'Mod 5' presentation slideshows

Lecture 7

1.08k views • 92 slides

Lecture 7

929 views • 92 slides

??????????? 6 ?

??????????? 6 ?. ???? ?????? kurosawa@mx.ibaraki.ac.jp. RSA ?? ?? ????????? ElGamal ?? ?? ??????????. RSA ?? ?? ????????? ElGamal ?? ?? ?????????? ?????? x=3. ??????. y=a x mod p (= ??? ???? x ??????????? p=1024 ??????? 10 ??. mod 5 ????. ????????. 2 ???? 4. mod 5 ????.

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890 views • 64 slides

Visual Basic 2

Visual Basic 2. Manipulating data types Exceptions Tooltips. Index of projects in this ppt. Digitizer (digit extractor) Numeric operator practice form Exception handling in operator form Book order form The calculator (GUI only at this point). Some asides and remarks.

706 views • 63 slides

?????????? (A Study on Cryptography and Its Applications ) Min-Shiang Hwang ( ??? )

?????????? (A Study on Cryptography and Its Applications ) Min-Shiang Hwang ( ??? ) Department of Management Information Systems National Chung Hsing University Email: mshwang@nchu.edu.tw http://isrc.nchu.edu.tw/. ???? - ???? ??. ???? ??. ? ???????? ? ?????????

630 views • 52 slides

Erik Jonsson School of Engineering and Computer Science

411 views • 32 slides

Evaluation/Interpolation

Evaluation/Interpolation. Lecture 8. Backtrack from the GCD ideas a bit. We can do some operations faster in a simpler domain, even if we need to do them repeatedly. GCD(F(x,y,z),G(x,y,z)). H(x,y,z). H p (x,y,z). GCD(F p (x,y,z),G p (x,y,z)). GCD(F p (x,0,0),G p (x,0,0)). H p (x,0,0).

422 views • 31 slides

Erik Jonsson School of Engineering and Computer Science

417 views • 31 slides

Evaluation/Interpolation

Evaluation/Interpolation. Lecture 8. Backtrack from the GCD ideas a bit. We can do some operations faster in a simpler domain, even if we need to do them repeatedly. GCD(F(x,y,z),G(x,y,z)). H(x,y,z). H p (x,y,z). GCD(F p (x,y,z),G p (x,y,z)). GCD(F p (x,0,0),G p (x,0,0)). H p (x,0,0).

325 views • 31 slides

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Module 4 and 5 Regional Airlines - jetBlue

Module 4 and 5 Regional Airlines - jetBlue. Michelle Kelly. Mod 4-Calculation of 2013 Values. Compared Q3 2013 to Q3 2012 to get growth rate Applied to December 31, 2012 numbers to compute 2013 values Exception: Operating Expenses (% of revenue). Mod 4-Calculation of 2013 Values.

350 views • 23 slides

Section 13.3

Math in Our World. Section 13.3. Modular Systems. Learning Objectives. Find congruent numbers in modular systems. Perform addition, subtraction, and multiplication in modular systems. Solve congruences in modular systems. Modular Systems.

453 views • 19 slides

MUNCHING SQUARES

MUNCHING SQUARES. A plot of the cells on a grid satisfying bitwise XOR (x, y) < n for consecutive values of n. n = 1, 2, .... grid size It is thought that it was discovered by Jackson Wright on the RLE PDP-1 around 1962.

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Elliptic Curve Cryptography ( ECC )

Elliptic Curve Cryptography ( ECC ). Mustafa Demirhan Bhaskar Anepu Ajit Kunjal. Contents. Introduction Addition Law Elliptic Curves Mod n Encryption Example Decryption Example General Diffie-Hellman Key Exchange Scheme Diffie Hellman Method with Elliptic Curves Conclusions.

737 views • 18 slides

The Dining Philosophers Problem

The Dining Philosophers Problem. The Dining Philosophers. Philosopher (int i) { while (TRUE) {// Think (wait for forks) then Eat P (fork[i]); // test left fork P (fork[(i+1) mod 5]); // test right fork eat(); V (fork[(i+1) mod 5]); V (fork[i]); } }

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National Advocacy Qualification Award project

241 views • 9 slides

The Dining Philosophers Problem

The Dining Philosophers Problem. The Dining Philosophers. Philosopher (int i) { while (TRUE) {// Think (wait for spoons) then Eat P (spoon[i]); // test left spoon P (spoon[(i+1) mod 5]); // test right spoon eat(); V (spoon[(i+1) mod 5]); V (spoon[i]); }

124 views • 9 slides