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App IV. Supplements to the Theory of Symmetric Groups. Lemma IV.1: x p = p x p –1 Let { h } & { v } be horizontal & vertical permutations of Young tableaux .
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App IV. Supplements to the Theory of Symmetric Groups Lemma IV.1: xp = p x p–1 Let { h } & { v } be horizontal & vertical permutations of Young tableaux . Let s, a & e be the associated symmetrizer, anti-symmetrizer, & irreducible symmetrizer, respectively. Then the corresponding quantities for the Young tableau p are given by Proof: Let x be h, v, s, a, or e. QED Hence, only need be considered explicitly.
Lemma IV.2: • For a given tableau , { h } & { v } are each a subgroup of Sn. • The following identities hold: Proof: • { h } = Sm where m n. Ditto { v }. 2. (Rearrangement theorem)
Lemma IV.3: Given and p Sn. at least 2 numbers in one row of which appear in the same column of p. Proof of : If then Hence p can be obtained from in 2 steps: 1. which permutes numbers in same row of 2. which permutes numbers in same column of p p can't move 2 numbers in one row of to the same column of p. Negation of this completes the proof.
Proof of : Assume no 2 numbers are shared by a row of and a column of p p can be obtained from as followings: Starting from the 1st column of p. Since these numbers are in different rows of , they can be brought to the 1st column by a horizontal permutation. Repeating the procedure for the other columns of p, we get , which differs from p by a vertical permutation. i.e., Negation of this completes the proof.
Lemma IV.4: Given and p Sn. ( ~ denotes transpositions ) Proof: By Lemma IV.3, (a,b) in the same row of & the same column of p Let t be the transposition of (a,b). and Let QED
Lemma IV.5: Given and r G. Proof: where Lemma IV.4: If then QED
1. Lemma IV.6: Given 2 distinct diagrams > , 2. Proof: Let r be the permutation that brings the numbers of the 2 tableaux to the same sequential order ( 1st row left to right, then 2nd row … ) Since the diagrams are distinct, By lemma IV.3, at 1 pair of numbers that appears simultaneously in one row of p and one column of q. Let t be the transposition of these 2 numbers. By lemma IV.2,
Lemma IV.7: The linear group transformations on Vmn , spans the space K of all symmetry-preserving linear transformations. Proof: A K Obviously, A necessary & sufficient condition for { g Gm } to span K is that L = 0 where L is a linear functional by The symmetry-preserving version of L is Since A K We can assume
Let and consider where Since is arbitrary Repeating the argument gives QED