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Calculate the volume of gas released at 227 o C under 83.1 kPa pressure when 16 kg of NH 4 NO 3 is exploded forming N 2 , O 2 , & H 2 O:. Drill: Calculate mole fraction of:. A solution containing 331 g Pb(NO 3 ) 2 in 1782 mL water. Thermo-chemistry. Chm II. Chapter 15. Thermochemistry.
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Calculate the volume of gas released at 227oC under 83.1 kPa pressure when 16 kg of NH4NO3 is exploded forming N2, O2, & H2O:
Drill: Calculate mole fraction of: A solution containing 331 g Pb(NO3)2 in 1782 mL water.
Chm II Chapter 15
Thermochemistry • The study of heat transfer in chemical reactions
Thermochemistry • Heat change • Calorimetry • TCE
System • That part of nature upon which attention is focused
Surroundings • That part of nature around the part upon which we are focused
Reaction Coordinate • A graph of energy change versus time in a chemical reaction
P Energy R Time
Exothermic Rxn • Chemical reactions that release, give off heat, or lose heat
Endothermic Rxn • Chemical reactions that absorb, take in heat, or gain heat
Specific Heat • The heat required to raise one gram of a substance 1oC • C: (J/goC, J/kgoK)
Sp. Heat DH = mCDT
Heat of Fusion • The heat required to melt one gram of a substance at its normal MP • Hf: (J/g or J/kg)
Heat of Fusion DH = mHf
Heat of Vaporization • The heat required to boil one gram of a substance at its normal BP • Hv: (J/g or J/kg)
Heat of Vap. DH = mHv
Calculate the heat change when 10.0 g H2O goes from –100.0oC to 200oC.MP = 0oC BP = 100oCHf = 334 J/g HV = 2260 J/g Cice = 2.06 J/gC Cwater = 4.18 J/gC Csteam = 2.02 J/gC
Drill: Calculate the heat required to change 25 g of water from 140.0oC to 60.0oC MP = 0oC BP = 100oCHf = 334 J/g HV = 2260 J/g Cice = 2.06 J/gC Cwater = 4.18 J/gC Csteam = 2.02 J/gC
Calorimetry • Experimental measure of heat transfer
Calorimeter • Device used to measure heat transfer • A calorimeter is an adiabatic system • Experimental yield
Adiabatic System • A system that exchanges zero heat with its surroundings DHsystem = 0
DH (J) DH = q = the heat or enthalpy change in a system DHsys = mCDTsysparts
Calorimetry DHsystem = 0 DHsys = DHcal + DHrxn DHrxn = -DHcal DHrxn = -mCDTcal
When Q reacts in a 1.5 kg calorimeter containing 2.5 kg water ch. from 22.5oC to 26.5oC. Calculate DHrxn. Cwater = 4.18 J/gK Ccal = 2.00 J/gK
When X reacts in a 2.0 kg calorimeter containing 1.5 kg water went from 22.5oC to 30.5oC. Calculate DHrxn. Cwater = 4.18 J/gK Ccal = 1.50 J/gK
When Z reacts in a 1.0 kg calorimeter containing 2.0 kg water went from 22.5oC to 32.5oC. Calculate DHrxn. Cwater = 4.18 J/gK Ccal = 2.00 J/gK
Drill: When 40.0 g NH4NO3 dissolves in 460.0 g water at 25.0oC, the temp. falls to 22.5.oC. Calculate the DHosoln for NH4NO3. Csoln = 4.00 J/gK
Heat (H) • A form of energy that can flow between samples of matter
Enthalpy • Heat that can flow in/out of a system DH
Typical Reaction • HCl + NaOH NaCl + HOH
Heat of Reaction • The heat or enthalpy change of a chemical reaction DHrxn
Typical Ionization HCl H+(aq) + Cl-(aq)
Heat of Solution • The heat or enthalpy change when a substance is dissolved DHsoln
Combustion Reaction • CxHy + O2 • CO2 + HOH
Heat of Combustion • The heat or enthalpy change when a substance is burned DHcombustion
Rxn Making Compounds from elements H2 + ½ O2 H2O
Heat of Formation • The heat required to form one mole of a compound from pure elements DHfo (kJ/mole)
The Degree Symbol • Indicates standard conditions & molar quantities by itself or from a balanced equation.
Gibb’s Free Energy • Energy of a system that can be converted to work • Determines spontaneity DG
Energy of Formation • The energy required to form one mole of a compound from pure elements DGfo (kJ/mole)
Exergonic Reaction • A reaction in which free energy is given off DG< 0
Endergonic Reaction • A reaction in which free energy is absorbed DG> 0
Exergonic Reaction • A reaction which can be spontaneous DG< 0
Endergonic Reaction • A reaction which cannot be spontaneous DG> 0
Reaction at Equilibrium DG= 0