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Angles Formed by Parallel Lines and Transversals. 21.1. Warm Up. Lesson Presentation. Lesson Quiz. Holt McDougal Geometry. Holt Geometry. 21.1. Warm Up Identify each angle pair. 1. 1 and 3 2. 3 and 6 3. 4 and 5 4. 6 and 7. corr. s. alt. int. s. alt. ext. s.
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Angles Formed by Parallel Lines and Transversals 21.1 Warm Up Lesson Presentation Lesson Quiz Holt McDougal Geometry Holt Geometry
21.1 Warm Up Identify each angle pair. 1.1 and 3 2. 3 and 6 3. 4 and 5 4. 6 and 7 corr. s alt. int. s alt. ext. s same-side int s
21.1 Objective Prove and use theorems about the angles formed by parallel lines and a transversal.
21.1 Example 1: Using the Corresponding Angles Postulate Find each angle measure. A. mECF x = 70 Corr. s Post. mECF = 70° B. mDCE 5x = 4x + 22 Corr. s Post. x = 22 Subtract 4x from both sides. mDCE = 5x = 5(22) Substitute 22 for x. = 110°
21.1 Example 2 Find mQRS. x = 118 Corr. s Post. mQRS + x = 180° *Def. of Linear Pair* Subtract x from both sides. mQRS = 180° – x = 180° – 118° Substitute 118° for x. = 62°
Helpful Hint If a transversal is perpendicular to two parallel lines, all eight angles are congruent. 21.1
21.1 Remember that postulates are statements that are accepted without proof. Since the Corresponding Angles Postulate is given as a postulate, it can be used to prove the next three theorems.
21.1 Example 3 Find each angle measure. A. mEDG mEDG = 75° Alt. Ext. s are Congruent. B. mBDG x – 30° = 75° Alt. Ext. s are congruent. x = 105 Add 30 to both sides. mBDG = 105°
21.1 Example 4 Find x and y in the diagram. By the Alternate Interior Angles Theorem, (5x + 4y)° = 55°. By the Corresponding Angles Postulate, (5x + 5y)° = 60°. 5x + 5y = 60 –(5x + 4y = 55) y = 5 Subtract the first equation from the second equation. Substitute 5 for y in 5x + 5y = 60. Simplify and solve for x. 5x + 5(5) = 60 x = 7, y = 5
21.1 Lesson Quiz State the theorem or postulate that is related to the measures of the angles in each pair. Then find the unknown angle measures. 1. m1 = 120°, m2 = (60x)° 2. m2 = (75x – 30)°, m3 = (30x + 60)° Alt. Ext. s Thm.; m2 = 120° Corr. s Post.; m2 = 120°, m3 = 120° 3. m3 = (50x + 20)°, m4= (100x – 80)° 4. m3 = (45x + 30)°, m5 = (25x + 10)° Alt. Int. s Thm.; m3 = 120°, m4 =120° Same-Side Int. s Thm.; m3 = 120°, m5 =60°
21.2 Proving Lines Parallel Warm Up Lesson Presentation Lesson Quiz Holt McDougal Geometry Holt Geometry
21.2 Warm Up State the converse of each statement. 1.If a = b, then a + c = b + c. 2. If mA + mB = 90°, then A and B are complementary. 3. If AB + BC = AC, then A, B, and C are collinear. If a + c = b + c, then a = b. If A and B are complementary, then mA + mB =90°. If A, B, and C are collinear, then AB + BC = AC.
21.2 Objective Use the angles formed by a transversal to prove two lines are parallel.
21.2 Recall that the converse of a theorem is found by exchanging the hypothesis and conclusion. The converse of a theorem is not automatically true. If it is true, it must be stated as a postulate or proved as a separate theorem.
21.2 The Converse of the Corresponding Angles Postulate is used to construct parallel lines. The Parallel Postulate guarantees that for any line ℓ, you can always construct a parallel line through a point that is not on ℓ.
21.2 Lesson Quiz: Part I Name the postulate or theorem that proves p || r. 1. 4 5 Conv. of Alt. Int. sThm. 2. 2 7 Conv. of Alt. Ext. sThm. 3. 3 7 Conv. of Corr. sPost. 4. 3 and 5 are supplementary. Conv. of Same-Side Int. sThm.
21.3 Perpendicular Lines Warm Up Lesson Presentation Lesson Quiz Holt McDougal Geometry Holt Geometry
21.3 Objective Prove and apply theorems about perpendicular lines.
21.3 Vocabulary perpendicular bisector distance from a point to a line
21.3 The perpendicular bisectorof a segment is a line perpendicular to a segment at the segment’s midpoint. The shortest segment from a point to a line is perpendicular to the line. This fact is used to define the distance from a point to a lineas the length of the perpendicular segment from the point to the line.
A. Name the shortest segment from point A to BC. AP AP is the shortest segment. + 8 + 8 21.3 Example 5: Distance From a Point to a Line B. Write and solve an inequality for x. AC > AP x – 8 > 12 Substitute x – 8 for AC and 12 for AP. Add 8 to both sides of the inequality. x > 20
HYPOTHESIS CONCLUSION 21.3
21.3 Example 6 Solve to find x and y in the diagram. x = 9, y = 4.5