a. Ln[A]= -Kt +Ln[A] o Ln[61.5]= -K(480) + Ln[100] Ln[.615]= -K(480) K=0.00101
#39 A first-order reaction is 38.5% complete in 480. s. a. Calculate the rate constant. b. What is the value of the half-life? c. How long will it take for the reaction to go to 25%, 75%, and 95% completion?. a. Ln[A]= -Kt +Ln[A] o Ln[61.5]= -K(480) + Ln[100] Ln[.615]= -K(480) K=0.00101.
432 views • 4 slides