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Entry Task: March 8 th Friday

Entry Task: March 8 th Friday. Entry task question: 2AgCl + Mg  MgCl 2 + 2Ag Question: How many grams of silver can be produced if 150 grams of magnesium reacts with excess AgCl ? You have ~10 minutes. Agenda:. TURN IN ALL STOICH LAB!!- NOW!!! OR it will be considered LATE!!

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Entry Task: March 8 th Friday

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  1. Entry Task: March 8thFriday Entry task question: 2AgCl + Mg  MgCl2 + 2Ag Question: How many grams of silver can be produced if 150 grams of magnesium reacts with excess AgCl? You have ~10 minutes

  2. Agenda: • TURN IN ALL STOICH LAB!!- NOW!!! • OR it will be considered LATE!! • Break out periodic tables and calculators

  3. Stoichiometry – gram-gram • Clear off Desks! • QUIETLY work through the first problem. • After ~10-15 minutes we will check answers • If you get done sooner- move on 

  4. Iron III sulfate reacts with potassium hydroxide to create potassium sulfate and iron III hydroxide ___Fe2(SO4)3 + ___KOH  ___K2SO4 + ___Fe(OH)3 6 3 2

  5. ___Fe2(SO4)3 + ___KOH  ___K2SO4 + ___Fe(OH)3 6 3 2 a. How many grams of potassium hydroxide were used to create 50.9 grams of iron III hydroxide? 50.9 grams Fe(OH)3 1 mole of Fe(OH)3 6 mole of KOH 56.10 g of KOH g of KOH 2 mole of Fe(OH)3 106.9 g of Fe(OH)3 1 mole of KOH 50.9 X 6 X 56.10 17132.9 80.1 g of KOH 106.9 X 2 213.8

  6. ___Fe2(SO4)3 + ___KOH  ___K2SO4 + ___Fe(OH)3 6 3 2 b. How many grams of iron III sulfate were used to create 155 grams of potassium sulfate? 155 grams K2SO4 1 mole of K2SO4 1 mole of Fe2(SO4)3 399.873 g of Fe2(SO4)3 g of Fe2(SO4)3 3 mole of K2SO4 174.3 g of K2SO4 1 mole of Fe2(SO4)3 155 X 1 X 399.873 61980.3 119 g of Fe2(SO4)3 174.3 X 3 522.9

  7. ___Fe2(SO4)3 + ___KOH  ___K2SO4 + ___Fe(OH)3 6 3 2 c. How many grams of potassium sulfate were produced if 35.0 grams of potassium hydroxide were used? 35.0 grams KOH 1 mole of KOH 3 mole of K2SO4 174.3 g of K2SO4 g of K2SO4 6 mole of KOH 56.10 g of KOH 1 mole of K2SO4 35.0 X 3 X 174.3 18301.5 54.4 g of K2SO4 56.10 X 6 336.6

  8. ___Fe2(SO4)3 + ___KOH  ___K2SO4 + ___Fe(OH)3 6 3 2 d. How many grams of iron III hydroxide were produced if 25.0 grams iron III sulfate were used? 25.0 grams Fe2(SO4)3 1 mole of Fe2(SO4)3 2 mole of Fe(OH)3 106.9 g of Fe(OH)3 g of Fe(OH)3 1 mole of Fe2(SO4)3 399.87 g of Fe2(SO4)3 1 mole of Fe(OH)3 25.0 X 2 X 106.9 534.5 13.4 g of Fe(OH)3 399.87 399.87

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