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The Empirical Gas Laws. Unit 10 Chapter 13. Boyle’s Law. Published in 1662 by Robert Boyle, it states that for a fixed amount of a gas at a fixed temperature, the pressure of the gas is inversely proportional to the volume of the gas. P ∝ V -1 Generalizing this, we get .
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The Empirical Gas Laws Unit 10 Chapter 13
Boyle’s Law • Published in 1662 by Robert Boyle, it states that for a fixed amount of a gas at a fixed temperature, the pressure of the gas is inversely proportional to the volume of the gas. • P ∝ V-1 • Generalizing this, we get
Boyle-ing your Brain • A gas occupies 17.4 liters at 0.862 atm. What is the pressure if the volume becomes 15.0 L? • P1 = 0.862 atm V1 = 17.4 L • P2 = ? V2 = 15.0 L • (0.862 atm)(17.4 L) = P2(15.0 L) • P2 = 1.000 atm
Charles’s Law • Published in 1802 by Joseph Gay-Lussac based off of work from the 1780’s by Jacques Charles, it states that for a fixed amount of a gas at a fixed pressure, the volume of the gas is directly proportional to the temperature of the gas. • V ∝ T • Generalizing this, we get (since there is a sign inversion at 0 °C, always use Kelvin)
Giving Your Brain a Charlie Horse • The temperature of a 4.00 L sample of gas is changed from 10.0 °C to 20.0 °C. What will the volume of this gas be at the new temperature? • V1 = 4.00 L T1 = 10.0°C + 273 = 283 K • V2 = ? T2 = 20.0°C + 273 = 293 K V2 = 4.14 L
Pressure/Temperature Law • Published in 1702 by Guillaume Amontons but made famous by Gay-Lussac (in the same paper from 1802), it states that for a fixed amount of a gas at a fixed volume, the pressure of the gas is directly proportional to the temperature of the gas. • P ∝ T • Generalizing this, we get (remember to always use Kelvin)
Feeling the Pressure • If a gas in a closed container is pressurized from 15.0 atm to 16.5 atm and its original temperature was 23.7 °C, what would the final temperature of the gas be? • P1 = 15.0 atm T1 = 296.7 K • P2 = 16.5 atm T2 = ? T2 = 326.4 K = 53.4°C
The Combined Gas Law • Combining Boyle’s, Charles’s, and the Pressure/Temperature Law, assuming a fixed amount of gas, we get: (Always use Kelvin!)
I’ll Have the Combo-Meal • A gas has a volume of 800.0 mL at -23.00 °C and 300.0 torr. What would the volume of the gas be if it were heated to 289.5 °C and the pressure doubled? • P1 = 300.0 torr V1 = 800.0 mL T1 = 250.00 K • P2 = 600.0 torr V2 = ? T2 = 562.5 K V2 = 900.0mL
Avogadro’s Law • Published in 1811 by Amedeo Avogadro, it states that for a gas with a fixed pressure and temperature, the volume of the gas is directly proportional to the number of particles of the gas – we now use moles. • V ∝ n • Generalizing this, we get
Attack of the Mole • A container with a volume of 18.7 L contains 0.379 mol nitrogen. • How many moles of fluorine must be added to increase the volume to 43.4 L? • V1 = 18.7 L n1 = 0.379 mol N2 • V2 = 43.4 L n2 = ? n2 = 0.880 mol nF2 = 0.880 – 0.379 = 0.501 mol F2
Ideal Gas Law (pt 1) • Published in 1834 by Émile Clapeyron based off of Boyle’s Law and Charles’s Law, it states that for an ideal gas, the pressure-volume product is directly proportional to the mole-temperature product. • PV ∝ nT
Ideal Gas Law (pt 2) • The proportionality constant is the same for all gases! • It is called the Ideal (or Universal) Gas Constant with symbol R. • Adding R, we get
What’s the Pirate Movie Rated? • R has many possible values. • The 3 most common ones: • If P is in atm, R = 0.08205746 atm·L / mol·K • in kPa, R = 8.314472 kPa·L / mol·K • in mmHg, R = 62.36367 mmHg·L / mol·K (same for torr)
An Ideal Test • What volume will 1.15 moles of H2 occupy at 20.0ºC and 801.8 mmHg? • P = 801.8 mmHg V = ? • n = 1.15 mol T = 293.0 K P V = n R T • (801.8)V = (1.15)(62.36)(293.0) • V = 26.20628835 = 26.2 L
Universally Yours • At what temperature will 10.967 g of oxygen occupy 0.683 L at 1,266.4 kPa? • P = 1,266.4 kPa V = 0.683 L • n = ? T = ? • n = 10.967 g O2 / 32.00 g/mol = 0.3427 mol O2 • P V = n R T • (1,266.4)(0.683) = (0.3427)(8.314)T • T = 303.5760326 = 303.6 K T = 30.6°C
Ideal Gases Ideal gases are assumed to consist of: • 1. Randomly moving point particles (no size/volume) that are • 2. Infinitely compressible and • 3. Have no intermolecular attractions (i.e. will not stick to other atoms/molecules)
But Seriously, Folks There is no such thing as an ideal gas! • 1. Real gases are not point particles. • They have a volume • And they are usually at least two atoms bonded together • (except the noble gases)
Deviation from Ideal • 2. Real gases are not infinitely compressible and • 3. Individual molecules show at least a small amount of attraction to other molecules • This is how we are able to liquefy & solidify gases.
Approaching the Ideal • Gases exhibit ideal behavior at low pressures and high temperatures (big volumes). • The closest thing to an ideal gas is helium.