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Exploring the concepts of force, time, mass, and change in velocity with examples and calculations that showcase their relationship. Learn how to calculate force, time, and velocity changes in practical scenarios.
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Force, time, mass, and velocity • Contents: • New concept • Example • Whiteboards: 1,2,3,4
Force, time, mass, and velocity • So far we have: p = mv, • so p = mv • And Impulse = p = Ft • Impulse = F t = mv • F = Force (N) • t = Elapsed time (s) • m = Mass (kg) • v = Change in velocity (m/s)
Example: A car going 34 m/s hits a .0025 kg bug. The collision lasts .020 seconds. What force does the windshield exert on the bug? • F t = mv • (F )(.02 s) = (.0025 kg)(34 m/s) • F = (.0025 kg)(34 m/s)/(.02 s) • F = 4.25 N (units?)
Whiteboards Ft = mv 1 | 2 | 3 | 4
What force for 10. seconds makes a 2.0 kg rocket speed up to 75 m/s from rest? 15 N (m)(v) = (F )( t) (2.0 kg)(75 m/s) = (F )(10 s) F = (2.0 kg)(75 m/s)/(10 s) = 15 N
A baseball bat exerts a force of 200. N on a .50 kg ball for .10 seconds. What is the ball’s change in velocity? 40. m/s (m)(v) = (F )( t) (.50 kg)(v) = (200. N )(.10 s) v = (200. N )(.10 s)/(.50 kg) = 40. m/s
Jolene exerts a 50. N force for 3.00 seconds on a stage set. It speeds up from rest to .25 m/s. What is the mass of the set? 6.0x102 kg (m)(v) = (F )( t) (m)(.25 m/s) = (50. N )(3.0 s) m = (50. N )(3.0 s)/(.25 m/s) = 600 kg = 6.0 x102 kg
For what time must a 517 kg spaceship fire its retro rockets to slow it from 576 m/s to 312 m/s. The rockets generate 35,000 N of thrust. 3.9 seconds v = 576 m/s - 312 m/s = 264 m/s (517 kg)(264 m/s) = (35,000 N )( t) t = (517 kg)(264 m/s)/(35,000 N ) = 3.9 seconds
One last thing: • If we re-arrange things in • m v = F t • t t • Now • v = acceleration, so • t • Which gives us • F = m v = ma = p • t t