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Pumping Plants. Types of Pumps. Positive displacement pumps Rotary (gear, screw, etc.) Reciprocating (piston, diaphragm, etc.) Used as injection and sprayer pumps, but not for irrigation water Centrifugal pumps
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Types of Pumps • Positive displacement pumps • Rotary (gear, screw, etc.) • Reciprocating (piston, diaphragm, etc.) • Used as injection and sprayer pumps, but not for irrigation water • Centrifugal pumps • Rotating impeller converts mechanical energy into hydraulic energy (show examples and transparency)
Rotating Impeller Converts Mechanical Energy to Hydraulic Energy
Centrifugal Pump Impellers Enclosed Impeller Semi-Open Impeller
Centrifugal Pumps • Horizontal • Drive shaft is horizontal • Often used when pumping from a surface source (pond, lake, stream, etc.), Or for boosting the pressure in an irrigation pipeline (booster pump) • Usually sold as completely assembled units
Centrifugal Pumps, Contd... • Vertical Turbine • drive shaft is vertical • used when pumping from a well • normally custom built from components (with multiple stages) • submersible: electric motor below the lowest stage
Single-Stage Vertical Turbine Pump Water Flow Path Through a One-Stage Vertical Turbine Pump
Two-Stage Vertical Turbine Pump Water Flow Path Through a Two-Stage Vertical Turbine Pump
(Discharge Heads) Gearhead for engine drive Holloshaft electric motor
Submersible Water Pumps • Same as vertical turbine pump design • Driven from below by electric motor • Good for deep wells • High efficiency • Wells as small as 4” diameter
Pump Characteristics • Head vs. discharge • discharge (or capacity): volume of water pumped per unit of time (gpm) • head (or total head or total dynamic head): • energy added to the water by the pump • units of feet (energy per unit weight of water
Pump Characteristics Cont’d… • Pump Efficiency vs. Discharge Power = energy/time; 1 HP = 33,000 ft-lb/min • Q in gpm; TDH in ft, whp in horsepower - whp = power added to the water by the pump
Pump Characteristics Contd… • Brake horsepower vs. Discharge where: Q, (gpm); TDH, (ft); bhp & whp, (HP) • Combined characteristic curves • Horizontal centrifugal pump • Vertical turbine pump
Affinity Laws • Speed • Law applies to virtually all irrigation pumps • Ep may be affected a little, but not as predictable • Ways of changing speeds: pulleys, gear ratios, throttle, change motor
Affinity Law Example A pump operating at 1800 RPM delivers 200 gpm at a TDH of 150 feet and requires 10 HP to operate. What will be its Q, TDH and BHP conditions if it is sped up to 2000 RPM? RPM1=1800 RPM2= 2000 RPM2/RPM1=1.11 Q2/Q1= RPM2/RPM1 Q2= Q1 x RPM2/RPM1 = 200 x 1.11= 222 gpm TDH2/TDH1=[RPM2/RPM1]2 TDH2= TDH1 x [RPM2/RPM1]2 TDH2 = 150 x [1.11]2 = 185 feet BHP2/BHP1 = =[RPM2/RPM1]3 BHP2= BHP1 x [RPM2/RPM1]3 BHP2= 10x [1.11]3 = 13.7 HP
Affinity Laws Contd… • Impeller diameter • Law strictly applies only to horizontal centrifugal pumps, but good approximation for vertical turbine pumps • Ep may change a little • Diameter is changed by trimming the impeller (law holds up to about 10-20% trim)
Pumps in Series • Booster pump • Multi-stage turbine pump • Q1 = Q2 • TDHtot = TDH1 + TDH2 (add heads at the same discharge) • bhptot = bhp1 + bhp2
Pumps in Parallel Contd… • Qtot = Q1 + Q2 (add discharges at the same head) • bhptot = bhp1 + bhp2
Pump Selection • System Head • Definition: • Total head imposed on a pump by the irrigation system also called TDH (Total Dynamic Head), total pumping head, etc. • Components • Static Head (Elevation Head): elevation difference between water level on the inlet side and the water delivery point
Components Cont’d… • Pressure Head: difference in water pressures between the source and the delivery point • Friction Head: total friction loss between the source and the delivery point • Velocity Head: V2/(2g) (usually considered negligible) • System Head = Static + Pressure + Friction (units of feet)
Components of Total System Head (or Total Dynamic Head, Total Pumping Head)
