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Measurement Techniques. DC Circuits Feb. 2009. Measurement Techniques DC Circuits . Resistance (R) Ohms, Ω , K Ω , M Ω Voltage (V) Volt, AC, DC, mV, KV Current (I) Amp, mA (milliamps), uA (microamps). Series Circuit RT = R1 + R2 + R3. R T Ω. R T. R1 R2 R3.
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Measurement Techniques DC Circuits Feb. 2009
Measurement Techniques DC Circuits • Resistance (R) • Ohms, Ω, KΩ, MΩ • Voltage (V) • Volt, AC, DC, mV, KV • Current (I) • Amp, mA (milliamps), uA (microamps)
Series Circuit RT = R1 + R2 + R3 RTΩ RT R1 R2 R3 Bread Board Techniques - Series Circuits Resistance Measurement • Measurement must be made without power applied or wired to the circuit. • Individual components must be removed from the circuit to measure the value accurately. Given R1= 100, R2= 4.7K, R3=100K Find RT
Vs 12V VR1 R1 R2 R3 Vs VR2 VR3 Vs = VR1 + VR2 + VR3 Breadboard Techniques - Series Circuit Voltage Measurement • The voltage supplied by the (12V) voltage source is proportionally distributed across each resistor. • The higher the resistor value, the greater the voltage drop • Kirchoffs Law – The sum of the voltage drop across each resistor in the circuit will add up to the source voltage
Vs 12V IT VR1 R1 R2 R3 Vs VR2 VR3 VR1 = IT x R1 VR2 = IT x R2 VR3 = IT x R3 Calculating Voltage Drops RT = R1 + R2 + R3 • Determine total resistance RT • Using Ohms Law calculate total current IT • Using Ohms Law again, calculate the voltage drop across R1, R2, R3 IT = Vs / RT
IR1 IT R1 R2 R3 Vs Vs 12V IR2 IT IT IT IR3 IT = IR1 = IR2 = IR3 IT Bread Board Techniques - Series Circuit Current Measurement • The meter must be configured for current measurement. • The circuit must be “opened” and the meter placed (anywhere) in series. • The same current flows from the voltage source, “through” the meter, each resistor, and then back to the source.
RTΩ RT R1 R2 R3 Bread Board Techniques – Parallel CircuitsResistance • Circuit must be removed from the voltage source • The total resistance is “less than” the smallest resistor value • Avoid finger contact when measuring 1
1 1 1 1 RTΩ Parallel Circuit RT R1 + R2 + R3 = RT R1 R2 R3 Parallel CircuitsCalculating Total Resistance R1//R2//R3 Where R1 is in parallel with R2 which is in parallel with R3
Let Rp = R1 // R2 R1 x R2 R1 + R2 Rp = R1 R2 R3 Now RT = Rp // R3 RT Rp x R3 Rp + R3 RT = Product-Over-Sum Method • Calculate the parallel resistance of any 2 resistors at a time. • First do R1//R2 using the Product-Over-Sum method • Then use the R1/2 resistance in parallel with R3
R1 R2 R3 Parallel Circuits Voltage Measurement The source voltage (Vs) is common to all components in the circuit Vs = VR1 = VR2 = VR3 Vs
I1 I2 I3 IT Parallel Circuits Current Measurement I1 + I2 + I3 Vs R1 R2 R3 I2 + I3 IT= I1 + I2+ I3
IT I1 I2 I3 Vs R1 R 2 R3 Parallel CircuitsCurrent Calculations To measure current the circuit must be broken and the current meter must be placed in series with the component.
Vs 50V R1 150 Ω R2 300 Ω R3 100 Ω Calculating Total Current (IT) • First find total resistance RT 2. Then use Ohm’s Law to find total current Using Product-Over-Sum Method R1//R2 = (150 x 300) / (150 + 300) = 100 ohms Rp//R3 = (100 x 100) / (100 + 100) = 50 ohms Note: when the parallel resistors are equal in value, just divide by the number of R’s 3K//3K = 1.5K 6K//6K//6K = 2K Using Reciprocal Method 1/RT = 1/R1 + 1/R2 + 1/R3 = 1/150 + 1/300 + 1/100 = 0.00666 + 0.00333 + 0.01 = 0.020 RT = 1/ 0.020 = 50 ohms
Vs 50V R1 150 Ω R2 300 Ω R3 100 Ω Total Current IT Vs RT IT = Calculating Total Current (IT) • First find total resistance RT 2. Then use Ohm’s Law to find total current 50 v = -------- = 1 amp 50 Ω The power supply must be capable of supplying at least 1 amp of current
Calculating Branch Currents RT = 50 ohms IT = 1 amp IT I1 I2 I3 Vs 50 V R1=150 R2=300 R3=100 I1 = Vs / R1 = 50/150 = 0.333333 amps I2 = Vs / R2 = 50/300 = 0.166666 amps I3 = Vs / R3 = 50/100 = 0.200000 amps 1.00 amp
Series/Parallel Circuits • There are multiple current paths. • Resistors may be in series or parallel with other resistors. • A node is where three or more paths come together. • The total power is the sum of the resistors’ power.
--/\/\/\/\-- Rs I R E Simple Combo circuit Reduce the parallel connection to its series equivalent R2 // R3 = Rs Then reduce the series equivalent to the total resistance as seen by the source RT = R1 + Rs
R1 R3 R2 R4 R1 R3 + + R2 R4 RT = R1,2 // R3,4 Reduce & Simplify
100 200 200 400 12 V Analysis of a combo circuit • Calculate • Total current • Branch currents • IR drops Board Solution
100 200 200 400 300 600 12 V 12 V 200 Ώ Reduce & Simplify – find RT RT = R1,2 // R3,4 = 300 // 600 = 200 IT = 12 / 200 = 0.06 amps (60 mA)
R1 R2 R3 R1 R2 R3 RT IT Determining Total Resistance 1 1 1 1 RT = R1 + R2 + R3 V RT RT = V IT
100 200 200 400 300 600 12 V Branch Currents IT Ia Ib Branch Currents Ia = 12 / 300 = 40 mA Ib = 12 / 600 = 20 mA IT = Ia + Ib = 40mA + 20 mA = 60 mA
60 mA 40 mA 20 mA R1 R3 100 200 R2 R4 200 400 12 V IR Drops (voltage across each resistor) VR1 = 40 mA x 100 = 4000 mV = 4V VR2 = 40 mA x 200 = 8000 mV = 8V VR3 = 20 mA x 200 = 4000 mV = 4V VR4 = 20 mA x 400 = 8000 mV = 8V
VA = R2 x Vs R2 + R1 VB = R4 x Vs R4 + R3 R1 R3 R2 R4 AB Vs VAB VA VB Bridge Circuit In a bridge circuit the voltage difference between the two parallel branches is used to indicate the potential difference between the two points. VAB = VA - VB Using the Voltage Divider Formula
Wheatstone Bridge – null balance detector VOUT = 0 volts A balanced bridge can be used to measure an unknown resistance. The Wheatstone bridge can be used as an “ohmmeter” by comparing the unknown resistance value to a known one.
R1 R1 VOUT A B Vs R1 Rs Conditioning circuit for resistive sensors and transducers • VOUT can be used to represent some type of process variable • Temperature • Thermistor • Resistance Temperature Detectors (RTD’s) • Pressure • Strain Gauge • Flow • Anemometer The bridge is often used as a conditioning circuit to convert the output of aresistivetype sensing element into a voltage (mV)