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Hybridization

Hybridization. Hybridization. In Lewis theory, a covalent bond is a shared pair of electrons. This suggests that there is a region of electron density between two atoms as a result of the electron pair being shared.

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Hybridization

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  1. Hybridization

  2. Hybridization • In Lewis theory, a covalent bond is a shared pair of electrons. • This suggests that there is a region of electron density between two atoms as a result of the electron pair being shared. • Atomic orbital theory suggests that electrons exist in atomic orbitals that are regions of space surrounding the nucleus of an atom.

  3. Hybridization • Each atomic orbital can hold no more than two electrons. • How can we use atomic orbitals to explain bonding and to account for the shapes of molecules? • This leads to a model of chemical bonding called valence-bond theory.

  4. Overlapping Orbitals • In valence-bond theory, a region of electron density between atoms is explained in terms of the overlap of two atomic orbitals. • Two orbitals from different atoms, each containing an unpaired electron, can merge in the region of space between the two atoms. • The overlapping of two orbitals creates a bonding orbital between the two atoms.

  5. Overlapping Orbitals • When two p orbitals overlap in the same axis, or an s orbital and a p orbital or even two s orbitals overlap, the bond formed is called a σ (sigma) bond.

  6. Overlapping Orbitals • This overlapping orbitals explains the difference in bond length between two single bonds, such as an F-F bond and a Cl-Cl bond. • The two orbitals overlapping in the case of the F-F bond are both 2p orbitals, whereas in the case of the Cl-Cl bond, the overlapping orbitals are both 3p orbitals.

  7. Overlapping Orbitals • The 3p orbitals are larger than the 2p orbitals, so when two 3p orbitals overlap, they do so at a greater distance form the nucleus than do two 2p orbitals. • This causes the bond length in the Cl2 to be greater than in the F2.

  8. Overlapping Orbitals • Recall that the three p orbitals are at right angles to each other. • When two px orbitals are overlapping in a σ bond, the other two p orbitals, py and pz are not overlapping.

  9. Overlapping Orbitals • When two atoms come close enough together, the py and/or the pz orbitals are able to overlap in a sideways fashion. • This sideways overlapping of two orbitals is called a π (pi) bond. • In a π bond the overlapping is not as great as in a σ bond, so a π bond is not as strong as a σ bond.

  10. Overlapping Orbitals • π bonds occur most commonly when a multiple bond (a double or a triple bond) is formed. • A double bond is formed by one σ bond and one π bond. • Since a π bond is not as strong as a σ bond, a double bond is less than twice as strong as a single covalent bond between the same two elements.

  11. Overlapping Orbitals • A triple bond is formed by one σ bond and two π bonds and is less than three times as strong as a single bond.

  12. Hybrid Orbitals • Bond lengths can tell us much about the equality of covalent bonds between atoms. • When the bond lengths of the four C-H bonds in methane, CH4, are measured, they are all found to be equal. • This suggests that they are all equal in nature.

  13. Hybrid Orbitals • The electronic configuration of carbon is 1s22s22p2 and that of hydrogen is 1s1. • An orbital that overlaps with another must have only one electron in it, so that the new overlapping (bonding) orbital has no more than 2 electrons in it. • The valence configuration of carbon causes problems.

  14. Hybrid Orbitals • There are only 2 orbitals with just one electron in them. • The 2s orbital is full and the third 2p orbital has no electrons in it at all. • If the four bonds that carbon is commonly observed to make are to exist, there must be four unpaired electrons in the valence shell. • This is made possible if the atomic orbitals in the valence shell are assumed to mix together to make hybrid orbitals.

  15. Hybrid Orbitals • The shape of a hybrid orbital is different from that of the two orbitals from which it is formed, but the total number of orbitals in the valence shell remain the same.

  16. Hybrid Orbitals • Note that there is not energy change involved in forming hybrid orbitals; the is, the total energy is the same before and after hybridization has occurred. • The process of mixing atomic orbitals as atoms approach each other is called hybridization.

  17. sp3 Hybridization • The case of carbon’s four equal bonds can be explained by hybridization. • The four orbitals in the valence shell of carbon, 2s, 2px, 2py and 2pz, are mixed together. • Whenever we mix a certain number of atomic orbitals, the same number of hybrid orbitals is formed. • Hence, we get four sp3 hybrid orbitals.

  18. sp3Hybridization • The shape of an sp3 hybrid orbital is not the same as either the s orbital or the p orbital. • Like p orbitals it has two lobes, but, unlike p orbitals, one lobe is much bigger than the other. • When put together, the four lobes of the sp3 orbitals take up a tetrahedral shape in space. • This shape allows the electron pairs to be as fair apart as possible.

  19. sp3 Hybridization

  20. sp3 Hybridization • The H-C-H bond angle is 109.50. • In this manner the hybridization of atomic orbitals agrees with the requirements of VSEPR theory. • Each orbital is equal in size, hence allowing the four bonds to be equal in length and strength when they overlap with eh orbital of another atom.

  21. Methane • A molecule of methane is formed when each of the four sp3 hybrid orbitals of carbon overlap in σ bonds with the s orbitals of four hydrogen atoms.

  22. sp2 Hybridization • Boron is an element that only forms three bonds. • It has three electrons in its valence shell and will form three covalent bonds with elements such as hydrogen and fluorine. • These three equal covalent bonds can be explained by the existence of hybrid orbitals. • The electron configuration of boron is 1s22s22p1. • If the 2s orbital and the two 2p orbitals are mixed, the hybrid orbitals will be called sp2 hybrid orbitals.

  23. sp2 Hybridization • The sp2 hybrid orbital will be arranged around the central atom in such a way as to minimize electrostatic repulsion. • This results in a trigonal planar arrangement.

  24. sp2 Hybridization

  25. sp2 Hybridization

  26. Ethene • Ethene, C2H4, has a C-C double bond between the two carbon atoms and there is a trigonal planar arrangement of atoms around each carbon. • Although carbon has four orbitals in the valence shell, only three of them (2s, 2px and 2py) are involved in the hybridization. • The fourth orbital, the 2pz orbital, exists at right angles to the plane of the hybrid orbitals.

  27. Ethene

  28. Ethene • The sp2 hybridized orbitals of the carbon atom in ethene form σ bonds with hydrogen 1s orbitals and with the sp2 hybridized orbital of the other carbon atom. • The atoms are sufficiently close that the 2pz orbitals of the two carbon atoms can overlap sideways forming a π bond. • The combination of the σ bond between the hybridized orbitals and the π bond between the two 2pz orbitals creates a double bond between the two carbon atoms.

  29. Ethene

  30. sp Hybridization • Beryllium has only two electrons in its valence shell. • Its electron configuration is 1s22s2. • It makes two equal-sized bonds with elements such as hydrogen and the halogens. • In order for two equal bonds to be made, the 2s and one 2p orbital must be mixed to form two sp hybrid orbitals. • This results in a linear arrangement.

  31. sp Hybridization

  32. sp Hybridization • In beryllium hydride, BeH2, the sp hybrid orbitals of beryllium form σ bonds with the 1s orbitals of hydrogen. • The H-Be-H bond angle is 180o. • The shape of these molecules is linear.

  33. Hybridization • Generally speaking, if there are four negative charge centres around the central atom, the hybridization will be sp3; if there are three negative charge centres, the hybridization will be sp2; and if there are two negative charge centres, the hybridization will be sp.

  34. Sample Problems • Both σ and π bonds involve the overlapping of orbitals. Draw a diagram to show the difference between the overlapping that constitutes a σ bond and the overlapping to make a π bond.

  35. Sample Problems • Copy and complete the following table.

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