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Energy and Power Cycle Analysis: Turbines, Compressors, Heat Exchangers

Understand steady-state vs. transient analysis, mass and energy balances, modeling turbines, compressors, heat exchangers. Solve ideal condition system properties, energy rate balances, and power cycles.

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Energy and Power Cycle Analysis: Turbines, Compressors, Heat Exchangers

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  1. Chapter 4 Control Volume Analysis Using Energy (continued)

  2. Learning Outcomes • Distinguish between steady-state and transient analysis, • Distinguishing between mass flow rate and volumetric flow rate. • Apply mass and energy balances to control volumes. • Develop appropriate engineering models to analyze nozzles, turbines, compressors, heat exchangers, throttling devices. • Use property data in control volume analysis appropriately.

  3. netrate at which energy is being transferred out by work at time t netrate of energy transfer into the control volume accompanying mass flow time rate of change of the energy contained within the control volume attime t netrate at which energy is being transferred in by heat transfer attime t Energy Rate Balance

  4. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 2 properties 4 3

  5. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 2 properties 4 3

  6. Turbines • Turbine: a device in which power is developed as a result of a gas or liquid passing through a set of blades attached to a shaft free to rotate.

  7. Eq. 4.20a Turbine Modeling • If the change in kinetic energy of flowing matter is negligible, ½(V12 – V22) drops out. • If the change in potential energy of flowing matter is negligible, g(z1 – z2) drops out. • If the heat transfer with surroundings is negligible, drops out.

  8. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 2 properties Look up state 3 properties in order to determine W of Turbine 4 3

  9. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 2 properties Look up state 3 properties in order to determine W of Turbine 4 3

  10. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 4 properties 4 3

  11. Heat Exchangers • Direct contact: A mixing chamber in which hot and cold streams are mixed directly. • Tube-within-a-tube counterflow: A gas or liquid stream is separated from another gas or liquid by a wall through which energy is conducted. Heat transfer occurs from the hot stream to the cold stream as the streams flow in opposite directions.

  12. 3 4

  13. Q rejected 3 4

  14. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 4 properties Now one can solve for Q rejected 4 3

  15. Compressors and Pumps • Compressors and Pumps: devices in which work is done on the substance flowing through them to change the state of the substance, typically to increase the pressure and/or elevation. • Compressor: substance is gas • Pump: substance is liquid

  16. Eq. 4.20a Compressor and Pump Modeling • If the change in kinetic energy of flowing matter is negligible, ½(V12 – V22) drops out. • If the change in potential energy of flowing matter is negligible, g(z1 – z2) drops out. • If the heat transfer with surroundings is negligible, drops out.

  17. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 1 properties 4 3

  18. Consider a system similar to what the components that we’ve just analyzed in class. 1 2 Assume ideal conditions initially Look up state 1 properties Now one can solve for W pump 4 3

  19. Heat Exchangers – Boilers too Pump State 1 To turbine, state 2

  20. DEcycle = Qcycle – Wcycle (Eq. 2.39) • Since the system returns to its initial state after each cycle, there is no net change in its energy: DEcycle = 0, and the energy balance reduces to give Wcycle = Qin – Qout (Eq. 2.41) Power Cycle • Applying the closed system energy balance to each cycle of operation, • In words, the netenergy transfer by work from the system equals the netenergy transfer by heat to the system, each per cycle of operation.

  21. Power Cycle • The performance of a system undergoing a power cycle is evaluated on an energy basis in terms of the extent to which the energy added by heat, Qin, is converted to a net work output, Wcycle. This is represented by the ratio called the thermal efficiency.

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