1 / 15

Solubility Lesson 6 Separating Ions

Solubility Lesson 6 Separating Ions. Positive ions react with negative ions to give a precipitate if they have low solubility. A precipitate can be separated from a solution by filtration . The precipitate will be on the filter paper while the soluble ions will go through.

smithjack
Download Presentation

Solubility Lesson 6 Separating Ions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Solubility Lesson 6 Separating Ions

  2. Positive ions react with negative ions to give a precipitate if they have low solubility. A precipitate can be separated from a solution by filtration. The precipitate will be on the filter paper while the soluble ions will go through. To separate ions one ion must be low solubility and all others high.

  3. Separating Positive Ions 1. Separate Ba2+ & Pb2+ Start at the top of page 4 and try Cl- first

  4. Ba2+ 1st add Cl-, it reacts with Pb2+ (low) and not Ba2+(high) 2nd add SO42-, it reacts with Ba2+ (low)

  5. NaCl Cl- Na+ Pb2+ NO3- Ba2+ PbCl2 Filter

  6. Separating Positive Ions 1. Separate Ba2+ & Pb2+ i. Add NaCl Filter out PbCl2(s) Cl-does not exist on its own Add NaCl because it is soluble- always use Na+for negative ions Pb2+ + 2Cl- PbCl2(s) ii. Add Na2SO4 Filter out BaSO4(s) Ba2+ + SO42- BaSO4(s)

  7. Separating Positive Ions 2. Separate Cu2+, Mg2+ & Sr2+

  8. Cu2+ Sr2+ Cu2+ Mg2+ Mg2+ Mg2+ Cu2+

  9. Separating Positive Ions 2. Separate Cu2+, Mg2+ & Sr2+ i. Add Na2SO4 Filter out SrSO4(s) Sr2+ + SO42- SrSO4(s) SO42-does not exist on its own Add Na2SO4 because it is soluble- always use Na+for negative ions ii. Add Na2S Filter out CuS(s) Cu2+ + S2- CuS(s) iii. Add NaOH Filter out Mg(OH)2(s) Mg2+ + 2OH- Mg(OH)2(s)

  10. Separating Negative Ions Remove the lowest negative ionon the chart first by adding a positive cation. 3. Separate Cl- & OH- Look for a cation that is low with OH- (lowest)and high with Cl-.

  11. Ba2+ Look for a cation that is low withwith Cl- Look for a cation that is low with OH- (lowest)and high with Cl-. Ba2+ Remove the lowest negative ion first by adding a positive cation.

  12. Separating Negative Ions 3. Separate Cl- & OH- i.Ba2+works so add Ba(NO3)2and filteroutBa(OH)2(s) Ba2+ + 2OH- Ba(OH)2(s) Ba2+does not exist on its own Add Ba(NO3)2because it is soluble- always use NO3-to pair with positive ions ii.Add Ag+as AgNO3 and filter out AgCl(s) Ag+ + Cl- AgCl(s)

  13. Separating Negative Ions 4. Separate Cl- S2- CO32-

  14. Look for a cation that is low withwith Cl- Look for a cation that is low withS2-and high with Cl- Zn2+ Look for a cation that is low with CO2- and high with Cl- and S2- Ba2+

  15. Separating Negative Ions 4. Separate Cl- S2- CO32- i.Ba2+works so add Ba(NO3)2and filteroutBaCO3(s) Ba2+ + CO32- BaCO3(s) Ba2+does not exist on its own Add Ba(NO3)2because it is soluble- always use NO3-to pair with positive ions ii.Add Zn2+as Zn(NO3)2 and filter out ZnS(s) Zn2+ + S2- ZnS(s) iii. Add Ag+as AgNO3 and filter out AgCl(s) Ag+ + Cl- AgCl(s)

More Related