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ENERGY EVALUATION OF FEEDS. I. Monogastric Animals István HULLÁR associate professor (2010.)

ENERGY EVALUATION OF FEEDS. I. Monogastric Animals István HULLÁR associate professor (2010.). Aim: to express the energy requirement of animals and the energy content of their feeds by the same unit. FLOW DIAGRAM OF ENERGY TERMS. GE (Gross Energy)  - Faecal Energy loss

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ENERGY EVALUATION OF FEEDS. I. Monogastric Animals István HULLÁR associate professor (2010.)

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  1. ENERGY EVALUATION OF FEEDS. I. Monogastric Animals István HULLÁR associate professor (2010.) Aim: to express the energy requirement of animals and the energy content of their feeds by the same unit.

  2. FLOW DIAGRAM OF ENERGY TERMS GE (Gross Energy)  - Faecal Energy loss DE (Digestible Energy) - Urinary and Gaseous Energy loss ME (Metabolizable Energy)     - Heat increment NEm NEl NEg (Net Energy) (m: maintenance; l: lactation; g: gain).

  3. Unit of Measure 1. Earlyer: calorie (cal); 2. System International (SI): Joule (J); 3. 1 cal = 4.184 J; 4. 1000 J = 1 kJ; 5. 1000 kJ = 1 MJ; 6. Energy content of feeds: kJ/g or MJ/kg; 7. 1 kJ/g = 1 MJ/kg.

  4. GE  - Faecal Energy DE (MJ/kg) Pig, Horse, Rabbit DIGESTIBLE ENERGY (DE)

  5. DE content of feeds I. Calculation according to the experimental data (Fi*GEF) – (FA*GEFa) DE (kJ/g) =  whereFi Fi= Feed intake (g, DM); GEF= Gross Energy content of Feed (kJ/g, DM); FA = Faeces output (g, DM); GEFa = GE content of Faeces (kJ/g, DM).

  6. DE content of feeds Fi= 6000 g, DM; GEF= 18 kJ/g, DM; FA = 2500 g, DM; GEFa = 7.32 kJ/g, DM; (6000*18) – (2500*7.32) DE (kJ/g) =  = 6000 108000 – 18300 DE (kJ/g) =  = 6000 = 14.95 kJ/g.

  7. DE content of feeds II. Prediction according to the digestible nutrients (Equation of Rostock) DEpig (MJ/kg) = 0.0242*DCP + 0.0394*DEE + 0.0194*DCF + 0.0170*DNFE where DCP = Digestible Crude Protein (g/kg); DEE = Digestible Ether Extract (g/kg); DCF = Digestible Crude Fibre (g/kg); DNFE = Digestible N-free Extract (g/kg).

  8. DE content of feeds E.g. Prediction of the DE content of extracted soybean meal (MJ/kg) DEpig (MJ/kg) = 0.0242*DCP + 0.0394*DEE + 0.0194*DCF + 0.0170*DNFE  Nutrients g/kg Dig. Coeff. Dig. Nutr. g/kg Factors DE MJ/kg  CPEECFNFE 480 10 35288 *0.92*0.40*0.65*0.97 =441.6= 4.0= 22.1= 279.4 *0.0242*0.0394*0.0194*0.0170 = 10.687 = 0.158= 0.429= 4.750  16.024

  9. GE  - Faecal Energy loss DE  - Urinary and Gaseous Energy loss ME (MJ/kg) Poultry: AMEn (Apparent Metabolizable Energy corrected to zero N retention.) ME content of feeds

  10. Calculation of the AME content of feeds (Fi*GEF) – (E*GEE) AME (kJ/g) =  whereFi Fi= Feed intake (g, DM); GEF= Gross Energy content of Feed (kJ/g, DM); E = Excreta output (g, DM); GEE = GE content of Excreta (kJ/g, DM).

  11. Adult Bird: N intake = N output  zeroN retention. Growing Bird: N intake > N output  positive N balance (uric acid: 34.4 kJ/g N). Calculation of the AME content of feeds

  12. Calculation of the AME content of feeds Adult Bird (N balance = 0) 1000 KJ – 200 KJ 800 kJ AME (kJ/g) =  =  = 11,43 kJ/g 70 g 70 g Growing Bird (N balance = + 1 g): -34,4 kJ 1000 KJ – 165,6 KJ 834,4 kJ AME (kJ/g) =  =  = 11,92 kJ/g. 70 g 70 g

  13. Calculation of the AMEn content of feeds Adult Bird (N balance = 0) 1000 KJ – 200 KJ 800 kJ AME (kJ/g) =  =  = 11,43 kJ/g 70 g 70 g Growing Bird (N balance = + 1 g): -34,4 kJ 1000 KJ – 165,6 KJ – 34,4 kJ AMEn (kJ/g) =  = 70 g 1000 KJ – 200 KJ 800 kJ AMEn (kJ/g) =  =  = 11,43 kJ/g. 70 g 70 g

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