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Jeopardy Review for Conic Sections Test

Join Mr. Young Moses Brown School for a fun Jeopardy game to review conic sections. Answer questions, earn points, and win prizes!

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Jeopardy Review for Conic Sections Test

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  1. JEOPARDY!!! HOSTED by Mr. Young Moses Brown School

  2. RULES • Today we are playing Jeopardy to Review for our test tomorrow. • Get in groups of 2-3. You must all sit together. • Each person will get a Marker and a Board. • You will get about 30 seconds-2 minutes to answer each question. • The team who chose the question can get double the points if they get the question right and hit a bball shot. • All other teams can get the normal points for answering the question correctly • Only hold up your answer on your board when you are told. • Have someone record your points on your board. • The top 3 teams will get a prize.

  3. JEOPARDY: Conic Sections Final Jeopardy

  4. Parabolas: 100 Graph the parabola. Find the coordinates of the vertex And the coordinates of the focus. (x – 2)2 = 24(y + 4) ANSWER?

  5. Parabolas: 100 Graph the parabola. Find the coordinates of the vertex And the coordinates of the focus. (x – 2)2 = 24(y + 4) Vertex: (2, -4) Focus: (2, 2) ANSWER?

  6. Parabolas: 200 Write the equation of the parabola with the following features. a.) Focus (-4, 0) and a vertex at (-6,0) ANSWER?

  7. Parabolas: 200 Write the equation of the parabola with the following features. a.) Focus (-4, 0) and a vertex at (-6,0) y2 = 8(x + 6) ANSWER?

  8. Parabolas: 300 A gyms overhead lights have a parabolic reflector that forms a “bowl” which is 20 inches wide from rim to rim and 12 inches deep. If the filament of the light bulb is located at the focus (so that the beams of light reflect in parallel lines making it easier for the driver to see) how far from the vertex of the reflector is the filament? ANSWER?

  9. Parabolas: 300 A gyms overhead lights have a parabolic reflector that forms a “bowl” which is 20 inches wide from rim to rim and 12 inches deep. If the filament of the light bulb is located at the focus (so that the beams of light reflect in parallel lines making it easier for the driver to see) how far from the vertex of the reflector is the filament? 2.083 inches ANSWER?

  10. Parabolas: 400 Find the vertex, focus, and directrix of the conic section x2 + 12x + 3y + 9 = 0 ANSWER?

  11. Parabolas: 400 Find the vertex, focus, and directrix of the conic section x2 + 12x + 3y + 9 = 0 (x + 6)2 = -3(y – 9) Vertex: (-6, 9) Focus: (-6, 8.25) Directrix: y = 9.75 ANSWER?

  12. Ellipses: 100 Graph the ellipse below. Find the Foci and Vertices. DOUBLE JEOPARDY!!! x2 + 16y2 = 64 ANSWER?

  13. Ellipses: 100 Graph the ellipse below. Find the Foci and Vertices. x2 + 16y2 = 64 A = 8 B = 2 Vertices (8, 0) and (-8, 0) Foci: (√68, 0) and (-√68, 0) ANSWER?

  14. Circles: 200 Find the center and radius x2 + y2 + 12y - 25 = 0 ANSWER?

  15. Circles: 200 Find the center and radius x2 + y2 + 12y - 25 = 0 Center: (0, -6) Radius: √61 ANSWER?

  16. Ellipses: 300 The planets move around the sun in elliptical orbits with the sun at one focus. The point in the orbit at which the planet is closest to the sun is called perihelion and the point at which it is farthest is called aphelion. These points are the vertices of the orbit. Mercury’s distance from the sun is 46,000,000km at perihelion and 70,000,000km at aphelion. Find an equation for mercury’s orbit (place the origin at the center of the of the orbit with the sun on the x-axis). ANSWER?

  17. Ellipses: 300 The planets move around the sun in elliptical orbits with the sun at one focus. The point in the orbit at which the planet is closest to the sun is called perihelion and the point at which it is farthest is called aphelion. These points are the vertices of the orbit. Mercury’s distance from the sun is 46,000,000km at perihelion and 70,000,000km at aphelion. Find an equation for mercury’s orbit (place the origin at the center of the of the orbit with the sun on the x-axis). ANSWER?

