'Accepting states' presentation slideshows

Antichain Algorithms for Finite Automata

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Lecture Four: Nondeterministic Finite Automata

Lecture Four: Nondeterministic Finite Automata. Amjad Ali. A DFA has exactly one transition from every state on every symbol in the alphabet. By relaxing this requirement we get a related but more flexible kind of automaton: the nondeterministic finite automaton or NFA.

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CS323: Theory of Computation

Lecture 11 Practice and Closure Operations. CS323: Theory of Computation. Dr. Mohammad Nassef Department of Computer Science Faculty of Computers and Information Cairo University Egypt. Syllabus and Terminologies. Regular Languages .. Regular Sets REs (Regular Expressions)

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Finite State Machines

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LTL Model Checking

LTL Model Checking. Flavio Lerda. LTL Model Checking. LTL Subset of CTL* of the form: A f where f is a path formula LTL model checking Model checking of a property expressed as an LTL formula: Given a model M and an initial state s 0 : M,s 0 ? A f. LTL Formulas. Subset of CTL*

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CSCI 3130: Automata theory and formal languages

Fall 2011. The Chinese University of Hong Kong. CSCI 3130: Automata theory and formal languages. NFA to DFA conversion and regular expressions. Andrej Bogdanov http://www.cse.cuhk.edu.hk/~andrejb/csc3130. NFAs are as powerful as DFAs. An NFA can do everything a DFA can do

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Nondeterminism-NFA

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Generalized Buchi automaton

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MA/CSSE 474

MA/CSSE 474. Minimizing DFSMs Proof of NDFSM ?DFSM ALGORITHM (If there is time left). Theory of Computation. Your Questions?. HW4 or HW5 problems Tuesday's Exam Anything else. Previous class days' material Reading Assignments. Computer science

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Generalized Buchi automaton

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Computability

Computability. Catch up last lecture. Turing machines. Variations Homework: Check out videos. Describe certain TMs. What next?. It wasn't done this way, but, how can we define a machine more powerful than PDA (which was more powerful than FSM)

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SI-DFA: Sub-expression Integrated Deterministic Finite Automata for Deep Packet Inspection

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Homework #2 Solutions

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The time complexity for e-closure(T). Push all states in T onto stack;

The time complexity for e-closure(T). Push all states in T onto stack; initialize e-closure(T) to T; while stack is not empty do begin pop t, the top element, off the stack for each state u with an edge from t to u labeled e do if u is not in e-closure(T) do begin

87 views • 8 slides