external field E: if E 0 free electrons would be accelerated • These electrons would not be in equilibrium • When the external field is applied, the electrons redistribute until they generate a field in the conductor that exactly cancels the applied field. Etot =0 Etot = E+Ein= 0
Conductors: charge on surface only • Choose a gaussian surface inside (as close to the surface as desired) • There is no net flux through the gaussian surface (since E=0) • Any net charge must reside on the surface (cannot be inside!) E=0
this surface this surface this surface E-Field Magnitude and Direction E-field always surface: • Parallel component of E would put force on charges • Charges would accelerate • This is not equilibrium • Apply Gauss’s law at surface
- - + + - + - + - - + + Summary of conductors • everywhere inside a conductor • Charge in conductor is only on the surface • surface of conductor
+ + Electric forces, work, and energy • Consider positive particle charge q, mass m at rest in uniform electric field E • Force on particle from field • Opposite force on particle from hand • Let particle go - it moves a distance d • How much work was done on particle? • How fast is particle moving? v>0 v=0
In our case, Work and kinetic energy • Work-energy theorem: • Change in kinetic energy of isolated particle = work done • Total work
+ Electric forces, work, and energy • Same particle, but don’t let go • How much force does hand apply? • Move particle distance d, keep speed ~0 • How much work is done by hand on particle? • What is change in K.E. of particle? Conservation of energy? W stored in field as potential energy +
Work done on system Change in electric potential energy Change in kinetic energy Work, KE, and potential energy • If particle is not isolated, Works for constant electric field if • Only electric potential energy difference • Sometimes a reference point is chosen • E.g. • Then for uniform electric field
Electric potential V • Electric potential difference V is the electric potential energy / unit charge = U/q • For uniform electric field, This is only valid for a uniform electric field
Quick Quiz Two points in space A and B have electric potential VA=20 volts and VB=100 volts. How much work does it take to move a +100µC charge from A to B? +2 mJ -20 mJ +8 mJ +100 mJ -100 mJ
+ Check for uniform E-field Push particle against E-field, or across E-field Which requires work? Constant electric potential in this direction + Increasing electric potential in this direction Decreasing electric potential in this direction
Potential from electric field • Potential changes largest in direction of E-field. • Smallest (zero) perpendicular to E-field V=Vo
Electric potential: general • Electric field usually created by some charge distribution. • V(r) is electric potential of that charge distribution • V has units of Joules / Coulomb = Volts Electric potential energy difference U proportional to charge q that work is done on Electric potential difference Depends only on charges that create E-fields
for point charge Electric potential of point charge • Electric field from point charge Q is • What is the electric potential difference? Define Then
Distance from ‘source’ charge +Q Electric Potential of point charge • Potential from a point charge • Every point in space has a numerical value for the electric potential y +Q x
B Electric potential energy=qoV A qo > 0 Potential energy, forces, work • U=qoV • Point B has greater potential energy than point A • Means that work must be done to move the test charge qo from A to B. • This is exactly the work to overcome the Coulomb repulsive force. Work done = qoVB-qoVA = Differential form:
V(r) from multiple charges • Work done to move single charge near charge distribution. • Other charges provide the force, q is charge of interest. q1 q2 q q3 Superposition of individual electric potentials
x=-a x=+a +Q -Q Quick Quiz 1 • At what point is the electric potential zero for this electric dipole? A B A B Both A and B Neither of them
x=-a x=+a +Q -Q Superposition: the dipole electric potential • Superposition of • potential from +Q • potential from -Q + = V in plane