  18. Circles: 400 Find the solution to the system of equations 4x + 2y = 10 and (x+2)2 + (y – 5)2 = 121 . Find the coordinates of intersection algebraically. ANSWER?

  19. Circles: 400 Find the solution to the system of equations 4x + 2y = 10 and (x+2)2 + (y – 5)2 = 121 . Find the coordinates of intersection algebraically. Solutions: (-5.25, 15.51) (4.45, -3.91) ANSWER?

  20. Hyperbolas: 100 Find an equation for the hyperbola that satisfies the condition. a.) Focus at (+/-5, 0), Vertices ((+/-4, 0) ANSWER?

  21. Hyperbolas: 100 Find an equation for the hyperbola that satisfies the condition. a.) Focus at (+/-5, 0), Vertices ((+/-4, 0) ANSWER?

  22. Hyperbolas: 200 Sketch a graph the hyperbola. Include the center, central box and asymptotes. DOUBLE JEOPARDY!!! ANSWER?

  23. Hyperbolas: 200 Graph the hyperbola. Include the center, central box and equation of the asymptotes. Center: (-2, -3) A=4 B=3 Asymptotes: y = 3/4x – 1.5 y = -3/4x – 4.5 ANSWER?

  24. Hyperbolas: 300 Find the center, foci, vertices and asymptotes. -9x2 + 16y2 – 64y - 80 = 0 ANSWER?

  25. Hyperbolas: 300 Find the center, foci, vertices and asymptotes. -9x2 + 16y2 – 64y - 80 = 0 Center: (0, 2) Vertices: (0, 5) and (0, -1) Foci: (0, 7) and (0, -3) Asymptotes: y = 3/4x + 2 and y = -3/4x + 2 ANSWER?

  26. Hyperbolas: 400 The figure below shows the path of a comet in hyperbolic motion. Find an equation for the path of the comet assuming that the closest that the comet comes to the earth is 20,000 miles and that the path the comet was taking before it neared the solar system is a at a right angle to the path it continues after leaving the solar system. Draw in the figure. ANSWER?

  27. Hyperbolas: 400 The figure below shows the path of a comet. Find an equation for the path of the comet assuming that the closest that the comet comes to the earth is 20,000 miles and that the path the comet was taking before it neared the solar system is a at a right angle to the path it continues after leaving the solar system. ANSWER?

  28. Grab Bag: 100 SAT QUESTION ANSWER?

  29. Grab Bag: 100 SAT QUESTION ANSWER?

  30. Grab Bag: 200 Find the equation of the circle. The center is (-2, 5) and the circle is tangent to the line y = 9. ANSWER?

  31. Grab Bag: 200 Find the equation of the circle. The center is (-2, 5) and the circle is tangent to the line y = 9. (x+2)2 + (y – 5)2 = 16 ANSWER?

  32. Grab Bag: 300 Graph the Conic Section. Include important aspects. 4x2 + y2 = 4y + 12 ANSWER?

  33. Grab Bag: 300 Graph the Conic Section. Include important aspects (center, vertices, foci). 4x2 + y2 = 4y + 12 Ellipse. A= 4 B = 2 Oriented on y axis Center: (0, 2) Vertices: (0, 6) and (0, -2) Foci: (0, 2+√12) and (0, 2-√12) ANSWER?

  34. Grab Bag: 400 The circle is tangent to the line x = -2 and has x-intercepts at -1 and 7. Find where this circle intersects the line y = 2x - 4 ANSWER?

  35. Grab Bag: 400 The circle is tangent to the line x = -2 and has x-intercepts at -1 and 7. Find where this circle intersects the line y = 2x - 4 ANSWER?

  36. FINAL JEOPARDY !!!! • Graph the following Function on the graph and its inverse? • F(x) = 2x + 3 2. How are the function and the inverse related? ANSWER?

  37. FINAL JEOPARDY !!!! • Graph the following Function on the graph and its inverse? • F(x) = 2x + 3 2. How are the function and the inverse related? The graph is reflected over y = x. ANSWER?

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