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One Dimensional Motion. Distance. How far something has moved. Distance. Scalar quantity. Displacement. How far something is from its starting position. Displacement. A vector quantity. Time. The interval between two occurrences. Uniform Motion.
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Distance • How far something has moved
Distance • Scalar quantity
Displacement • How far something is from its starting position
Displacement • A vector quantity
Time • The interval between two occurrences
Uniform Motion • Equal displacement occurs during successive equal time intervals
Uniform Motion • Velocity is constant during uniform motion
Slope • Slope = rise/run • Slope = Dy/Dx
Slope • On a distance vs time graph: • Slope = Dd/Dt
Slope • Slope = Dd/Dt • Slope = velocity
Average Velocity • v = Dd/Dt • v = d1 – d0 • t1 – t0
Displacement • d1 = d0 + vt1 • d = d0 + vt
Acceleration a =Dv/Dta =v1- v0t1- t0
Velocity v = v0 + at vf = vi + at
Displacement d = d0 + v0t + ½ at2
Displacement df = di + vit + ½ at2
v2 = v02 + 2 a(d1 – d0) v2 = v02 + 2ad
v = v0 + at d = d0 + v0t + ½ at2 v2 = v02 + 2ad
v = v0 + at vf = vi + at
d = d0 + v0t + ½ at2 df = di + vit + ½ at2
df = di + vit + ½ at2 d = vit + ½ at2
v2 = v02 + 2ad vf2 = vi2 + 2ad
ff = vi + at d = vit + ½ at2 vf2 = vi2+ 2ad
Drill A ball is dropped from 490 m. Calculate its: vf & tair
Determining Instantaneous Velocity • Graph the Dd/Dt data • Draw tangent to point of interest • Determine slope of tangent
a = slope d = xy or vt d = area
a = slope = Dy/Dx = Dv/Dt = 62/5 = 12.4 m/s
Define each of the following • Distance Displacement • Speed Velocity • Acceleration
Draw a position time graph for a person who walks uniformly from the positive side of the origin back thru the origin to the negative side. Repeat for the negative side.
Make the following conversions:a) 10 m/s to km/hrb) 72 mph to m/s 1.6 km/mile
Draw a position time graph of a person who walks one block briskly, waits at a traffic light, walks the next block slowly, waits at another light, then runs the last block.
A car starts 200.0 m west of town, and moves at 15 m/s east.1) write its best equation2) where will the car be at 10 min3) When will the car be in town
A truck starts 400.0 m east of town, and moves at 12 m/s west Find the time & place where the car from the last problem & the truck will be at the same place
A car increases its velocity from 4.0 m/s to 36 m/s over 4.0 s. 1) Calculate the average acceleration