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Chapter 11A – Angular Motion

Chapter 11A – Angular Motion. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University. © 2007.

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Chapter 11A – Angular Motion

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  1. Chapter 11A – Angular Motion A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University © 2007

  2. WIND TURBINES such as these can generate significant energy in a way that is environ-mentally friendly and renewable. The concepts of rotational acceleration, angular velocity, angular displacement, rotational inertia, and other topics discussed in this chapter are useful in describing the operation of wind turbines.

  3. Objectives: After completing this module, you should be able to: • Define and apply concepts of angular displacement, velocity, and acceleration. • Draw analogies relating rotational-motion parameters (, , ) to linear (x, v, a) and solve rotational problems. • Write and apply relationships between linear and angular parameters.

  4. Objectives: (Continued) • Define moment of inertia and apply it for several regular objects in rotation. • Apply the following concepts to rotation: 1. Rotational work, energy, and power 2. Rotational kinetic energy and momentum 3. Conservation of angular momentum

  5. A Rotational Displacement,  Consider a disk that rotates from A to B: B Angular displacement q:  Measured in revolutions, degrees, or radians. 1 rev=360 0= 2rad The best measure for rotation of rigid bodies is the radian.

  6. s R R 1 rad = = 57.30 Definition of the Radian One radian is the angle subtended at the center of a circle by an arc length sequal to the radius R of the circle.

  7. R h = 20 m Example 1:A rope is wrapped many times around a drum of radius 50 cm. How many revolutions of the drum are required to raise a bucket to a height of 20 m? q= 40 rad Now, 1 rev = 2p rad q = 6.37 rev

  8. Example 2: A bicycle tire has a radius of 25 cm. If the wheel makes 400 rev, how far will the bike have traveled? q = 2513 rad s = q R = 2513rad (0.25 m) s = 628 m

  9. q t w =Angular velocity in rad/s. Angular Velocity Angular velocity,w, is the rate of change in angular displacement. (radians per second.) Angular velocity can also be given as the frequency of revolution, f (rev/s or rpm): w =2pfAngular frequency f(rev/s).

  10. R q t 50 rad 5 s w = = h = 10 m Example 3:A rope is wrapped many times around a drum of radius 20 cm. What is the angular velocity of the drum if it lifts the bucket to 10 m in 5 s? q= 50 rad w = 10.0 rad/s

  11. R h = 10 m Example 4:In the previous example, what is the frequency of revolution for the drum? Recall that w = 10.0 rad/s. Or, since 60 s = 1 min: f = 95.5 rpm

  12. Angular Acceleration Angular acceleration is the rate of change in angular velocity. (Radians per sec per sec.) The angular acceleration can also be found from the change in frequency, as follows:

  13. 0 R h = 20 m Example 5:The block is lifted from rest until the angular velocity of the drum is 16rad/s after a time of 4 s. What is the average angular acceleration? a = 4.00 rad/s2

  14. v = w R Angular and Linear Speed From the definition of angular displacement: s = q R Linear vs. angular displacement Linear speed = angular speed x radius

  15. a = aR Angular and Linear Acceleration: From the velocity relationship we have: v = wR Linear vs. angular velocity Linear accel. = angular accel. x radius

  16. R1 A B R2 Examples: Consider flat rotating disk: wo= 0; wf = 20 rad/s t = 4 s R1 = 20 cm R2 = 40 cm What is final linear speed at points A and B? vAf = wAf R1= (20 rad/s)(0.2 m); vAf= 4m/s vAf = wBf R1= (20 rad/s)(0.4 m); vBf= 8m/s

  17. Consider flat rotating disk: R1 A wo= 0; wf = 20 rad/s t = 4 s B R2 R1 = 20 cm R2 = 40 cm Acceleration Example What is the average angular and linear acceleration at B? a = 5.00 rad/s2 a= 2.00 m/s2 a = aR = (5 rad/s2)(0.4 m)

  18. Recall the definition of linear acceleration a from kinematics. becomes Angular acceleration is the time rate of change in angular velocity. Angular vs. Linear Parameters But, a = aR and v = wR, so that we may write:

  19. A Comparison: Linear vs. Angular

  20. Select Equation: 100 m vf= 0 m/s vo= 20 m/s -(20 m/s)2 2(100 m) 0 - vo2 2s a = = Linear Example:A car traveling initially at 20 m/s comes to a stop in a distance of 100 m. What was the acceleration? a = -2.00 m/s2

  21. R Select Equation: -(62.8 rad/s)2 2(314 rad) 0 - wo2 2q a = = Angular analogy:A disk (R = 50 cm), rotating at 600 rev/min comes to a stop after making 50 rev. What is the acceleration? wo = 600 rpm wf = 0 rpm q = 50rev 50 rev = 314 rad a= -6.29 m/s2

  22. Problem Solving Strategy: • Draw and label sketch of problem. • Indicate + direction of rotation. • List givens and state what is to be found. Given: ____, _____, _____ (q,wo,wf,a,t) Find: ____, _____ • Select equation containing one and not the other of the unknown quantities, and solve for the unknown.

  23. +a R Example 6:A drum is rotating clockwise initially at 100 rpm and undergoes a constant counterclockwise acceleration of 3 rad/s2 for 2 s. What is the angular displacement? Given:wo= -100 rpm; t = 2 sa= +2 rad/s2 q = -14.9 rad q = -20.9 rad + 6 rad Net displacement is clockwise (-)

  24. Summary of Formulas for Rotation

  25. CONCLUSION: Chapter 11A Angular Motion

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