1 / 12

Review for Unit 1 Test

Review for Unit 1 Test. 1 . 1 and 2 are a linear pair . 1 = 5x + 25 2 = 4x + 20 Find m2. 5x + 25 + 4x + 20 = 180. 9x + 45 = 180 9x = 135 x = 15.  2 = 4(15) + 20 = 80 . x + 4y – 15 + 2x + y – 10 = 6x – 5y -3x + 10y = 25. M. Y is the midpoint of RL.

shiloh
Download Presentation

Review for Unit 1 Test

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Review for Unit 1 Test

  2. 1. 1 and 2 are a linear pair.1 = 5x + 252 = 4x + 20 Find m2 5x + 25 + 4x + 20 = 180 9x + 45 = 180 9x = 135 x = 15 2= 4(15) + 20 = 80

  3. x + 4y – 15 + 2x + y – 10 = 6x – 5y -3x + 10y = 25 M Y is the midpoint of RL mEYL = (6x – 5y)Write and solve a system of equations to find the values of x and y. 2. YI bisects LYE R x + 4y – 15 = 2x + y – 10 -x + 3y = 5 Y L 2(x + 4y – 15) = 6x – 5y 2x + 8y – 30 = 6x – 5y -4x + 13y = 30 I E (2x + y – 10) (x + 4y – 15) 2(2x + y – 10) = 6x – 5y 4x + 2y – 20 = 6x – 5y -2x + 7y = 20 x = 25 y = 10

  4. 3. Six times an angle’s supplement is 5 less than the angle. Find the measure of the angle’s supplement. 6(180 – x) = x – 5 1080 – 6x = x – 5 1085 = 7x 155 = x Supplement = 180 – 155 = 25

  5. 4. 1 and 2 form a right angle.1 = 10x + 122 = 3x Find m1 10x + 12 + 3x = 90 13x + 12 = 90 13x = 78 x = 6 1= 10(6) + 12= 72

  6. 5. 1 and 2 are complementary.1 is 15 more than twice 2 Find m2 2 = x; 1 = 90 – x 90 – x = 2x + 15 75 = 3x 25 = x

  7. 6. 1 and 2 are vertical angles.1 = 3x2 – 2x + 62 = x2 – 11x + 2 Find the value of x. 3x2 – 2x + 6 = x2 – 11x + 2 2x2 + 9x + 4 = 0 (2x + 1)(x + 4) = 0 x = -½ x = -4 (both work!)

  8. 7. The sum of an angle’s supplement and its complement is equal to 8 times the angle. Find the measure of the angle. 180 – x + 90 – x = 8x 270 – 2x = 8x 270 = 10x 27 = x

  9. 8. JM intersects GW at point J GJM = 2x + 5MJW = x + 25Draw and label a diagram. G J 2x + 5 W x + 25 M

  10. M Y is the midpoint of RL 9. Can you assume: YI bisects LYE R Y L I E d) R, Y, L are collinear e) Angle LYI = angle EYI a) SO + OU = SU c) Angle LYE is right b) RY = YL f) MY = YI e) Angle LYI = angle MYR d) yes e) yes, b/c you’re told BISECTOR a) yes c) no! b) yes, b/c you’re told MIDPOINT f) no! e) yes, b/c they are vertical angles

  11. 10. Anangle is twice it’s complement. Find the measure of the angle’s supplement. x = 2(90 – x) x = 180 – 2x 3x = 180 x = 60 Supplement = 180 – 60 = 120

  12. 11. Solve the system using either substitution or elimination. 3x + 2y = 11 -6x + y = -32 x = 5 y = -2

More Related