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The Mole

The Mole. Q: how long would it take to spend a mole of $1 coins if they were being spent at a rate of 1 billion per second?. Mollionaire. Q: how long would it take to spend a mole of $1 coins if they were being spent at a rate of 1 billion per second? A: $ 6.02 x 10 23 / $1 000 000 000

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The Mole

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  1. The Mole Q: how long would it take to spend a mole of $1 coins if they were being spent at a rate of 1 billion per second?

  2. Mollionaire Q: how long would it take to spend a mole of $1 coins if they were being spent at a rate of 1 billion per second? A: $ 6.02 x 1023 / $1 000 000 000 = 6.02 x 1014 payments = 6.02 x 1014 seconds 6.02 x 1014 seconds / 60 = 1.003 x 1013 minutes 1.003 x 1013 minutes / 60 = 1.672 x 1011 hours 1.672 x 1011 hours / 24 = 6.968 x 109 days 6.968 x 109 days / 365.25 = 1.908 x 107 years A: It would take 19 million years

  3. The Mole • Atomic Masses give information about # of p+, n0, e– 2. It is useful to associate atomic mass with a mass in grams. 3. It has been found that 1gH,12gC,or 23gNahave6.02x1023atoms 4. 6.02 x 1023 is a “mole” or “Avogadro’s number”

  4. Comparing cobalt & sulfur Co S Mass 58.93 g 32.07 g # of moles? 1 mole of cobalt 1 mole of sulfur • # of atoms? 6.02x1023 6.02x1023

  5. Molar mass • The mass of one mole is called “molar mass” • For ex. 1 mol Lithium = 6.94 g Lithium • This is expressed as 6.94 g/mol • 1 mol Titanium = 47.87 g/mol

  6. Element g/mol g mol Iron 0.25 mol Bromine 53 g Calcium 3.50 mol Arsenic 15 g Converting between grams and moles • In order to convert from one to the other you must first determine the molar mass (g/mol) 55.85 13.96 g 79.90 0.66 mol 40.08 140.3 g 74.92 0.200 mol

  7. Element atoms mol Iron 0.25 mol 3.97 x 1023 atoms Bromine Calcium 3.50 mol Arsenic 1.2 x 1023 atoms Atoms? As Avogadro determined… 1 mole = 6.02 x 1023 atoms 1.5 x 1023 atoms 0.66 mol 2.1 x 1024 atoms 0.200 mol

  8. g mol g/mol Element g/mol g mol Iron 0.25 mol Bromine 53 g Calcium 3.50 mol Arsenic 15 g Converting between grams and moles • In order to convert from one to the other you must first determine the molar mass (g/mol) • Thiscanberepresentedinan“equationtriangle” 55.85 13.96 g 79.90 0.66 mol 40.08 140.3 g 74.92 0.200 mol

  9. Molar mass • The mass of one mole is called “molar mass” • E.g. 1 mol Li = 6.94 g Li • This is expressed as 6.94 g/mol • What are the following molar masses? S SO2 Cu3(BO3)2 32.06 g/mol 64.06 g/mol 308.27 g/mol Calculate molar masses (to 2 decimal places) CaCl2 (NH4)2CO3 O2 Pb3(PO4)2 C6H12O6 Cu x 3 = 63.55 x 3 = 190.65 B x 2 = 10.81 x 2 = 21.62 O x 6 = 16.00 x 6 = 96.00 308.27

  10. Molar mass • The mass of one mole is called “molar mass” • E.g. 1 mol Li = 6.94 g Li • This is expressed as 6.94 g/mol • What are the following molar masses? S SO2 Cu3(BO3)2 32.06 g/mol 64.06 g/mol 308.27 g/mol Calculate molar masses (to 2 decimal places) CaCl2 (NH4)2CO3 O2 Pb3(PO4)2 C6H12O6 110.98 g/mol (Cax1, Clx2) 96.11g/mol(Nx2, Hx8, Cx1, Ox3) 32.00 g/mol (Ox2) 811.54 g/mol (Pbx3, Px2, Ox8) 180.18 g/mol (Cx6, Hx12, Ox6)

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