Bit Operations

1. Bit Operations Horton pp. 70 - 76

2. Why we need to work with bits Sometimes one bit is enough to store your data: say the gender of the student (e.g. 0 for men, 1 for women). We don’t have a 1-bit variable type in C++, so for gender, you will have to use a unsigned char or char type variable. But if you need say 8 such 1-bit variables, say to record if the student were present in the times when attendance was taken, then you can actually combine all into one char variable. class student { … private: unsigned char attendance; //now I can fit 8 bits into this, we will see how } In C++, there is special container class, called bitset, that is designed to store bits. But we will not see and use it. And you are not allowed to use it in this course.

3. Packing bits “Packing” 8 1-bit variables into 1 char variable is easy. Say you know that the student were present in the first 3 class and not in the last 5. The variable attendance can be set as: unsigned char attendance = 7; where the lest significant 3 bits represent the first 3 attendances (just a choice, it could be the other way around as well). But in addition to being able to set a variable’s value, we need to be able to handle each bit separately, for which we need bit operators.

4. Hexadecimalliteralsandoutput In C++ a hexadecimal literal (number) is represented by preceeding 0x before the literal. E.g. 0xb4a2 // equivalent to 11x163 + 4x162 + 10x16 + 2 = 46242 (decimal) char ch = 0x7c; // ch contains 124 (7x16+ 12) When you want to display a numeric value in hexadecimal, use hex in cout before the value to be displayed. • This affects all future integer outputs to be displayed in hexadecimal, so if you want to switch back to decimal, use dec later. short nums = -200; cout << "hexadecimal: " << hex << nums << " decimal: " << dec << nums << endl; Output: hexadecimal: ff38 decimal: -200 unsigned int numi = 0xfd04e0e4; cout << "hexadecimal: " << hex << numi << " decimal: " << dec << numi << endl; Output: hexadecimal: fd04e0e4 decimal: 4244955364

5. Bit Operators &Bitwise and | Bitwise or ^Bitwise exclusive or ~ Complement(unary operator, takes only one operand) << shift left >>shift right Do not confuse &&with & || with |

6. Bitwise Operations: AND Take the AND of the two numbers, bit by bit. char x,y,z; x = 0xd5; y = 0x6c; z=x&y; x y z

7. Bitwise AND unsigned char c1, c2, c3; c1 = 0x45; c2 = 0x71; c3 = c1&c2; c1 : 0100 0101 c2 : 0111 0001 c3 : 0100 0001(=0x41 = 4x16+1 = 65 10)

8. Bitwise OR Take the OR of the two numbers, bit by bit. unsigned char c1, c2, c3; c1 = 0x45; c2 = 0x71; c3 = c1 | c2; c1 : 0100 0101 c2 : 0111 0001 c3 : 0111 0101 (=0x75 = 7x16+5 = 11710 )

9. BitwiseXOR Take the Exclusive OR of the two numbers, bit by bit. unsigned char c1, c2, c3; c1 = 0x45; c2 = 0x71; c3 = c1 ^ c2; c1 : 0100 0101 c2 : 0111 0001 c3 : 0011 0100 (=0x34 = 3x16+4 = 5210 )

10. Bitwise Complement Complement operation (~) converts bits with value 0 to 1 and bits with value 1 to 0. unsigned char b1 = 0xc1; // 1100 0001 unsigned char b4 = 0x08; // 0000 1000 b4 = ~b1; // 0011 1110

11. What do these twostatements do? char x = 0xA5; if ( x & 0x08 ) //what does this mean? x = x | 0x02; //what happened to x? These are two of the most important bit operations! We will see more later, but basically you can access a particular bit and you can set a particular bit with these two operations.

12. Logic Operators versus Bitwise Logic Ops. The operators && , || and ! are not bitwise logic operators! • The result of ! , && and|| operations is anintegral data type with the value 0 (every bit is a zero) or 1 (LeastSignificant bit is 1, all the others are 0).

