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Mrs. Rivas

Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Then substitute to answer the question. Mrs. Rivas. X = 3. = 4 (3) – 1. = 11. m ∠ AOB = 4 x – 1. m ∠ BOC = 2 x + 15. = 2 (3) + 15. = 21. 2x + 15. m ∠ AOC = 8 x + 8. = 8 (3) + 8. = 32.

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Mrs. Rivas

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  1. Mrs. Rivas

  2. Mrs. Rivas

  3. Mrs. Rivas

  4. Mrs. Rivas

  5. Mrs. Rivas

  6. Mrs. Rivas

  7. Mrs. Rivas Then substitute to answer the question.

  8. Mrs. Rivas X = 3 = 4(3) – 1 = 11 m∠AOB = 4x – 1 m∠BOC = 2x + 15 = 2(3) + 15 = 21 2x + 15 m∠AOC = 8x + 8 = 8(3) + 8 =32 8x + 8 4x – 1

  9. Mrs. Rivas 3x – 10 8x + 13 Then substitute to answer the question.

  10. Mrs. Rivas X = 9 12x – 6 m∠COD = 8x + 13 = 8(9) + 13 = 85 = 3(9) – 10 = 17 m∠BOC = 3x – 10 3x – 10 8x + 13 =102 m∠BOD = 12x – 6 = 12(3) – 6

  11. Mrs. Rivas Always read the question and draw a picture. 3x + 8 = 2x + 48 – 8 – 8 3x = 2x + 40 – 2x – 2x x = 40 A E 3(40) + 8 = 128 2(40) + 48 = 128 B 3x + 8 2x + 48 F C

  12. Mrs. Rivas Always read the question and draw a picture. 2x– 3 + 5x+ 2 = 90º 2x – 3 + 5x + 2 = 90º 7x– 1 = 90º + 1 + 1 7x = 91º 5(13) + 2 = 67 J N 2x – 3 7 7 L 2(13) – 3 = 23 M x = 13º 5x + 2 K P

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  17. Mrs. Rivas Always read the question and draw a picture. If ∠JKM = 86 then ∠MKL = 86, so ∠JKL has to be equal to 86+86 = 172. J M 86 K L

  18. Mrs. Rivas Always read the question and draw a picture. Since bisectmeans cut in half. Then, m∠RSV = 62 ÷ 2 = 31 62 R V S T

  19. Mrs. Rivas Always read the question and draw a picture. 3x= 5x – 20 – 5x – 5x – 2x= – 20 P 5x – 20 S 2 2 3x x= 10 Q 3(10) = 30 5(10) – 20 = 30 R So, m∠PQR= 30 + 30 = 60

  20. Mrs. Rivas Always read the question and draw a picture. 2x + 1 = 4x – 15 – 1 – 1 2x= 4x – 16 P – 4x – 4x 4x – 15 S 2x + 1 – 2x= – 16 Q 4(8) – 15 = 17 2(8) + 1 = 17 2 2 R So, m∠PQR= 17 + 17 = 34 x= 8

  21. Mrs. Rivas Always read the question and draw a picture. 30 + 30 = 3x – 12 60 = 3x – 12 + 12 + 12 30 P S 72 = 3x 3x –12 3 3 Q 3(24) – 12 = 60 R x= 24

  22. Mrs. Rivas Always read the question and draw a picture. 2x + 10 = 5x – 17 – 10 – 10 2x= 5x – 27 P – 5x – 5x 5x – 17 S 2x + 10 – 3x= – 27 Q 3 3 5(9) – 17 = 28 2(9) + 10 = 28 R x= 9 So, m∠PQR= 28 + 28 = 56

  23. Mrs. Rivas Always read the question and draw a picture. b). a). m∠MLN = 7(8) – 1 = 55 7x– 1 + 4x+ 3 = 90º 11x+ 2 = 90º m∠JKL = 4(8) + 3 = 35 – 2 – 2 c). I can check the answer by adding 55 and 35, and it should be 90º. 55 + 35 = 90º 11x= 88º 11 11 x= 8

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