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dBm

For ‘Rule of 10s and 3s Example 2’ you have a wireless bridge generating a 100 mW signal. The antenna cable and connectors create 3 dB of signal loss, and the antenna provides 10 dBi of gain. +. 3. 2. *. -. ÷. 10. 10. dBm. mW. 0. 1. Start off with the template.

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dBm

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  1. For ‘Rule of 10s and 3s Example 2’ you have a wireless bridge generating a 100 mW signal. The antenna cable and connectors create 3 dB of signal loss, and the antenna provides 10 dBi of gain.

  2. + 3 2 * - ÷ 10 10 dBm mW 0 1 Start off with the template. Rule of 10s and 3s Example 2: 100 mW bridge, 3 dB cable loss, 10 dBi antenna gain

  3. + 3 2 * - ÷ 10 10 dBm mW 0 1 =10 =100 *10 *10 You determine that by multiplying 1 by 10 twice, you will get 100 mW. Calculate the new mW value by performing both of these multiplications, and enter the new values in the mW column. You need to determine if by using * and ÷ and 2 and 10, you can change from 1 to 100 mW. Rule of 10s and 3s Example 2: 100 mW bridge, 3 dB cable loss, 10 dBi antenna gain

  4. + 3 2 * - ÷ 10 10 dBm mW +10 +10 0 =10 =20 1 =10 =100 *10 *10 Remember that whatever you do to one side, you must do the correlative mathematics on the other side. Since you multiplied on the right side, you must add on the left. And since you multiplied by 10 twice on the right, you must add 10 twice on the left. Rule of 10s and 3s Example 2: 100 mW bridge, 3 dB cable loss, 10 dBi antenna gain

  5. + 3 2 * - ÷ 10 10 dBm mW +10 +10 -3 0 =10 =20 =17 1 =10 =100 *10 *10 Subtract 3 for the cable loss. Rule of 10s and 3s Example 2: 100 mW bridge, 3 dB cable loss, 10 dBi antenna gain

  6. + 3 2 * - ÷ 10 10 dBm mW +10 +10 -3 0 =10 =20 =17 1 =10 =100 =50 *10 *10 ÷2 Again, whatever you do to one side, you must do the correlative mathematics on the other side. Since you subtracted on the left, you must divide on the right. And since you subtracted 3 on the left, you must divide by 2 on the right. So the IR is either 17 dBm or 50 mW. Rule of 10s and 3s Example 2: 100 mW bridge, 3 dB cable loss, 10 dBi antenna gain

  7. + 3 2 * - ÷ 10 10 dBm mW +10 +10 -3 +10 0 10 20 17 =27 1 10 100 50 =500 *10 *10 ÷2 *10 All that’s left is to increase the dBm side by the 10 dBi of the antenna. When you do, you must perform the correlative *10 to the mW side. Rule of 10s and 3s Example 2: 100 mW bridge, 3 dB cable loss, 10 dBi antenna gain

  8. + 3 2 * - ÷ 10 10 dBm mW +10 +10 -3 +10 0 10 20 17 27 1 10 100 50 500 *10 *10 ÷2 *10 So you know that the EIRP of this wireless bridge is either 27 dBm or 500 mW. The two columns of numbers are equal. They are just presented using two different units of measurement. Rule of 10s and 3s Example 2: 100 mW bridge, 3 dB cable loss, 10 dBi antenna gain

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