System Head Curve • H increases with increasing Q because of: • drawdown (wells) • friction • pressure at nozzles • System head can also vary with time: • water table fluctuations • changes in the irrigation system • pipe aging
Pump Operating Point • As indicated by its TDH-Q curve, a pump can operate at many possible points • A pump will operate at a Q and TDH determined by the point where the pump curve and the system head curve cross • The same pump is likely to operate at two different TDH-Q combinations when placed in two different irrigation systems
Matching a Pump to the System • General • buyer specifies desired Q and TDH (usually not the entire system head curve) • supplier specifies operating characteristics (including pump curves) • obviously want a high Ep • can fine tune a match by adjusting speed and/or trimming the impeller
Matching a Pump to the System Contd… • Horizontal Centrifugal Pumps • provide correct Q and TDH at a high Ep • usually buy off-the-shelf unit • Vertical Turbine Pumps • choose a bowl and impeller to provide the desired Q at a high Ep • determine the number of bowls required to provide the desired TDH (pumps in series)
A vertical turbine pump is needed to deliver 400 gpm from a well that will have a static pumping lift of 237 feet, plus an operating pressure of 55 psi at the pump head. Is the WLR 10JKH pump below a good choice? If so, how many stages are required? TDH= 237+(55psi*2.31 ft/psi)=364 ft @ Q=400 gpm: TDH=52 ft/stage for 7.7” & Ep=79.5% TDH=41 ft/stage for 7.13” & Ep=77.5% TDH=30 ft/stage for 6.56” & Ep=72% 364 ft/52 ft/stage=7 stages The best choice is the 7.7” diameter impeller at 52 ft/stage, because it not only requires the fewest stages (low initial cost), but has the best efficiency (low operating cost) near 80%.
A vertical turbine pump is needed to deliver 400 gpm from a well that will have a static pumping lift of 237 feet, plus an operating pressure of 60 psi at the pump head. Is the WLR 10JKH pump below a good choice? If so, how many stages are required? TDH= 237+(55psi*2.31 ft/psi)=364 ft @ Q=400 gpm: TDH=52 ft/stage for 7.7” & Ep=79.5% TDH=41 ft/stage for 7.13” & Ep=77.5% TDH=30 ft/stage for 6.56” & Ep=72% 364 ft/52 ft/stage=7 stages The best choice is the 7.7” diameter impeller at 52 ft/stage, because it not only requires the fewest stages (low initial cost), but has the best efficiency (low operating cost) near 80%.
Net Positive Suction Head • Suction lift and cavitation • Handout • Pump does not "suck" or "pull" water • Impeller causes partial vacuum • Atmospheric pressure forces water up to the impeller • Theoretical vs. practical lift • Describe cavitation
NPSHa • NPSHa = AP - SL - FL - VP • AP = atmospheric pressure • SL = suction lift (vertical distance) • FL = friction loss on suction side • VP = vapor pressure • all have units of feet
NPSHr • NPSHr is a pump characteristic (increases as Q increases) • If NPSHa > NPSHr: Design is OK • If NPSHa < NPSHr: Cavitation will be a problem (good idea to have a factor of safety)
Power Units • Electric motors • direct coupled • High Efficiency drive (Edrive=100%), but Fixed Speed • belt drive • Variable Speed, but Lower Efficiency drive (Edrive= 90%) • rated by output HP • Em's 90% are common • Em doesn't vary much with load (unless it's significantly under-loaded)
Internal Combustion Engines • Fuels • Natural gas • Diesel fuel • Propane • Gasoline • Right-angle Gear Drives • Convert power in horizontal engine shaft to power in vertical pump line shaft • Edrive 95% (5% loss through the gear drive)
Internal Combustion Engines Contd… • Ee varies with engine speed and with the load on the engine • Ee's rarely exceed 30%
Pumping Costs Fixed Costs vs. Operating Costs • Fixed: pump, motor/engine, well, other equipment (total cost is the same regardless of use) • Operating: energy, maintenance, repairs, labor (total cost increases with increasing use)
Overall Pumping Plant Performance Overall pumping plant efficiency, (Eo): Electric Motor Driven • Eo = Ep x Em x Edrive Internal Combustion Engine Driven • Eo = Ep x Ee x Edrive Efficiencies are expressed in decimal for this calculation, (%/100)