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Let f(x) = ( sqrt(2-x^3 ) - 1) / ( sqrt(6x) - sqrt(6) ) Find : lim f(x) as x --> 1

Let f(x) = ( sqrt(2-x^3 ) - 1) / ( sqrt(6x) - sqrt(6) ) Find : lim f(x) as x --> 1 (use 5 decimals ) ( sqrt(a) means square root of a = a^(1/2) ). find c for continuity Let f(x) = x^2 - c if x=< 5 cx + 12 if x > 5 Find the value of c that make f(x) continuous on (-inf, +inf)

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Let f(x) = ( sqrt(2-x^3 ) - 1) / ( sqrt(6x) - sqrt(6) ) Find : lim f(x) as x --> 1

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  1. Let f(x) = ( sqrt(2-x^3 ) - 1) / ( sqrt(6x) - sqrt(6) ) Find : lim f(x) as x --> 1 (use 5 decimals ) ( sqrt(a) means square root of a = a^(1/2) )

  2. find c for continuity Let f(x) = x^2 - c if x=< 5 cx + 12 if x > 5 Find the value of c that make f(x) continuous on (-inf, +inf) (use 5 decimals ) ( =< means less that or equal) ( inf means infinity)

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