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How Tall Is IT?

How Tall Is IT? . Bekah Sean Griffen Kohta 5 th period . 60 Degrease Bekah. Long leg= square root of 3 x short leg X = square root of 3 x 14 feet X= 14 x square root of 3/ 3 X= 24.25 feet. Tan x= Opposite/adjacent Tan 60= x feet / 14 feet 14(tan 60)= X 24.249 feet+ 14 feet

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How Tall Is IT?

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  1. How Tall Is IT? Bekah Sean Griffen Kohta 5th period

  2. 60 DegreaseBekah Long leg= square root of 3 x short leg X = square root of 3 x 14 feet X= 14 x square root of 3/ 3 X= 24.25 feet • Tan x= Opposite/adjacent Tan 60= x feet / 14 feet 14(tan 60)= X 24.249 feet+ 14 feet 5.125 feet+ 24.249 feet = 29.374 feet 60 degrees 5 feet 14 feet

  3. 45 Degrees Kohta 60 inches (eye height) 28 feet base Tan x = opposite adjacent Tan (45)= x feet 28 feet 28 (tan 45)= x 28 feet = x 28 feet + 60 inches 28 feet + 5 feet = 33 feet 45-45-90 Side=Side 28=28 Side+Height=Pole Height 28+5=33feet 5 Feet 28 feet

  4. Tan x = opposite / adjacent Tan30 = x / 38ft 38(Tan30) = x X ≈21.94 + 5.75 X≈27.69 ft 30 Degrees Sean Long leg =√3 ×short leg 38 = √3 × s. leg s. Leg = 38√3 / 3 s. Leg ≈ 21.94 + 5.75 X ≈ 27.69 ft. X 30 degrees 38 ft 5.75

  5. Tan x ≈ opposite Adjacent Tan (24) ≈ X Feet 67 Feet 67 [Tan (24)] ≈ X Feet X ≈ 29.83 Feet 29.83 Feet + 5.75 Feet ≈ 35.58 Feet 24 DegreesGriffin 5.75Feet 24 Degrees 67 Feet

  6. So………What Did We Learn Again? • We noted that as the measure of the angle increased, the closer we got to the object. This made the angle sharper, and obviously decreased the distance from us to the light pole. • The height of the light pole stayed the same • We also noted that our light pole was crooked, so the measurements were most likely inaccurate. Also, one can not get an accurate measurement by simply taking steps.

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