13. Shift Operators Shift operators move bits left or right, discarding bits from one side and filling the other side with 0s. << means shift left >>means shift right Do not confuse with stream operators how many times it is shifted

14. Bit operations: left shift Suppose we want to shift the bits of a number N, k bits to the left • denoted N << k • drop leftmost k bits • append k zeros to the right Ex: y = x << 1; Another example: unsigned char c2 = 0x9C; //10011100 c = c2 << 2 //01110000 x y

15. Bit Shifting as Multiplication Shift left by one position means multiplication by 2 (provided that the result is in the range) - Works as multiplication for both unsigned & 2’s complement numbers - May overflow. • What is the effect of shifting a number left by 3? 0 0 0 1 0 0 1 1 = 19 1 1 1 1 1 1 0 1 = -3 0 0 1 0 0 1 1 0 = 38 1 1 1 1 1 0 1 0 = -6

16. Bit operations: right shift As opposed to left shift, the right shift works differently for signed and unsigned numbers. Suppose we want to shift N by k bits to the right (denoted N >> k): • For unsigned numbers (i.e. unsigned char, unsigned int, etc.): • drop rightmost k bits • append k zerosto the left • For signed numbers (i.e. char, int, etc.): • drop the rightmost k bits • append the sign bit k timesto the left

17. right shift operator:examples Signed (all your variables are signed unless youspecify “unsigned” specifically): • positives: char c = 8; //0000 1000 c = c >> 2 //0000 0010= 210 • negatives: char c = - 8; //1111 1000 in 2s comp. c = c >> 2 //1111 1110 which is -210 • Called arithmetic shift Unsigned: unsigned chard = 0xf8; //1111 1000 (24810) d = d >> 2 //0011 1110 which is 6210 • Called logical shift

18. Logical shift rightfor one bit divides by 2 for unsigned: 0 1 1 1 = 7 1 0 0 0 = 8 0 0 1 1 = 3 0 1 0 0 = 4 Always rounds down! Arithmetic shift rightfor one bit divides by 2 for signed numbers 0 1 1 1 = 7 1 0 0 1 = -7 0 0 1 1 = 3 1 1 0 0 = -4 Always rounds down! CAUTION: Regular division of negative integers rounds down magnitude-wise. E.g. -7/2 is -3 Bit Shifting as Division: summary

19. Bit Shifting as Multiplication & Division Why useful? • Simpler, thus faster, than general multiplication & division Can shift multiple positions at once: • Multiplies or divides by corresponding powerof2. • a << 5 (multiply by 25) • a >> 5 (divide by 25) Remember, when you need to use only positive numbers or you need to manipulate bits, use unsigned numbers.

20. Self-Quiz What are the resulting values of x,y and z? char x,y,z; x = 0x33; x = (x << 3) | 0x0F; y = (x >> 1) & 0x0F; z = x && y;

21. Exampleforsetting, testing, and clearing the bits of bytes const charIO_ERROR = 0x01; //LSB (right-most bit)is 1, othersare 0 const char CHANNEL_DOWN = 0x10; char flags = 0; //if ever CHANNEL_DOWN eventhappens, set itscorresponding bit in theflagsvariable flags = flags | CHANNEL_DOWN; // set the 5th bit . . . //tocheckwhaterrorsmayhavehappened... if ((flags & IO_ERROR ) != 0) // check the 1st bit cout << "I/O error flag is set"; else if ((flags & CHANNEL_DOWN) != 0) // check the 5th bit cout << "Channeldownerror flag is set"; . . . flags = flags & ~IO_ERROR; // clear the ERROR flag This is also called masking

22. Example 2: Attendance unsigned char attendance = 0x00; //let the LSB be for quiz 1, the next one is for quiz 2, . . . //0 means unattended, 1 means attended //there are total of 8 quizzes; initally all unattended unsigned char mask=0x01; //Draft code showing how attendance array may be filled //if attended to quiz 1 attendance = attendance | mask; //if attended quiz 3 mask = mask << 2; // mask becomes 0000 0100 attendance = attendance | mask; . . . //to display attendance information mask=0x01; for (int i=1; i <= 8; i++) { if (attendance & mask) cout << "Student attended quiz number " << i << endl; else cout << "Student missed quiz number " << i << endl; mask = mask << 1; }